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QUESTION:
Is that true that a single atom can be in two places at once?
If it's true, why?
ANSWER:
That depends by what you mean by "being in a place". Atoms must be
described quantum mechanically where we talk about probability of being
rather than being. An atom may have a probability of
½ of being in one volume and a probability of ½ of being in a different
volume. In a practical sense, this means if you had a whole bunch of
identical such atoms, half the time you observed one of them it would
"be" in one place and half the time it would "be" in the other. Once you
observe where it "is", it is no longer in two places.
QUESTION:
is it possible for the internal energy of a system to be larger than the kentic energy of the molecules and the atoms making up the system?
ANSWER:
The internal energy is the sum of kinetic and potential energies. So,
the internal energy certainly can be greater than the kinetic energy.
This is not an issue for an ideal gas, but certainly is for a solid.
QUESTION:
If a bird is packed in a box, and it's carried by a boy, then if a bird flies inside the box only will the weight less or more or equal?
ANSWER:
This question has been previously answered.
Your question is a little different, though, since you do not specify
that the bird is hovering. If the bird accelerates upward the box+bird
will weigh more and if it accelerates down it they will weigh less. If
you want to get much deeper into this, see another
earlier answer.
QUESTION:
When you fire a gun in space (say a rifle of some sort), what will happen? If I were to fire a projectile into space, what would be the net reaction? Would the bullet and rifle travel the same distance, just in opposite directions?
ANSWER:
The principle which governs this situation is conservation of momentum.
The momentum of an object is its mass times its velocity. If a system is
isolated (like your gun+bullet in space), its total momentum never
changes. So, before you fire the gun, the momentum is zero. After you
fire, the bullet emerges with a speed Vbullet and the
gun recoils in the opposite direction with speed Vgun. If
the masses are Mbullet and Mgun, we
must have MbulletVbullet=MgunVgun
since the total MV must be zero and they move in opposite
directions. For example, a 40 gram bullet with a speed of 500 mph when
fired from a 2 kg (2000 grams) gun: the speed of the gun recoil would be
5 mph. Of course, if you are holding the gun we would add your mass to
the gun's. (Incidentally you refer to each as "travel[ing] the same
distance" which implies you think they will stop. They will never stop
but the bullet in my example will travel 100 times farther than the gun
in a given time.)
QUESTION:
what is the diffrence between following through a hit/kick/swing against a sports ball and stopping at impact
ANSWER:
Take a look at a recent answer and see if
that addresses your question.
QUESTION:
according to the law of universal gravitation, what would happen to earth if the sun were somehow replaced by a black hole of the same mass?
ANSWER:
Things would get very cold and dark! But the earth would go happily on
its way in the same orbit. To see the effects of the black hole you need
to be inside the Schwartzchild radius which, for the mass of the sun,
would be 3 km.
QUESTION:
As I can presume you would sympathize with the frustration one can feel at 'bad/inaccurate science' being used to move works of fiction along, I ask the following questions in order to avoid said pitfall.
In the latest theories regarding controlled nuclear fusion for potential power purposes, is helium-3 a potential reactant, or is it more practical as we currently understand the science to use hydrogen isotopes?
What kind of radiation hazards exist with nuclear fusion as a potential power source?
ANSWER:
You can learn a lot of what you seek in the Wikepedia article on
fusion power.
One possibility with 3He is the 3He+2H —>4He+1H.
This has the advantage that neutrons are responsible for much of the
radiation hazards in fusion and no neutrons are produced. However, since
the
2H is abundantly present in the reaction, there will also be
2H+2H—>3He+n.
A favored hydrogen-only process is
3H+2H—>4He+n,
but again here we have copious neutrons, 3H itself is
radioactive and rare.
QUESTION:
I am currently taking a physics class in high school and we where discussing nuclear physics more specifically fusion and fission. My questions is a HBomb fuses hydrogen isotopes to create helium isotopes and large amounts of energy by means of using a traditional u238 atomic bomb for initial energy,could you create a device that creates hydrogen form helium exact opposite of nuclear fussion so basically fission of helium atoms to create hydrogen isotopes and take in a large amount of energy instead of burning and vaporizing every thing it would freeze or some thing similar( I'm not quite sure if something else could or would happen) my idea of how to get such a reaction to start would be a particle accelerator like the big one in sweden and just bash helium together at near the speed of light. So I was just wondering if such a thing could theoretically be possible.
ANSWER:
Whenever you split a light nucleus you must put energy in. For example,
to cause one He4 nucleus to break into two H2
nuclei, you must add energy somehow. However, you will not be able to
get it to happen on a big enough scale to see anything get cold.
QUESTION:
Does the pound (lb) measure mass or force?
ANSWER:
In everyday life the pound is often used to represent either the weight
(force) or mass of something; similarly, in non-US countries, the
kilogram is often used to measure weight (force). In physics, a pound is
unambiguously a measure of force and a kilogram is unambiguously a
measure of mass.
QUESTION:
We know that gravitational lensing is due to light being attracted by matter, as predicted by Einstein theory of special relativity. Has it been experimentally shown that Newton's third law applies here too? I.e., has anybody detected the light - matter attreaction, in the reverse direction? It seems that Heisenberg's uncertainty princile muddles this extremely small movements. So does Newton's third law also to be modified by the uncertainty equation?
ANSWER:
The first thing I would say is that just because nobody ever measured
the recoil of the earth when I jump up into the air does not mean that
Newton's third law is not true. Secondly, I would note that Newton's
laws are not correct laws of physics in the theory of special
relativity, and if anything is relativistic it is photons (light).
Finally, Newton's third law is not always true for electromagnetism —the
forces between two moving point charges are not always in opposite
directions.
QUESTION:
What is the difference between a "principle" and a "law" i n physics?
Why do we have "Archimede's Principle" and "Newtow's Law"?
I could never understand when one uses one or the other....
ANSWER:
Philosophy of physics may have very precise definitions of terms like
these, but I think it can be ambiguous in physics. Here is my take on
it. A physical law is a statement of an experimental measurement which
is correct as accurately as you can measure it and for any condition
under which it can be experimentally observed. Newton's second law is a
very good example; it states that an object's acceleration is
proportional to the net force on it and inversely proportional to its
mass. The only way to find this out is to measure the acceleration while
you vary the force and mass. Archimedes' principle, however, does not
require that you go to a laboratory and measure the buoyant force, you
can derive it using Newtonian mechanics. Sometimes, laws are misnamed
from this perspective. Hooke's law, which states that the force a spring
exerts on an object connected to it is proportional to its stretch (or
compression) and opposite the stretch (or compression), is only
approximately true and over only a limited range of stretches.
QUESTION:
It is generally accepted in the firearms world that a longer barrel equals greater accuracy, but if repeatabilty and predictabilty are the hallmarks of accuracy then why wouldn't a short barrel be as accurate as long barrel. The short barrel has the same input or impact on the bullet shot to shot everyhing else being equal. I am not a student and hope this dose not fit into the "off the wall" catagory. I' m just and old man trying to decide on a project. It comes down to- If the imput is the same shot shot the results should be the same shot to shot, right?
ANSWER:
My brief research on the web reveals that there is considerable
controversy over whether or not this is true. It will depend on other
properties of the gun besides length, particularly the thickness of the
wall of the barrel and the material from which it is made since these
will determine the flexibility of the barrel. It appears that one
important factor is that the firing will cause the barrel to vibrate
like a reed; although this will be very small in amplitude, it may very
well be large enough to make a significant difference in accuracy
because of relatively large distances traveled by the projectile. One
experimenter actually found that reducing the barrel length to 18"
from 26" increased the accuracy of the rifle. Apparently one of
the reasons for the belief that long is better is that if you rely only
on mechanical sights on the barrel (as opposed to, say, a telescopic
sight), it is the distance between the notch and the post which is
responsible for the improved accuracy, not necessarily the effect of a
long barrel on the projectile.
QUESTION:
This question pertains to the penetration potential of two arrows having :
-The same outside shaft diameter
- different weights
- traveling at different velocities
- impacting into an identical target material.
In effect, the arrows are identical in every regard with the exceptions noted as follows:
Arrow "A" weighs 350 grains and leaves the bow at 212 feet/second;
Arrow "B" weighs 650 grains and leaves the bow at 170 feet/second
The arrows each travel 20 yards before impacting an identical target material.
My question is, which arrow would penetrate deeper into the target;
-The lighter (350 grain), faster travelling (212 feet/sec) arrow; or -The heavier (650 grain), slower travelling (170 feet/sec) arrow.
In this "experiment" everything is the same except the weight and speed of the two arrows.
ANSWER:
I will make the following assumption: the forces on the two arrows are
identical and constant as they stop. This may not be a good
approximation since the forces are likely to be velocity dependent;
still, it seems reasonable to me since the frictional force stopping the
arrow is more like sliding friction (not velocity dependent) than air
friction (velocity dependent).
I have also assumed that the mass of the target is much larger than the
the mass of the arrows. I will ignore the loss of speed due to air drag
over that first 20 yd.
Now, use Newton's second law in the form P/F=T
where P is the magnitude of the change in momentum (mass times
velocity), T is the time to stop, and F is the force the
target exerts on the arrows. So the time to stop the heavier is TB=650x170/F=1.11x105/F
and the time to stop the lighter one is TA=350x212/F=7.42x104/F.
So, the time for the heavier arrow to stop is larger by a factor of TB/TA=1.5.
Also, since the forces are equal, the accelerations will be in the
inverse proportion to their masses, aA/aB=650/350=1.86,
so the acceleration of the lighter arrow is of greater magnitude by
about 86% (though both are negative since both are slowing down).
Knowing the relative times and accelerations, it is straightforward to
compute the relative distances using x=vT- ½aT2.
I find xB/xA=1.17—the heavier arrow
will go about 17% deeper than the lighter one. I would say that, given
the approximations made, there is not really a significant difference.
QUESTION:
Why does gravity affect on the water when it is solid or liquid and does not affect it in its gaseous ?
ANSWER:
If gravity did not affect water vapor, it would escape into space. The
reason the earth has an atmosphere is because it has gravity. On the
moon, the gravity is not strong enough to hold gas molecules from
escaping and hence has no atmosphere.
QUESTION:
As time can be measured, what is the shortest duration of time?
How many such periods would fill a second?
ANSWER:
See an
earlier answer.
QUESTION:
I've been reading about physicists that need to shield sensitive experiments (neutrino detection and the like) using "old" lead because the radiation from traces of lead-210 (half-life 22.2 years) in recently manufactured lead interferes with the detectors. My question: when and how is a metal "born"? I mean, any sample of lead-210 has been around for same length of time and so will be decayed to the same degree, surely? The implication is that when you create a new ingot of lead, it is virgin lead, and the radioactive isotope has yet to decay. Can you explain how that is so?
ANSWER:
210Pb is a naturally occuring isotope of lead. It is a decay
product of 238U which has a half life of more than 4 billion
years. Therefore, if there is any uranium in the ore from which lead is
extracted, there will be 210Pb in the lead which is refined from the
ore. Since the refining removes only lead, the 210Pb will
eventually decay away.
QUESTION:
If the rest mass of a photon is zero,then it should not be
affected by gravity.But black hole shows that light is effected by gravity!
how does it happen?
ANSWER:
See earlier answers.
QUESTION:
Is it at all possible that just as photons are observable quantum particles (because of the huge quantity that are produced by things such as light bulbs and stars), there is some sort of observable quantum particle for gravity?
It would make sense if these quantized particles were able to self-organize into different structures, causing different behaviors, when there are more or fewer of them around (maybe some kind of gravitational Lego block?).
ANSWER:
These quanta are called gravitons; they are hypothetical since they have
never been observed and there is no successful theory of quantum
gravity. See my earlier answers
about gravitons. I do not see how their self-organizing would make
sense. Do photons self organize? What they might or might not do needs
to wait until a theory of quantum gravity is found.
QUESTION:
why the sound not travel on moon whenever there is a surface of moon as a solid medium ?
ANSWER:
Sound will travel through the material of the moon, just not through the
vacuum above it.
QUESTION:
I was wondering, why do we say that electrons in an electric current move from positive to negative eventhough they move in the opposite direction? When physicists found out that electrons move from negative to positive, why wasn't the principal changed?
ANSWER:
Whether the electron is positively or negatively charged does not really
matter. The charge was arbitrarily chosen to be negative (by Benjamin
Franklin) before it was known that electrons are the charge carriers of
most electric currents. Electric current is rate of charge passing
through the wire, so that means positive current flows in the direction
as positive charges would.
QUESTION:
Sands drops on a conveyor belt from a stationary hopper. The belt was acted on by an external force to keep moving with a constant speed.
I find out the power supply by the force is twice that of the gain in kinetic energy of the sands. I cannot figure out where the other half of the power is dissipated ?
ANSWER:
Friction between the sand and the belt must exist. Another way of saying
it is that the collision between the belt and the conveyer is not
elastic. The lost energy will show up as heat.
QUESTION:
Can you point me in the direction of a formula that I can use to calculate the effective weight in pounds of 200 lbs dropped 1 meter? I want to understand (if I can) the relative load of doing a body weight squat (load equals body weight) vs the load of dropping down off a 1 meter high bench (load equals body weight x X).
ANSWER:
There is no way to determine this because the force which a falling object exerts on something depends on the time it takes it to stop.
I do not know what a "body weight squat" is and do not have a picture of
what you are trying to do.
QUESTION:
I am a 8th grade physical science teacher and I want to be sure about my understanding of action/reaction forces before explaining it to my students.
My students recently completed a ‘balloon rocket activity’ where they calculated speed and identified and described the action/ reactions forces involved. Here are my two possible explanations. Which one is correct?
#1 action force-the air in the balloon exerts a force on the air in the room as it is released, reaction force-the air in the room pushes on the air coming out of the balloon causing motion
#2 action force-balloon pushes on the air in the balloon (forcing it out), reaction force-the air in the balloon pushes back on the balloon causing motion.
I do understand that action/reaction forces involve two objects and do not cancel. I tried to relate the balloon’s behavior to that of a rocket when launched to space.
ANSWER:
The balloon would work perfectly well in a vacuum. Hence, the room air
has nothing to do with it. Your #2 is the correct view. The balloon
pushes the air and the air pushes with an equal and opposite force on
the balloon. When you say that they "do not cancel", that means that
they do not cancel if you look at one body or another. But if you look
at the two or more bodies as a whole, all the Newton's third law forces
do cancel out. That is why when an artillery shell explodes the center
of mass continues moving in a parabola even as the pieces fly apart. It
is particularly important not to consider any pair of equal and opposite
forces to be due to Newton's third law. For example, my weight is a
force 200 lb down and the floor exerts a force up on me equal to 200 lb.
These are due to Newton's first law, not the third; you seem to
understand that when you say the forces "involve two objects". Any two
forces on an object which are equal and opposite cannot be Newton's
third law forces. For me on the floor, the floor exerts a force up on me
and I exert an equal and opposite down on the floor —that
is Newton's third law.
QUESTION:
Can one gravitational field be made to reinforce another gravity field, like sound waves at the right frequency can reinforce each other?
ANSWER:
Interference of sound waves results from the wavelike properties; waves
can interfere constructively or destructively. Gravity is not really
analogous to this because a gravitational field is not a wave. If you
have two gravitational fields, they just add like vectors. For example,
if the moon is between the sun and the earth, it feels a smaller force
than when the earth is between the sun and the moon. But, there is
nothing analogous to interference.
QUESTION:
If neutrons have only the attractive nuclear strong force to bind them together and no repulsive electromagnetic forces to push them apart, why isn't it possible to form large homogeneous "clumps" of neutron matter on earth? Or is it?
ANSWER:
The nuclear force is not just a simple attractive force as you suggest.
It is much more complicated and, in fact, a bound system of neutrons has
never been observed. A neutron star is a "clump" of neutron matter, but
it is held together by gravity, not the strong interaction.
QUESTION:
Why two protons stuck together have less mass than two single separate protons?
ANSWER:
First of all, two protons do not bind together —there
is no such isotope as 2He. But, any bound system has less
mass than the sum of its parts. Because E=mc2, if you
do work on a system, you increase its mass. In order to pull a nucleus
apart, you must do work and therefore add mass.
QUESTION:
Is 2012 real?
ANSWER:
Yes, 2012 will come in a little more than a year. Prepare for the end!
Seriously, read an earlier answer.
QUESTION:
NASA Says "Gravity is a force of attraction that exists between any two masses" and relates this to why we don't fall off the earth.
I am confused- as I am now watching NOVA, etc. on TV.
As I understand it, gravity is the warping of the fabric of space-time.
Please relate space-time to not falling off earth.
Is it because the fabric of space-time of the earth is pushing on us, and the earth is equally pushing back on us?
Does it have anything to do with the fact the earth is traveling at 67,0000 miles per hour around sun?
ANSWER:
Gravity is a force between objects with mass. But the origin of this
force was a mystery for hundreds of years. Einstein's theory of general
relativity is a theory which does an excellent job of solving this
mystery: it views mass as warping the space around it such that the
space becomes non-Euclidean, that is the shortest distance between two
points is not a straight line. Hence, for example, light passing by a
massive star is bent in its path because it is following a straight line
which is curved if we project it onto our Euclidean space of everyday
experience. None of this has anything to do with the motion of the
earth. The easiest way to get a feeling for why we are attracted to the
earth is to imagine a large mass sitting on a trampoline, warping it
down. Then objects placed on the trampoline will be "attracted" to the
large mass because of the warping of the "space". Be sure to note that
this is not meant to be rigorous, just a simple cartoon to help us
imagine the effects of warped space. You might want to read some of my
earlier answers on general
relativity and gravity.
QUESTION:
Glockenspiel problem: From redistribution of lycopodium powder I have verified that there are 2 nodal lines which for a 790Hz G are about 14 cm apart. My understanding is that a standing wave has been set up in the bar with a wavelength of twice the nodal separation, and therefore the speed of the waves in the steel bar is 790 x 0.28 which gives about 220 m/s, 20 times too slow for steel. Indeed if you take the speed to be 6000 m/s the nodal lines should be 3.8 m apart! Can you help me work out what I've done wrong?
ANSWER:
Sound waves are longitudinal. But the bar is not vibrating
longitudinally, it is vibrating transversely. Think of it like very
heavy string vibrating; if you have a vibrating steel string, the speed
of waves on the string have nothing to do with the speed of sound in
steel.
QUESTION:
I know there are nuclear processes that provide heat and energy, (the sun, power plants, etc...) but are there any nuclear process that mankind can harness that absorbs heat and energy and locks it away in matter.
ANSWER:
Certainly there are nuclear reactions in which the initial kinetic
energy gets converted into mass. However, for a nuclear reaction to take
place you need to get the nucleus of one atom close to another and that
takes extremely hight energies. So if you are thinking of using such a
thing as a way to deal with global warming, for example, forget it —hot
air could never get involved in nuclear reactions.
QUESTION:
If I were to roll a bowling ball off a 10ft-high ledge at 20mph, and another bowling ball from a 1000ft-high ledge at 20mph, would the bowling ball from the 1000ft ledge land farther away from the ledge than the other ball?
In other words, since the height is the only difference, does that change the distance away from the ledge the ball will land?
ANSWER:
When the ball leaves the edge of the cliff, it has a horizontal
component of its velocity of 20 mph and a vertical component of zero. As
time goes on, the downward component of the velocity gets bigger and
bigger but the horizontal component stays the same as 20 mph. Therefore,
since it takes longer for the ball to fall from the high cliff, it will
travel farther in the horizontal direction. (All this assumes that air
drag on the ball is small.)
QUESTION:
You stated in a previous answer, "The equivalence principle says that there is no experiment that you can perform which can distinguish whether you are in a gravitational field or an accelerating frame of reference."
OK, what would happen if you were in an enclosed room away from any gravitational sources, and were accelarating at 1G? I understand that it would feel the same as being stationary on the earth. But, what if you stayed in this room for a very long time? At 1G accelaration, you would hit light speed in about a year (which, of course, is impossible). How could you remain in this room for many years, still feeling like you were in a 1-G field, and not exceed light speed?
ANSWER:
As I have emphasized in
earlier answers, acceleration does not play the important role in
relativity that it does in Newtonian physics. Acceleration is not an
invariant quantity (i.e., unlike classical
physics, all observers do not measure the same acceleration of an
object). Newton's second law no longer may be written as F=ma
but must be written in the form F=dp/dt. Anyhow,
acceleration in the way you are thinking about it, such that you
experience an apparent force equal to the earth's gravitational field,
is not measured by an outside observer but is your acceleration relative
to an inertial frame which has the same speed you do. An outside
observer would see your acceleration get smaller and smaller as you
approached the speed of light. I encourage you to read the earlier
related answers.
QUESTION:
First of all you are lucky, you're a physicist, I want to be one two :( but too bad I'm still 15 :( Anyway, I wanted to ask about E=MC2, I'm a big fan of the great Albert Einstein and his theory is the best, I'm trying to understand everything about it , Einstein said that M=E and E=M, but why did he have to put the speed of light2 in his theory I mean to me it's not strange that E can turn into M and M can turn into E but why did he have to say C2?
ANSWER:
Mass is a form of energy, that does not mean that you can have one
kilogram of energy. In physics, all physical quantities must have the
appropriate units. The appropriate unit we use for energy is kg-m2/s2
which is called a joule (J). Therefore, mass does not have the same
units of energy. But since c has units of m/s, c2
has units of m2/s2 and so mc2
has the units of energy. Of course, that does not explain why E=mc2;
that is a whole other kettle of fish. I expect you are not ready for the
math, but I gave a brief derivation in an
earlier answer.
QUESTION:
My friend's brother was working on a science project, determining the angle which best optimises the distance traveled by a ping pong ball when launched from a catapult. He found 60 degrees above the horizontal to be the optimal distance, which really confused him because he was looking for 45 degrees. My friend and I explained to him that it was because of air resistance. Then we spent the last hour trying to get an equation for the distance a ping pong ball would travel in the x direction given the initial velocity and launch angle when considering air resistance. Basically, given Vo and theta, we are trying to solve for x, the distance the ping pong ball would travel in the x direction. How would you solve for this?
ANSWER:
This is a very difficult problem and one which can only be solved
approximately. You can get an idea about how difficult this can be by
reading some old answers
involving air resistance. The textbook 450
is seldom appropriate for the real world. I would suggest that you keep
this project restricted to an experimental one in which you determine
the angle for maximum range. Here are a couple of suggestions to make it
more interesting:
-
Change the
initial velocity of the ball. For no air friction the maximum range is
independent of initial speed, but if air friction is important it is
not.
-
Maybe
repeat for different balls. Perhaps a golf ball would be interesting
because it has much more mass. The more massive ball would have a much
smaller effect from air friction (although it experiences about the same
force).
-
If
possible, measure the terminal velocity of the ping pong ball (the speed
it achieves after falling until it reaches a constant speed). There
might be an interesting correlation between the results of #1.
QUESTION:
In a chemistry class I took recently, my professor shared an interesting anecdote. He had taken a class in college where the final exam was a single question: how fast does a train measuring two miles long have to be traveling in order to fit entirely into a tunnel measuring one mile long? If I'm not mistaken, as an object approaches the speed of light, it will shrink (or shorten, I'm not sure of the terminology). I posted the question on Facebook, and some of my friends became interested. Unfortunately, none of us have the know-how to answer it. Could you please answer this question? The idea that there is a single quantitative answer to this is extremely intriguing.
ANSWER:
One of the main results of the theory of special relativity is length
contraction. An object actually becomes shorter in the direction of its
velocity. It becomes a noticable effect only for speeds not small
compared to the speed of light. The length shortens by a factor
√(1-(v/c)2)
where v is the speed and c is the speed of light. So,
simply solve ½=√(1-(v/c)2).
I get v=0.87c=2.6x108 m/s=580,000,000 mph. Pretty
fast!
QUESTION:
What prevents a particle from being perfectly at rest?
ANSWER:
The uncertainty principle says that you cannot simultaneously know the
momentum and the position of a particle to arbitrary accuracy. If you
think about a particle being at rest at a particular position, this
implies you know both its momentum and position simultaneously and
exactly. If you know a particle is at rest, you know its momentum is
zero exactly; thus, to avoid violating the uncertainty principle, you
are completely ignorant of its position —it
could be anywhere in the universe.
QUESTION:
I work in the medical field and I do not understand how it is that the larger a syringe, the lower the pressure is on injection. If the diameter of each syringe opening is the same (which I would assume to be the case since they all fit into the same needles, etc.) and you use a different volume of fluid through the same diameter opening, wouldn't the pressure increase as the volume increases? I cannot understand why this is not so and am hoping that you can help me see the answer through math. Here is the info:http://tomfangrow.com/Syringe%20Pressure.html and they are listing the diameter of the of the syringe, not the diameter of the opening. So with a larger diameter syringe you have a larger volume of fluid.
ANSWER:
Basic fluid statics: If you increase the pressure at one point in a
fluid by a certain amount, you increase the pressure everywhere by the
same amount. If you have a syringe of radius R, its cross
sectional area is
πR2. If you now push with a force F on the
plunger, you increase the pressure everywhere in that fluid by an amount
ΔP=F/A=F/πR2.
As R get bigger, ΔP gets smaller. If, as is probably the
case, you are interested in the amount over atmospheric pressure you
have caused the pressure to increase, ΔP is what you are
interested in and is called the gauge pressure; gauge pressure is what
you measure when you measure the pressure in your tires. ΔP is
what is calculated in the little calculator on your website. The bottom
line is that the big fat syringe will be less effective in pushing fluid
through a particular needle than will a slender syringe pushed with the
same force.
QUESTION:
I understand that we have achieved temperatures in the lab of a few billionths of a degree kelvin (pK). Following E=mc^2 as the temperature (E) of the particles is reduced their mass should be reduced by deltaE/c^2. Does this mean that if the temperature of the particles could (hypothetically) be reduced to zero then they would have 0 mass and no weight in a gravitational field. How can matter have no mass and still be defined as matter?
ANSWER:
You misunderstand what E=mc2 means. When absolute
temperature is approached, the kinetic energy of the atoms approaches
zero, that is they stop moving. But, they still have their mass energy
when they cease to move. (Actually, you know, absolute zero cannot
be achieved and a particle cannot be perfectly at rest.)
QUESTION:
If someone discovers a unique, undiscovered, physics principle do they have the right to name it... Like stars?
ANSWER:
In physics, there is no generally accepted way to name laws or
principles. What normally happens is that if the finding is of
sufficient importance to be referred to in the literature, it will come
to have the name of its discover(s) —Newton's
third law, Maxwell's equations, the Casimir effect, Čerenkov radiation,
the Van Allen belt, etc. Sometimes there might be arguments over
priority or some such. This sometimes happens for synthesis of new
elements where two different labs might independently make a new element
and each want to name it after their lab, for example.
QUESTION:
So I understand the concept that based on the theory of relativity, the faster speed a traveler goes, the faster time occurs for that traveler.
So, why can't we test this theory with some crazy fast planes? Or with a simple rocket with a clock and a radio?
Or have we (that you know of)?
I realize that this would require ridiculously fast speeds (ludicrous speed!) to give a significant result, but why couldn't we just measure with precision?
ANSWER:
Well, I guess you do not understand! Actually, moving clocks run slower,
not faster. For the traveler himself, time progresses at a perfectly
normal rate; you seem to imply that if I were going fast and looked at a
clock I would see its hands spinning. Not so. Anyhow, time dilation, as
this phenomenon is called, has been tested innumerable times. Scientists
have taken extremely accurate atomic clocks on trips around the world
and found the clocks to behave as relativity would have it. An everyday
example is the GPS. Here the device is dependent on timing of signals
from satellites which, of course, are moving. If corrections were not
made for time dilation on the moving satellites, GPS systems would not
work to an accuracy better than a few miles. To learn a little more
about time dilation, read the following question.
QUESTION:
do you know" why" time slows down if you are travelling near the speed of light? relative to someone who is not.
ANSWER:
It is not hard to show, mathematically, why moving clocks run slow. I
have always found a simple example to be more instructive than a
mathematical demonstration, though. An earlier answer describes the
light clock which makes the fact plausible, I think.
QUESTION:
When converting energy to usable energy, the portion of usable energy which is actually available after the conversion is less than energy used to create it.
Does this hold true for nuclear fusion/fission?
ANSWER:
Actually, there is no such "law" that only part of energy can be usable.
You are thinking of the second law of thermodynamics which states that
no engine operating between two temperatures can be 100% efficient. But
some machines are 100% efficient. For example, if I lift a stone I
impart increased potential energy to the stone. If I then drop it, that
energy is 100% converted to kinetic energy of the stone. In fission or
fusion, mass is converted into kinetic energy of the reaction products,
100% efficiently. If you then try to build an engine to take that
thermal energy and use it to, say, drive a turbine, only part of that
energy can be thus used. This, however, is absolutely no different from
trying to use the thermal energy from burning coal to drive the turbine.
QUESTION:
Although theoretically impossible. if the Sun's mass suddenly ceased to exist how long before the lack of its gravity would be felt on earth and the solar system.
We know light traveling at 186,000 miles per second would take seven minutes before we would notice its loss.
Any hypothesis on a highly theoretical question? Isn't it true that gravity is the least well understood of the four forces? Is there any connection with the speed of light?
ANSWER:
See an
earlier answer. Regarding "least well understood," it all depends on
what you mean by well understood. In some respects the theory of general
relativity, the theory of gravity, is considered to be one of the most
successful physics theories. On the other hand, nobody had been
successful in devising a theory of quantum gravity.
QUESTION:
what is the difference between an object at rest and the same or identical object in motion.
Does the application of a force physically change the object or if the object itself is not changed then something else must be changed.
ANSWER:
The questions you ask are answered by Newton's first and second law.
Newton's first law states that an object with no net force on it will
remain at rest or continue moving in a straight line with constant
speed. There is no difference between the two states of moving or rest,
there is no meaning to absolute rest; whatever you see to be at rest may
be seen as moving by another observer. Newton's second law says that if
there is a net force on an object the result is that the object
experiences an acceleration in the direction of the force and
proportional to the force; so, what is changed by a force is the
velocity.
QUESTION:
Are there any effects on the body if traveling 30 miles per hour or more? My therapist says no and I say yes there has to be some effect. Who is right?
ANSWER:
Your therapist? Hmmm. The earth has a speed at its surface of about 1000
mph because of its rotation, a speed of about 67,000 mph due to its
orbit. Do those have any effect on you? Speed is not what you feel,
acceleration is what you feel. Accelerations greater than a few
times larger than gravity can have bad effects on your body.
QUESTION:
Why when we throw an object vertically upwards to reverse gravity and stops at a certain height, say that the speed of that object at that time equal to zero does not say that the weight of the object may become less or greater than the force of gravity ??
ANSWER:
The weight of an object is the force which the gravitational field
exerts on it. Provided that the height is very small relative to the
radius of the earth, the weight is totally independent of how the object
is moving or where it is.
QUESTION:
does the outside temperature change when a mass passes through the atmosphere. I imagine energy is released by the moving body creating a rise in the temperature......what happens in space , where there is no atmosphere?
ANSWER:
When an object moves through the air it experiences a drag force. This
force does negative work on the object, that is it takes energy away
from that object. What is happening, microscopically, is that the object
is colliding air molecules which bounce off with more kinetic energy,
that is the temperature of the air will increase. Hence we can say that
energy lost to air drag is converted to thermal energy. Under normal
circumstances, the increase in temperature is too small to notice.
QUESTION:
is it true that while a rock is still rising its velocity and acceleration are both downward?
ANSWER:
No. A thrown rock always has its acceleration downward but its velocity on
the way up is upward.
QUESTION:
Equally massed negative electrons and positive positrons annihilate each other when they collide. What if positrons are replaced by heavier but singly charged positive protons in the experiment? Do they annihilate each other? If not and form a neutron or hydrogen, why that route? And come to think of it, why does not hydrogen collapse to form a neutron?
ANSWER:
No, an electron and proton do not annihilate each other because they are
not each others' antiparticle. And a neutron is not simply a composite
composed of an electron and a proton. When a neutron decays there is a
third particle, a neutrino, which is emitted; this is called beta decay.
An electron and proton may come together to form a hydrogen atom.
QUESTION:
if you shoot a gun towards the back of the train and the bullet goes 2000 miles and hour in a train thats going 2000 miles does the bullet stop? what would happen?
ANSWER:
For questions like this I always start with " …you
must specify the velocity relative to what…" You would see the bullet
travel toward the back of the train with a speed of 2000 mph but
somebody standing by the side of the tracks would see the bullet
standing still.
QUESTION:
What prevents something from getting colder than absolute zero? I have ideas, like "you can only lose so much heat", but nothing I can really put together. Nothing scientific.
ANSWER:
Temperature is a measure of the average kinetic energy per particle. At
absolute zero all motion ceases. You can't get any "stoppeder" than
stopped!
QUESTION:
I'm working on a project involving gravitational fields, and I came across something interesting. If you calculate out the gravitational fields of the Sun and the Earth relative to the Moon, the Sun's field is much larger. So why is it that the Moon revolves around us instead of assuming a planetary orbit around the Sun?
ANSWER:
Interesting question. If you think about it for a minute, you will
realize that the moon does orbit the sun also.
QUESTION:
Why does crockery make such a loud sound when banged into another piece of crockery such as when stacking dinner plates?
ANSWER:
When two things collide, there is an apparent loss of energy (the
kinetic energy before the collision). But, energy is never really lost,
just sometimes converted into forms which we cannot get our hands on.
The "energy loss" in a collision usually goes to two possible
mechanisms, sound energy or thermal energy. If there is a possible way
to produce sound, then sound may carry off some of the energy, and
things like plates can vibrate like a cymbal and produce sound. In a
collision between things which aren't so good as sound sources, say two
blocks of foam rubber, most of the initial energy is converted to
thermal energy —things
get a little warmer. Usually this temperature increase is too small to
be noticed, but if you fire a bullet into a block of wood the hole is
pretty hot.
QUESTION:
If your riding a motorcycle, going 55 miles per hour, and it is 75 degrees outside, what is the temperature of the air that you feel on your skin? I ride a motorcycle and I know that there is a formula but I just don't know what it is and I hope that you have the answer.
ANSWER:
You must be referring to the wind chill index which attempts to
quantify how cold it feels at a certain temperature and wind speed. I
find that it is not defined for the situation you want —
750F
just never feels cold, I guess. It is only defined for temperatures
between -450 and 450. Read all about it at
NWS.
QUESTION:
What happens if a spinning object is released from the axis of rotation? In what direction will it move?
ANSWER:
If it is spinning about an axis which passes through its center of mass
(COM), nothing happens, it just continues spinning. If it is spinning
about an axis not through its COM, its COM continues moving with a
constant velocity equal to the velocity it had at the instant the object
was released. It will also be spinning but about its center of mass now.
(My answers assume there are no other forces or torques acting on the
object.)
QUESTION:
I am a biologist/teacher and I have a science question that came up as my son was doing a project that has me scratching my head. He was supposed describe how the work done my several natural events changed the environment by the work they did. One of the natural events was fire. Now, as a biologist...I can't lie...I am not great at physics. However, since work=force * distance, do fires do work? Fires may "travel", however, they do not have mass for forces to act upon (fire is energy, not matter).
ANSWER:
For starters, it is not true that fire is not matter; a flame consists
of hot gas released by the chemical reactions going on in the burning.
Certainly fires contain energy, so where is the work being done to
create this energy? To understand this you have to look microscopically.
There are chemical reactions going on and that is where the work is
being done. Interestingly, the energy is really coming from E=mc2.
The chemistry law which we all learn, that the sum of all the masses
after a chemical reaction is the same as before is technically
incorrect. For example, combining carbon and oxygen to form CO2,
a simple form of "fire" releases energy and the mass of the CO2
would slightly smaller than the mass of C+O2; this difference
is really tiny, too small to measure with any lab balance; what that
means is that chemistry is really a crummy (by which I mean inefficient)
source of energy if compared to nuclear energy which converts a much
more significant fraction of the mass to energy. Thinking of work purely
in terms of Fd is really a mechanical idea which does not give a
bigger picture of energy. Of course, fire can do work because we can
(and of course often do) use the energy it releases. If you want more
details about the chemistry of fire, a good short article can be found
on
HowStuffWorks.
QUESTION:
Why does the center of mass of a bomb follow a parabolic path if it explodes in the air?
ANSWER:
It is rather complicated to derive the equations which show that the
center of mass is an important location for a body or collection of
bodies. The basic idea is that, because of Newton's third law, all the
forces on something (like the bomb) which originate inside the system
cancel each other out if you observe the entire system. Also, Newton'
second law says that the acceleration of the center of mass of a system
is equal to the sum of the external forces on the system divided
by the total mass of the system (this is what is complicated to prove).
The bomb experiences only gravity as an external force; all the forces
which caused it to explode are internal forces and sum to zero if you
look at the whole system. If you really want, I can provide the
derivation, but you probably do not really care!
QUESTION:
barring gravitational forces, can a spacecraft, achieve the volicity of it's own thrust?
ANSWER:
Whenever you talk about velocity you need to specify with what it is
relative to. If you are on the spacecraft, you will always see the
exhaust coming out with some constant speed depending on how you create
that exhaust there on the ship. If you are standing on earth, watching
the spacecraft accelerate away from you, there is no reason why the ship
could not be moving faster relative to the earth than the exhaust was
moving relative to the spacecraft.
QUESTION:
Does cooling a substance (e.g. a freezer pack) below its freezing point, take its temperature lower? or is the freezing temperature the lowest it can go?
ANSWER:
The only limit to how cold something can get is absolute zero, about
-2730C=-4600F.
QUESTION:
This maybe in quantum physics...
couldn't find the answer(s) in previous ques/ans listing here.
As an electron joins with an ion to complete an orbit/shell; does it impart any spin? Magnetic?
does it impart any energy (Exo or Endo)?
And the reverse
Electron separating from an ion;
spin... magnetic? energy (Exo/Endo)
Is there any information concerning where a electron leaves an atom/ion?
as an atom/ion has magnetic poles (North & South) Would this effect the spin/rotation?
ANSWER:
This question is really too unfocused. Let me simply say that any time
you add or subtract something to a quantum mechanical system, the added
particle brings with it all its properties —mass,
magnetic moment, angular momentum, energy, etc. What happens in
any particular case depends on that particular case.
QUESTION:
We are studying momentum. We are taught that when delivering a karate chop to a board (in order to break it) one must pull back on the chop and not follow through. This delivers more force. Why, then, when you hit a baseball doesn't that same rule apply? Why are you taught to follow through?
ANSWER:
I guess I do not believe your basic tenet about "pulling back". Suppose
that we simplify the situation and throw a ball at the board. If the
ball sticks to the board it has transferred its momentum P to the
board and if the collision lasts a time t then the force
experienced by the board is P/t; but if the ball bounces
back with the speed it came in with, the momentum transferred is 2P
and the force is thus twice as great. But, here is my problem: your hand
is not analogous because your arm is what is responsible for pulling
back your hand, not the collision. Because of the addition of your arm
to the equation, there is no guarantee that momentum will be conserved.
I do not profess to know much about karate, but if this technique works
it may be something like "letting" your hand bounce back, not "pulling"
back, that is quit pushing when you collide. Then your hand would be
more analogous to the bounced back ball. (What I am trying to say here
is that the technique may be right, but the reason is not simple
momentum conservation.) Regarding the baseball, the situation is very
different because the baseball, unlike the board, is not at rest when
the collision happens. If you looked at the ball-bat collision from the
frame of reference of the incoming ball, the bat would bounce back.
QUESTION:
I know that if two carts (same mass and velocity) stick together when they stop because the momentum is conserved. But, why, if they do not stick together, do they bounce off eachother? How come the momentum is not conserved then?
ANSWER:
Your question is incorrectly stated because what you describe happens if
the carts have the same mass and opposite velocities. Momentum is
a vector quantity and under the conditions you state, the momentum is
zero before the collision and must also be zero afterwards. If the carts
both stop, obviously the momentum is zero. But, if the carts have equal
and opposite momenta after the collision they also have zero momentum.
QUESTION:
do all electrons travel at the same speed? If they do what percentage of the speed of light do they move?
ANSWER:
No, all electrons do not move at the same speed. They can move at any
speed less than the speed of light, just like anything else.
QUESTION:
I am interested in blocking radiation for health reasons from cell phones, tv's, computers and surroundings in general. There is in the market different products you can carry around your body for this purpose. I would like to know your opinion on the most effective-cost effective method. One option is to carry a magnet but what kind and which side goes in which direction, does it need to touch the skin, and how much can it block? I would like an option that protects as much as possible of my entire body and also for my child who is 5.
Please be as detail as possible, I want to do this right.
ANSWER:
You are setting yourself up to be preyed upon by people who take
advantage of people's irrational fears. There is no credible scientific
evidence that any of these devices is a health hazard. And one thing is
really true: there is absolutely no way that a magnet will protect you
from any of the radiations from any of these devices because the only
radiation reaching you is electromagnetic waves (radio waves, light,
maybe some x-rays) and all are totally unaffected by a magnet. If you
are really worried about this, your only option is to get rid of them.
Trust me, the dangers are minimal if not nonexistant.
QUESTION:
My question is about the sound waves produced by a guitar. What happens to the sound when you touch the string of the guitar very lightly?
ANSWER:
A vibrating string does not just vibrate with the frequency which you
"hear", the fundamental, but with all the harmonics of that frequency as
well. If you were to touch the string in the center you would kill all
vibrations of the fundamental and all even harmonics. If you touch it
elsewhere, you kill all vibrations which do not have a node at that
point. (A node is a point on the string which does not move at all as
the string vibrates.) This is a technique used by violinists to excite
higher frequencies than one normally can play on a violin.
QUESTION:
I understand the equivalence between gravity and acceleraton. (Someone in a spaceship accelerating at just the right rate, would feel gravity as as he were on the earth). So then, if we feel gravity we must be accelerating but I don't understand what is accelerating.
It can't be the earth so what is it?
ANSWER:
The equivalence principle says that there is no experiment that you can
perform which can distinguish whether you are in a gravitational field
or an accelerating frame of reference. It does not follow that if you
are in a gravitational field, you are accelerating.
QUESTION:
A” metre”rule measures 1 metre in its rest frame (surprise surprise). How fast would another observer need to travel past it in order to see it as a “12 inch” rule instead
ANSWER:
The formula for length contraction is L'=L √(1-(v/c)2).
1 ft=0.305 m. You figure it out!
QUESTION:
If you're on a spaceship with rotating searchlight on top, traveling just a snail's pace slower than the speed of light, what happens to the light beam?
When pointed forward, does it creep out at the snail's pace to make up the difference?
And what about off the side or pointed behind?
ANSWER:
If you shine it forward, you see it receding at a speed of c. But
an observer watching you go by will also see it going forward with a
speed c. Amazing, huh? But true. At extremely high speeds things
do not behave like you expect them to. If you shine the light out the
side with speed c, you will see it going sideways with speed c.
But, if somebody sees you going by, the light will come out of your ship
sidways but also with a component forward in your direction. But the
speed of this light will still be c.
QUESTION:
recently i got an answer on why the speed of light 'c' has such high value. but from where did we calculate this speed? is there any mathematical calculations to find c = 3 x 10^8 m/s?
ANSWER:
See an
earlier answer.
QUESTION:
If I put a fly in a sealed container and place the container on an analytical balance, when the fly takes off and begins to hover in the container, will the reading on the analytical balance go down or stay the same?
ANSWER:
It will stay the same. The fly hovers because the air exerts a force up
on him equal to his own weight. But, by Newton's third law, the fly
exerts a force down on the air which is equal in magnitude to his
weight; the scale registers this downward force. You might be interested
in the answer to an
earlier question similar to yours in which I go into much more
detail.
QUESTION:
If a hummingbird is hovering in a car, not in contact with any surface in the car, will it travel at whatever speed the car travels? And if so, what force is causing the hummingbird to travel forward in the car since it is not actually in contact with the car? Additionally, what happens to the hovering bird if the car is suddenly stopped? Will it lunge forward with the car or remain in place?
ANSWER:
The bird flies relative to the air in the car. An observer outside the
car sees both that air and the bird moving with the same speed as the
car itself. What makes you think that a force is necessary to move the
bird forward? Newton's first law says that an object with no forces on
it will move with constant velocity. Granted, the car requires a force
to move with constant velocity but that is because there are frictional
forces trying to slow it. The net force on the car is zero when
traveling with constant velocity. If the car stops suddenly, the bird
will do like you would if unrestrained —keep
moving forward until he hits the windshield.
QUESTION:
If it is impossible to reach the speed of light, and the nearest solar system is over 4 light years away, does this mean that the human race is pretty much stuck in our system?
ANSWER:
Well, if we could achieve speeds comparable to the speed of light (c),
four years is not such a long time. And, at such high speeds, the clock
of the travelers would show much less time, maybe only a few months. But
the problems of attaining such speeds and the stresses large
accelerations would put on the travelers would be such that, in my
opinion, the only practicable way of traveling such distances would be
to have a colony in a large craft with no intention of ever coming back.
(Of course, that is not without its problems either!)
QUESTION:
How did Chicago Pile 1 achieved a chain reaction? I know that they used purified graphite as a moderator and VERY pure uranium in the pile (reactor). The yellow cake was obtained from the Eldorado plant in Port Hope Ontario, which went through an ether process at the Mallinckrodt Chemical Works in St. Louis. Later some of the Mallinckrodt uranium was sent to the University of Iowa at Ames to be cast. Both the cast product and the Mallinckrodt product were used in the CP-1 matrix; the cast product, being purer, being placed closest to the center.
During the testing, building up to the pile, they used a beryllium/radium neutron source, both in New York City and, later, in Chicago, to test the graphite as a moderator (as well as initiators for the atomic bombs). That I understand.
However, when it came to the actual pile there is no mention of a beryllium/radium neutron source. It certainly appears that they relied on the uranium itself to initiate fission. But, how did they get the first neutron(s) to begin the chain reaction?
Does U-235 undergo spontaneous fission? If so, it must be at a VERY slow rate and with a good moderator (graphite or heavy water). I've heard about spontaneous fission and the Flerov-Petrzhak discovery of sontaneous fission in 1940. Fermi must have known about this.
So, did they use a radium/beryllium source or rely on spantaneous fission to start CP-1?
ANSWER:
It is indeed true that spontaneous fission is a rare event. On the other
hand, there are one heck of a lot of atoms there and even very
improbable events are quite possible at reasonable rates. Indeed, the
first reactor, in Chicago, had no external neutron source but relied on
spontaneous fission. Spontaneous fission can also be triggered by
external radiation like cosmic rays. It took me a while to find a
source which explicitly said this (see page 23).
QUESTION:
we know that light is travelling at a very high speed. what makes the light (or photons) to travel at such speed. is there any force that is cating on these photons??????
ANSWER:
The most basic of physical laws, Newton's first law, states that an
object upon which no force acts moves with constant speed in a straight
line. Hence, nothing needs a force acting on it to continue at a
constant velocity. The reason that light has the speed it does is
because of the properties of electricity and magnetism of which it is
composed. The speed of light in a vacuum is a fundamental physical
constant.
QUESTION:
What is power measured in kwh?
ANSWER:
kWh (kilowatt-hour) is not a measure of power, it is a measure of
energy. Power, measured in watts (W), is the rate of energy consumption.
One Watt-second is 1 Joule (J), a unit of energy. For example, a 100 W
lightbulb consumes 100 J of energy per second. Since a kW is 1000 W, and
one hour is 3600 s, 1 kWh=3,600,000 J.
QUESTION:
Does the frame of reference concept carry over into the interaction between electrons and magnetic fields? Specifically, does a magnetic field only result from an electron moving relative to an observer? For example, would an observer not moving relative to an electron not see a magnetic field and an observer moving relative to an electron see a magnetic field?
ANSWER:
If the electron were a charge alone, it does not have a magnetic field
if at rest. However, since the electron has a magnetic moment (i.e. it
looks like a tiny bar magnet), it does have a magnetic field when at
rest. If it is moving, there is an additional magnetic field due to the
moving charge.
QUESTION:
If there were two people on opposite ends of a metal rod that was one light-year long, and one person pushed their end of the rod one meter, how long would it take for the other end of the rod to move one meter?
ANSWER:
This question has been asked many times and has been
answered. The bottom line is that it
would take much more than one year.
QUESTION:
Say you started moving straight upwards from the ground, how high could you go before the air becomes unbreathable?
ANSWER:
People climbing Mt. Everest, about 30,000 feet high, usually carry
oxygen because the air becomes so thin at that altitude. It is not that
the air becomes "unbreathable" but that there is not enough of it.
QUESTION:
If the amount of gravity speeds/slows time, Then by that logic, would a person living on the moon age faster then a person who lives on the Earth?
ANSWER:
Yes, but the time rate would be so small as to be almost impossible to
measure.
QUESTION:
If you fired a gun in space, would the kickback send you flying in the opposite direction at the same speed as the bullet?
ANSWER:
No, you would fly off with the same momentum as the bullet. Momentum is
mass times velocity, so if your mass is 1000 times larger than the
bullet's, your speed would be 1000 times smaller.
QUESTION:
I just watched a program on History last night about time travel. My Dad was really into it and I learn a lot from him. He told me back then that if you put a clock on a space ship and have a clock with the same time back on earth, and that ship travels close to the speed of light (actually he said "very fast") when the ship gets back to earth the clock on the ship will have run slower than the clock on the earth.
They said that if we could hit warp, we could get to Alpha Centauri (sp?) in about 45 months. However, in actuality, it would take years.
Here's the question: Does that not blow Star Trek and Warp Speed out of the water? Let's say that Kirk gets a distress call from a planet light years away. He hits warp. On his vessel it takes minutes. On the other planet it takes years for him to get there. By that time - well, it's all over.
ANSWER:
You are absolutely right with regard to what we currently believe to be
possible for time travel. You may go to the future but you can never
exceed the speed of light and you cannot go to the past. Star Trek is
fanciful in that anything greater than warp 1 is greater than the speed
of light. Warp 9, for example, is about 1500 times the speed of light;
at that speed it would take 15 years to get to the center of our galaxy!
(I mined these "facts" from Lawrence Krauss's fun book The Physics of
Star Trek.) So Star Trek authors have to imagine another means of
time travel than just going fast, things like worm holes which let you
(in principle) burrow from one point in space-time to another. (Don't
ask me about worm holes because I really do not know that much about
them!)
QUESTION:
In outer space, there isnt gravity to hold back and since space is a vacuum, there is almost nothing to cause drag or resistance or resistance on an object. If we kept applying a force on the object, wouldn't it keep accelerating? To and even past the speed of light? (provided we had a strong enough propulsion device)
ANSWER:
Gravity and drag are not the issue, the laws of physics are the issue.
No object may go as fast as or faster than the speed of light. The
simplest way to understand this is that the faster that an object go the
greater its mass (its resistance to being accelerated) becomes such that
if it reached the speed of light its mass would be infinite; so it would
have required an infinite amount of energy to get there. Read an
earlier answer for more detail
QUESTION:
I understand that a moving charged particle creates a magnetic field. If you have two parallel wires with electrons moving the same direction, the magnetic fields cause the wires to attract. If the same two wires have electrons moving one way on one wire and the opposite way on the other wire, they repel.
Now, what about the case where the electrons are traveling in a vacuum. When two electrons are moving opposite each other, they will repel. But what about when they are moving parallel to each other? Their velocity relative to each other is zero. Do they see a magnetic field and attract, or do they see only the electric charges and repel?
ANSWER:
The two situations (current in a wire and current in an electron beam) are
very different as you seem to realize because there is no electric field
in the case of the wires. There will still be magnetic forces in the
beam cases, but the electric forces will be so much bigger that you
would be hard-pressed to see any magnetic effect at all. If you try to
look at two single electrons moving parallel, they will see no magnetic
force in their own rest frames, but they will in the laboratory frame of
reference. This is where releativity comes in and transformation of the
electromagnetic field is probably beyond the scope of this site.
QUESTION:
I just recently had an argument with an engineering friend of mine and was hoping you could help settle it as we tend to end up at an impasse when it comes to disagreements like this.
The argument involves human body falling at terminal velocity and landing back first on various materials.
He is of the opinion that landing on cement will ultimately cause less damage to the body than landing on soft loosely packed soil. He bases this on the idea that the speed of sound through something as dense as cement is faster than the speed of sound moving through something as dense as flesh and that this somehow imparts a greater ability to absorb an impact and therefore will do less damage to the body than loosely packed soil.
I am of the opinion that the soil is able to shift its position under pressure and able to be compacted into a denser form than its current state and that this allows it to better absorb the impact (than concrete would) which reduces the damage done to the object hitting it.
He argues that this is only the case in low speed impacts and that in a high speed impact at terminal velocity the concrete would be the better material to land on.
So, which material would you expect to do the least amount of damage to an object with roughly the same density as water that hits it at terminal velocity and why?
ANSWER:
That is just about the craziest thing I ever heard! What hurts you when you
stop is the force you feel. If you feel a large force, you are hurt; if
the force you feel is small, you shrug it off. So the trick is to
minimize the force. One way to write Newton's second law is that
mΔv=Ft
where m is the mass,
Δv is
the change in speed, F is the average force, and t is the
time during which F acts. (The physics way to say this is that the change in
momentum is equal to the impulse, mv being momentum and Ft being
impulse.) So, letting your mass be about 100 kg and your terminal
velocity be about 50 m/s, F=5000/t. Clearly, the bigger
you make the collision time t, the smaller F will be. If
you hit concrete you stop very quickly, say a hundreth of a second, so
the force you feel is 500,000 Newtons, about 112,000 pounds. If you
could make the collision last 1 second, for example by landing in a
swimming pool full of shredded foam rubber, the force would be 5000
Newtons, about 1100 pounds, which you would probably survive.
QUESTION:
Is there a formula which could be used to calculate the following scenario: How long would a single point on the floor be in contact with a disc brush having a surface area of 126 sq. in., rotating at 300 RPM, and traveling forward in a line at 2.5 mph?
ANSWER:
To answer your question, the rotational speed is not relevant —if
it were not rotating at all the time would be the same if the machine
were moving forward at 2.5 mph. It does not really sound like you want
to see where the formula comes from, you just want the formula. First of
all, the answer depends on where the point is relative to the center of
the brush. A point which the center passes over will be in contact
longer than a point which the edge passes over. Anyhow, the formula I
get is t=[√(40-x2)]/22 seconds where x
is the distance in inches from the line which the center travels. For
example, if x=3 in, the point is in contact with the brush for
0.25 s, about a quarter of a second; a point in the center, x=0
in, is in contact for about 0.29 s. But, is this really what you want?
It seems to me to be a much more complicated problem because the speed
with which the brush is passing over the point depends on how far it is
from the center.
QUESTION:
I have a question about traveling around 99.9% the speed of light and communications at those speeds. If a ship were to travel away from Earth at 99.9% the speed of light would communications with Earth be possible? The second part is what effect would time dilation have on communications? Would it be possible to respond to a question that in relative time has not been asked yet?
ANSWER:
In an earlier answer I discussed how
communications would sound, but communication is certainly possible. As
I note in that earlier answer, you could not have a conversation type of
communication because of the large distances and hence long travel times
of signals. You certainly cannot respond to a question which you have
not received.
QUESTION:
Does the inverse square law apply to laser beams?
ANSWER:
No, because the inverse square law applies if the waves spread out in
all directions uniformly. It does not apply to a flashlight either.
QUESTION:
When you jump off a high building, your velocity changes drastically to zero as you hit the ground. Since your mass is constant, the impulse is also constant. How does a soft mat cushion the fall?
ANSWER:
The impulse is constant, not because the mass is constant but because
the impulse is equal to the change of momentum. So, a 100 kg person
hitting the ground at the speed of 20 m/s has a change of momentum of
2000 kg-m/s. The impulse is the average force times the time which it
acts. If the time is short (as in hitting the hard ground), the force
you experience is big —ouch! Putting
a soft mat there increases the time to stop you, so the force
decreases—ahhh!
QUESTION:
in a current carrying wire ,is there a potential difference between any two points ,in between which there is neither active or passive elements
ANSWER:
All real-world wires have a nonzero resistance and so, if a current
flows, a potential difference exists. (Superconducting wires will not
have a potential difference.)
QUESTION:
I am doing a report on breaking the sound barrier, achieved first by the United States Air Force (And Assistance with NASA!)! I was wondering how fast is the speed of sound in ranking? I know light would be the first, but would sound be the second fastest?
ANSWER:
Do you mean second fastest wave? Light, you must appreciate, is in a
class by itself because, unlike all other waves, it can propogate
through empty space. However, light propogating through a medium is
somewhat slowed and therefore far faster than sound. Regarding sound:
sound waves through a solid, like a steel rod, travel much faster than
sound in air. There is really no point in trying to "rank" wave speeds
because there are so many possibilities.
QUESTION:
My daughter is working on a physics project that includes making a rollercoaster that must include 7 elements (loops,cork-screws,camelbacks) but the marble must complete the loop and stop at the original beginning. Is it possible, being pulled along by gravitiy and falling that it could be built to return to the original starting height? Without motors or mehanical propulsion?
ANSWER:
No, it is not possible. If she had a frictionless marble, she could do
it but some energy will have to be lost to friction and the real
therefore could not return to its original altitude without an external
push somewhere.
QUESTION:
why does a half empty bottle of sand (or half full lol) not roll?
ANSWER:
Whether or not it rolls depends on lots of things. If the sand is real
dry and powdery, it will sort of behave like you have half filled it
with a fluid and roll just fine. If it is real wet and sticky, it will
behave as if you have half filled it with concrete; but this will still
roll if you get it going fast enough, just in a jerky fashion. If it
rolls too slowly, the fact that the center of gravity of the whole thing
is not at the center of the bottle means that it will rock rather than
roll. Think of the limiting case where the bottle has no mass, at least
negligibly small compared to the sand. It will rock like a half
cylinder.
QUESTION:
I am looking for a physics answer to why it is bad to have too much positivity. That is, I am looking to describe - it in somewhat lay terms - how a basic structure of an atom has protons and neutrons... yada yada yada As you might have guessed, I am not a physicist but am looking for an answer that is indisputable and based in fact.
ANSWER:
It is not at all clear what you are asking. Since you mention protons
and neutrons, maybe you mean the nucleus of the atom, not the atom
(which also includes electrons, "negativity"?) There are two competing
forces in a nucleus, the electrical force which tries to blow it apart
because protons repel each other electrically, and the nuclear force by
which nucleons (which is what we collectively call neutrons and protons)
attract each other. If you try to make a nucleus with just protons, it
will not be stable because the electrical force wins out. But, if you
add some neutrons (which do not feel the electrical force) to the mix,
you add some nuclear force without adding any electrical force, so the
nucleus may become stable. This also has the effect of having the
protons farther apart because there are more particles in the nucleus,
and this means the electrical force is weaker. Atom heavier than around
calcium tend to have more neutrons than protons in their nuclei.
QUESTION:
An iron rod 1cm in diameter and 1 light year in length is located in outer space far from any astronomical body. Sufficient force is applied to one end (end A) of the rod the direction of its opposite end (end B) to move it one meter. An observer at end B will wait to observe the rod move one meter and then apply sufficient force on the end (end B) of the rod to move it one meter in the direction of end A. The final position of the iron rod along the axis of the forces applied from either end will be where it began. How long would an observer and end A wait between the initial force applied at end A and end A returning to it's original position?
ANSWER:
I have
previously answered almost exactly the same question. The answer is
that he would wait much much longer than two years.
QUESTION:
Have tachyons been empirically proven to exist? If not, what evidence is
there to suggest they might exist?
ANSWER:
Not to be flip, but the answers to your questions are "no" and "none".
The Wikepedia entry on
tachyons is pretty readable.
QUESTION:
A friend says that changing electric and magnetic fields generate one another, and this gives rise to visible light when the frequency of change matches the frequencies of light.
ANSWER:
Your friend has it right. Electromagnetic waves are caused by radiating
electric charges; charges which are accelerated radiate. An example of
this is the broadcast antenna of a radio station which has electrons
oscillating back and forth to create the radio waves. For visible light,
atoms act like tiny antennas.
QUESTION:
Why do balls bounce? Also because non-bouncy balls travel back up with less energy, does that mean more energy has been transferred to the surface upon which it was bounced (and a more bouncy ball has transferred less energy to the ground?) AND if that is true what would be the best way to measure the difference in energy transferred (throwing balls at scales, throwing them at Styrofoam and observing imprints, etc.)?
ANSWER:
Not all balls bounce. A ball of putty will not bounce. Essentially, a
bouncing ball is a collision with an infinite mass (that is, the earth
has totally negligible recoil). If a putty ball is dropped, where does
the energy it had go to? Mainly it goes to thermal energy —the
ball and the surface heat up a little; a little goes into the sound it
makes. This is called a perfectly inelastic collision. The other extreme
is a perfectly elastic collision where energy is conserved. So, the ball
hits with velocity v down and recoils with velocity v up.
Now, your question asking why balls bounce. During the time the ball is
in contact with the floor, the floor exerts an upward force on the ball;
the result of an upward force is an upward acceleration (that is
Newton's second law) and therefore the ball reverses its direction. In
the real world, a bouncing ball always loses some energy during the
collision and the collision is somewhere between perfectly eleastic and
perfectly inelastic. The easiest way to measure how much energy the ball
has lost (which you should think of as lost, not "transferred to the
ground") is to measure how high it bounces. If you drop it from a height
h1 and it recoils to a height h2, it
loses 100x(h1-h2)/h1%
of its initial energy.
QUESTION:
As I understand it, when a photon is created, say in a light bulb, it is instantaneously moving at light's speed. Its acceleration is therefore infinite. Since it's massless, perhaps that level of acceleration is acceptable, but the entire picture seems somewhat muddy to me. Is there a physical description of the event, or is it in reality no more than a mathematical result of equations those of us not in the field cannot grasp?
ANSWER:
Let's just stop thinking about photons for a second. Think about water
waves; do you worry about their accelerating up to their speeds
instantaneously? No, they just begin at the source and propogate out. Or
sound waves? There is something beating against the air and the waves
just move out. The same is true for electromagnetic waves. A radio antenna
has electrons accelerating back and forth creating time varying electric and magnetic fields which result in electromagnetic waves.
Acceleration is never an issue in these examples, waves are created
going as fast as they go.
QUESTION:
With my understanding of relativity an objects speed is determined by how fast it is moving in relation to another object. Also no object can pass the speed of light (C). So how would it be possible for an object to travel at 75% C in one direction while another object travels 75% C in the opposite direction?
ANSWER:
See
earlier answer. The bottom line is that things do not behave like
you expect if the velocities are not very small compared to the speed of
light.
QUESTION:
I came up with a thought experiment described below.
I setup a potential difference of say V volts between two horizontal parallel plates kept fixeda certain distance apart.I have given the upper plate +q C charge & the lower plate -q C charge.This system of course has some energy that depends on the charge in the plates and the plates separation. Now what i do is I pass a negatively charges particle with some initial kinetic energy, say Ei and velocity component purely horizontal , halfway through the two plates . As the particle emerges out of the electric field, it has gained some velocity along the vertical direction and thus has a kinetic energy Ef, greater than Ei. The difference dE = Ef - Ei is obviously positive implying it has apparently absorbed some energy from the field in course of its passage through it. As far as I believe, this brings about no change in magnitude of charge in either of the plates and the separation between plates has been held constant. So in no way is there a change in the energy of the parallel plates system.
It follows that by doing this I have managed my little particle to gain some energy without any other system having lost it!!
ANSWER:
Ah, the seemingly simplest questions are often the hardest for me to
come to grips with! Here, as has happened before, we have a situation
where we apply ideas about idealized simple situations and end up in
trouble. We assume that the parallel plates were charged up in complete
isolation from the rest of the universe. Further we assume that nothing
will disturb these plates, their charge distributions or positions, no
matter what we do. So, suppose that there is, in all the universe, only
two plates, one point charge, and a battery. The battery charges the
plates and the work it does is stored in the electric field which
appears; then it is removed from the universe. When we calculate the
energy necessary to charge the plates, we do it just the way our
physics teachers told us to do it. But, wait a minute —our
teachers never told us to worry about the field caused by our particle
we are about to shoot through, but does that not make a difference? If
there is some other field present the work to charge the plates will be
different from the ideal case. In essence, the particle has a potential
energy by virtue of its position vertically and this was imparted to it
when the plates were charged by the battery. (A colleague pointed out to
me that this problem is really no different from asking where the energy
comes from when I drop a stone.) Also, when the particle passes through,
the charges on the plates and the plates themselves will be pushed
around. But, the energy which "magically appears" is normally
infinetesmal compared to the total energy stored in the (not really)
uniform and constant electric field. So, once again, the physics we
learn in a physics class is only an excellent approximation to what goes
on in the real world. My argument would be that the electron already had
the energy it appears to acquire, but in the form of potential energy it
acquired when the field was created.
QUESTION:
I know that sub atomic particles are believed to have spin due to the internal angular momentum and magnetic field but i heard that if two sub atomic particles are created at the same time they both have to have opposite spins, but until the spins are observed they both have both spins.. how can this be?
If it is true, how does this work to a pair of sub atomic particles where the twin of the particle is X number of light years away and we observed one and found it went clockwise tthis means the one x number of light years away instantly starts going anti clockwise which means the information travelled fast than the speed of light which ofcourse is impossible.
ANSWER:
What you are referring to is entanglement, often referred to as
Einstein, Podolsky, Rosen or EPR paradox. And, you are not alone in
finding this rather puzzling —Einstein
himself was very uncomfortable with these kind of results which can
happen in quantum mechanics. I will give you a bit of an overview.
First, we do not "believe" elementary particles have spin, it is an
experimentally well-established fact. In quantum mechanics a particle
can exist only in certain discrete states. For example, if a direction
is space is chosen as, say, a z-axis, than an electron's spin may
point in either the +z direction or the -z direction, two
states we usually refer to as spin up or spin down. Now here is the
strange thing—an electron may be in a state which is a mixture of the
two possible states, half up and half down. This does not mean sideways,
it means partly up and partly down. Now, when you make a measurement,
you must find it in either up or down and the customary
interpretation is that the measurement "puts" the electron in the state
you "find" it in. Now we get to the EPR experiment. Here we create a
pair of electrons and the total spin of the whole system must be zero
because of certain considerations I will not go into here and are not
important. But they do not go into a state where one of them is up and
the other is down, they go into a state where each is half up and half
down. And they are flying apart, so if you wait a while they will be far
apart. Now you observe one of them and find it in (that is, put it in)
the up state. Since the spin of the whole system must be zero, you have
effectively put the other electron in the down state, instantaneously.
Preposterous you say? The fact is that experiments have been done to
verify this! If it is of any comfort to you, you cannot use this to send
a message instantaneously; you can just think of the entangled electrons
as a really big quantum system which is constrained to have certain
properties overall regardless of what you do to one little piece of it.
QUESTION:
A physics teacher told me that velocity is the rate of change of displacement with respect to time. It seems to me that displacement is a vector, which is the difference between two vectors that describe a body's position relative to a fixed reference point. Velocity represents the change in these position vectors over a certain time period. So velocity is the rate of change of position with respect to time or it is the rate of displacement with respect to time. Either of these definitions is OK with me. But to say it is the rate of change of displacement with respect to time is very confusing to me. Is it actually correct to say that? If so, please explain how I am wrong.
ANSWER:
It is, I think, redundant to say rate of change with respect to time.
"Rate of change" implies "with respect to time". Velocity is indeed the
rate at which the displacement vector changes. The average velocity over
a time interval is the change in displacement vector divided by the
elapsed time. The instantaneous velocity is the average velocity over a
vanishingly small time interval which, unless you have studied calculus,
will likely not mean much to you.
 QUESTION:
In geometric optics, when we have two lenses in series, and we wish to calculate the position and size of an image of an object... we can take the image of the first lens as the object for the second lens.
But it is not clear to me why we are allowed to do this in cases where the placement of the second lens prevents the image of the first from forming.
For example, if we have a convex lens with on object to its left creating a real inverted image on the right... and now we place a concave/diverging lens between the convex lens and the real inverted image.... why are we allowed to use the hypothetical real image of the first lens, which doesn't exist now, as the object for the second lens? It doesn't seem obvious to me at all, that we should be allowed to do this. Can you explain this?
ANSWER:
In a case like you describe, if the object of the second lens never
actually forms, then it is called a virtual object and the corresponding
object distance must be entered as negative in the lens equation. I have
chosen an example to show that it can be done both analytically and with
ray tracing. There is a converging lens (blue) with focal length f1=1
cm, an object at an object distance p1=2 cm. The image
distance is found using the lens equation, 1/f=1/p+1/q,
so 1/1=1/2+1/q1, so q1=2; the
magnification is m1=-q/p=-1 and the
image is real since q1>0. Now, as you suggest, insert
a diverging lens (red) with f2=-3 cm (f2<0)
1 cm to the right of the first lens so that the first image never
actually forms. Take as the object distance p2=-1 cm
so the lens equation is now 1/(-3)=1/(-1)+1/q2, so
q2=1.5 cm, m2=-1.5/(-1)=+1.5; so the
image is not inverted (compared with the object which is itself inverted
on the ray diragram) and magnified by 1.5 and real. In my ray diagram I
have only drawn two rays (in red) to locate the final image, the central
ray and the ray coming in parallel to the axis; you could draw more but
only need two to locate the image.
  QUESTION:
I am a artist currently studying in London! I was going to make some work about the Sun, more specifically the sunset. I did some calculations and tried to work out the difference in sunset times if you were on the ground and to each other floor in a building. Working with the measurement of one floor being 10ft I worked out the time, PER INCH, the sunsets are 0.05625 seconds in difference. I was wondering if you could confirm or replace this figure as correct.
ANSWER:
Here is the way I worked it out. Let R be the radius of the earth
(R=6.4x106 m) and h be the height above the
surface from which you observe the sunset. The sun will set over the
horizon which is the point where you would draw a tangent from your
observation point. Since the tangent to the surface is perpendicular to
the radius drawn to that point, a right triangle is formed as shown in
the picture to the right. For the angle A in that triangle we can
write
cosA=R/(R+h)=(1+h/R)-1. If
h is much less than R we can approximate (1+h/R)-1 ≈(1-h/R).
Also, the angle A will be very small in which case you can
approximate cosA≈1-(A2/2).
Therefore, A≈√(2h/R); the angle A in these
equations has to be expressed in radians. To find the time T
associated with this angle, change A to revolutions by dividing
it by 2π (e.g. if the angle is 900=π/2,
this is ¼ of a revolution); then divide the revolutions by 24 to get
hours and that by 3600 to get seconds. If I do all this I get T≈7.7√h.
So, for example, if you view the sunset from 100 m above the surface, it
will occur 77 s later than if viewed from the surface, more than a
minute. You cannot really specify the time difference per inch, as you
do, because the time is not a linear function of the height. If you ask
the average change per inch over the first 100 m, you get about 0.02
s/inch, in the same ballpark as your calculation. The graph shows a
calculation of the time differences for heights up to 1000 m, the height
of a modest mountain. I guess my calculations are really only right on
the equator if the earth's axis were not tilted, but I don't think you
want to worry about that kind of detail and neither do I!
QUESTION:
If an object with mass greater than that of the earth (say 1.5X) was to be placed on the surface of the earth, would the earth remain stationary or would it travel on a new path? To develop on what I mean; because the gravitational field of the earth would of course act towards it's center, and the mass's weight would therefore be acting towards the center of the earth, would the object simply sit on the surface or invoke movement due to being of greater mass?
ANSWER:
For starters, the earth could not "remain stationary" because it is not
stationary to start with. What would happen would depend on the size and
shape of the object as well as its mass and how it was moving before it
"attached" —its velocity and how it
was rotating.
QUESTION:
i just took up Table Tennis again after a long layoff and as you may know friction (imparting spin to the ball) is a large part of the game. I was surprised to read in one book that the amount of spin imparted to the ball from the paddle during the stroke was not a function of the SPEED at which the paddle "brushes" (almost tangentially) the ball, but of the ACCELLERATION while the paddle is in contact with the ball. They suggested approaching the ball slowly and accelerating through impact . I wrote to an "Ask the Coach" forum and the coach said he thought it was just a function of speed but asked if anybody knew the physics of the problem. I think i understand the difference between static and dynamic friction, but since the paddle isn't starting from rest, just going a constant high speed in one case vs. slow to fast in the other, i didn't think this would apply.
ANSWER:
Here is all I can think of. Because of inertia and limited frictional
force, hitting the ball with a surface moving very rapidly may result
mainly in slipping of the two surfaces which would not be so good for
imparting spin. So, starting slow to allow the paddle to "grasp" the
ball more effectively might result in more transfer of spin.
QUESTION:
How do you explain Boyles Law in terms of molecules and atoms and what assumtions do you make?
ANSWER:
Boyle's law is just a special case of the ideal gas law (for constant
temperature), PV=NRT. To derive the ideal gas law you assume the
gas is in thermal equilibrium with the container and that the volume of
all the molecules is small compared to the volume of the container.
QUESTION:
What is the force called that makes items in a container go to the sides of the container when you spin the container around?
Tony - 9yrs old
ANSWER:
Well, Tony, since you are only 9 years old I am tempted to just tell you
that it is the centrifugal force. If you like, you can just stop
there and have your answer. But, I do not like to mislead anybody, even
a 9 year old, so I will give you a little tutorial about circular motion
if you are interested. For anything to move in a circle there must be a
force on it which points toward the center of the circle; this force is
called the centripetal force. An example of a centripetal force
is if you twirl a stone attached to a string around you, the string
pulls on the stone with this force. What happens if the string breaks?
The stone will fly off in the direction it was going just before the
string broke (which is not straight out away from you). Although the
stone is not moving straight away from you, it is moving farther away
from you so it might look like there is a force pushing it away, but
there isn't, it is just moving along in a straight path. The same kind
of thing happens in a container. Imagine a stone sitting on the bottom
of a barrel, and the barrel is spinning very slowly —the
stone just spins along because the friction between it and the barrel
bottom provides the
centripetal force. But if the barrel spins real fast, there will not be
enough friction and the stone will slide; it will eventually hit the
outside side of the barrel and stay there, going around with the barrel.
It looks like it was forced out there but it just drifted out there like
that stone from the broken string going away from you.
QUESTION:
Can you please break down Schrodingers equation for me? What each variable stands for and can you please explain to me the theory behind his equation. I'm just a curious English professor and I'm having a difficult time understanding the equation as well as Heisenberg's Uncertainty Principle equation. If you can put the breakdown in layman turns I will forever be grateful.
ANSWER:
Well, this is a tall order. I have attempted to do this, in spite of the
fact that it really can't just be done concisely. It was a challenge! I
have not done an explanation of the uncertainty principle because that
does really cause the discussion to be too long and unfocused. Maybe we
can deal with that later if my discussion of the Schr ödinger
eqiation is what you had in mind. Link here.
QUESTION:
When salt is poured on a table it couses a mound, why does gravity not couse the salt to spread out on a flat layer?
ANSWER:
Because of friction, the same reason a block will not necessarily slide
down an incline if there is adequate friction. Actually the study of
such phenomena (often called "sand pile physics") can be pretty
complicated and is a serious study. The angle the pile makes with the
ground is called the angle of repose; interestingly, the angle of
repose for a particular material is independent of how high the pile is.
QUESTION:
Doing an outside loop, why does the normal decrease with an increase in tangential speed?
ANSWER:
Think of a car with a speed v at the top of a hill with a radius
R. Its acceleration must be a=v2/R,
straight down. There are two forces, the normal force N up and
the weight mg down; so, from Newton's second law, mg-N=ma=mv2/R.
If you solve this for N, N=m(g-v2/R).
You can see that as v gets larger, N gets smaller.
Eventually, when v= √(gR),
N=0 and all the centripetal acceleration is caused by the weight.
If you go any faster the car will leave the road.
QUESTION:
The more I read the more confused I get....I was asked What kind of light would be emitted by atoms if energy were not quantized?
ANSWER:
If an atom could be in any energy state and decay to a lower state, you
would have a continuous spectrum of light. If you had lots of atoms
being excited and the deexciting you would just get white light.
QUESTION:
In a standard textbook example, a charged particle moving with a constant moderate velocity perpendicular to a constant magnetic field is deflected.
If an uncharged observer is traveling parallel to the charged particle with the same velocity, it would see the charged particle as having zero velocity at first and then motion in the direction of the deflection observed by the stationary observer.
If the magnetic field is "constant", how does the co-moving observer explain the force on the charged particle?
I guess another way to ask the question is if charged particle motion in a magnetic field produces a force on the particle, and motion is relative (to the field), then is it possible to have "moving" field produce a force on a "stationary" particle?
Or more fundamentally yet, if the field is constant, how does the particle "know" it's moving through the field?
ANSWER:
What a good question. The thing is that electric and magnetic fields are
not really different fields like all elementary texts make it look.
There is one field, the electromagnetic field and the "mixture" of how
much of each is electric or magnetic depends on the frame of reference
of the observer. If, in a particular frame of reference, there is a pure
electric field, then if you view this field from a moving frame, a
magnetic field will appear. Similarly, if, in a particular frame of
reference, there is a pure magnetic field, then if you view this field
from a moving frame, an electric field will appear. The situation you
describe is the second and it is then the electric field which produces
the force on the particle "at rest".
QUESTION:
Lately, in physics class, I have been studying how some substances will heat up (less calories) faster than others. I have a question pertaining to this on the atomic level, rather than the molecular level as we have been learning.
If some substances heat up faster than others, then wouldn't certain elements heat up faster than others when changing states (say from a liquid to gas)? For instance, if we take water, with both hydrogen and oxygen, why wouldn't one element separate from the other (assuming they have different boiling points, or require less calories for heat of fusion)? Why doesn't one element reach the boiling point and not separate from the other element?
ANSWER:
This is really chemistry, but chemistry is really physics! It all
depends on the molecule you are working with. Some molecules will
dissociate before the solid melts or the liquid boils and then you have
a mixture of the constituent elements. But most often, particularly with
common inorganic compounds, the molecules are sufficiently strongly
bound that heating them does not supply the necessary energy to
dissociate them and the properties are determined by the molecule, not
its constituents. (Your particular example is one in which the atoms are
too tightly bound to be broken apart by adding some heat. But, if they
were not, when they separated you would already be well beyond the
boiling points of either because both are gases at normal pressures and
temperatures. The bottom line in answer to your question is that it
takes energy to break a molecule apart and often supplying heat is
insufficient to do that.
QUESTION:
It's my understanding that as velocity increases, so does mass. Now, let's say we have two spaceships accelerating away from Earth at the same rate parallel to one another. To observer's on Earth, their velocities are increasing and therefore so is their mass. However, relative to one another, they are motionless and therefore their mass would not increase. Does this mean that the mass of a particle is relative to the observer? From Earth's perspective, the ships would need more and more energy to accelerate, but from the ships' perspective, they would not. What's the explanation for this apparent contradiction?
ANSWER:
Just as the case of your earlier question, the
resolution of the apparent contradiction is length contraction. Think of
there being a stick attached to the earth and pointing out to the
spaceships' destination. As the spaceships go faster and faster this
stick gets shorter and shorter so that each burn of fuel results in a
smaller and smaller acceleration.
QUESTION:
This is a pretty basic question, but what exactly is force? Newton's second law states that F=ma. Mass, distance, and time are easy, and velocity and acceleration are obvious to anyone who can ride a bike. Momentum is a little more difficult, but it has an intuitive definition (how hard it is to stop something, or how much it would hurt if you crash your bike at various speeds).
I can't define force without using the terms "mass" or "acceleration." Given that F=ma is a law and not a definition, can you give me a definition of force? Or am I misunderstanding "law" and velocity=distance/time would also be a "law"?
ANSWER:
I will give you a brief rundown of how I present this when teaching.
First, to start doing physics you need to have an intuitive idea of what
three essentially underivable quantities are: two of these are length
and time. Once you accept that length is what a stick measures and time
is what a clock measures, you can do what we call kinematics which
mathematically describes motion. So, velocity is time rate of change of
position, acceleration is time rate of velocity, etc. No "laws"
here, just definitions. Now, if we want to do dynamics, which is to
determine what makes things move the way they do, we need a third
fundamental concept; scientists generally start with mass. Technically
mass is the inherent property an object has which causes it to resist
being accelerated when we push or pull on it. This is what is called
inertial mass. But, wait, I cannot really understand what mass is
without introducing the language of force, viz. "push or pull".
As you correctly point out in your question, mass and force are
inextricably intertwined. So, why is mass the one we label as
"fundamental", why not force? In fact, you could go either way, either
operationally define what mass is (say 1 kg is the mass of some
arbitrary chunk of stuff in a vault in Paris which is what we do) or
operationally define what a unit of force is (say 1 lb is the force the
earth exerts on a pint of water). The English system of units is the
lb/ft/s (force/length/time) whereas the SI system used by scientists is
kg/m/s (mass/length/time). Now, once we decide on mass, how do we find
out how it relates to force? We do what all good scientists do —do
experiments. Keep in mind that we do not have a defined unit of force,
only a qualitative idea that it is a push or a pull. Imagine making a
machine which will always deliver the same force when pushing on
something; a simple example would be some spring which we attached to a
mass and pulled such that it was always stretched by 1 cm. Now do a
series of measurements keeping the force constant and varying the mass.
You would find that the acceleration was inversely proportional to the
mass—double the mass and you halve the acceleration. Now, do a series of
experiment where you vary the force and keep the mass constant; you
could do this by pulling with one spring, then two, then three, etc.).
You would find that the acceleration was directly proportional to the
force—double the force and you double the acceleration. So, you have now
learned that the acceleration a is proportional to F/m.
This is what I think of as Newton's second law. But, since F is not yet
defined, I can now define it by choosing the proportionality constant to
be 1. Hence, a=F/m or F=ma. One unit of force,
which we call a Newton, is that force which will cause a 1 kg mass to
have an accleration of 1 m/s2.
QUESTION:
A rollerblader leans into a turn as he moves in a circle. The net torque about any point in the rollerblader must be zero if the rollerblader is not to fall over. If the torque is computed about his center of gravity, then the torque caused by the normal force of the ground up on his wheeels is balanced by the torque due to the centripetal force of static friction of the ground on his wheels. If these torques are computed about the contact point of the wheels on the ground, however, there seems to be a non-zero, net torque due to his weight since the normal and static friction forces act through the contact point and would not contribute to the torque about this point. The moment of inertia of the wheels negligable. How can there (seemingly) be a net torque about the contact point and none about the cg?
P.S. I submitted this question to the "Mad Scientists Network" and the engineer who answered it said there was an outward, "righting" force that acts through the cg. He did not state the nature of this force but it sounded suspiciously like he was thinking of centrifugal force. This didn't seem right to me. I want to know how a physicist would explain this.
ANSWER:
Hey, guess what: the engineer got it right! He just didn't give you a
complete enough explanation, and you deserve one! Ask the Physicist
goes where other Q&A sites only dream to go! Enough silliness, here it
is. Newton's laws are not valid in accelerating frames of reference and
you are attempting to apply Newton's first law (N1) (the sum of all
torques equal zero is the rotational equivalent of N1) to the skater who
is accelerating because he is moving in a circle. If he were not
accelerating, i.e. moving in a straight line and leaned over he
would fall. The best way to deal with accelerating systems like
this is to do a trick which inserts forces which do not exist to force
Newton's laws to be true; these are called fictitious forces. In this
case you must add a fictitious force which points away from the center
of the circle, acts at the cg, and has a magnitude equal to the
centripetal force; this is called the centrifugal (Latin root center
fleeing, fugo is I flee) force. Then everything works out and he is
in "equilibrium" in his accelerating frame.
QUESTION:
what happens when a rubber ball is thrown in a square room in outer space?
ANSWER:
Every time it collides with the wall it will lose a little energy, but
between collisions it will move in a straight line. So, if given an
initial velocity parallel to one of the walls, it will bounce in a
plane, going slower after each collision. If there is air in the room,
it will also slow down as it goes on its path.
QUESTION:
I have read that in the early formation of the universe photons collided to create electron. How can two massless particles (photons) create a particle with mass (electrons)? What is the process?
ANSWER:
Mass is not a problem, because photons have energy so it could be
converted into mass, another form of energy. The real problem is
electric charge. Photons have no charge and so charge would have to be
created. I do not know where you read this, but I think you must have
misunderstood.
QUESTION:
I understand that nothing with mass can travel the speed of light because an infinite amount of energy would be required to accelerate the mass and there is not an infinite amount of energy in the universe. As a statement, it makes perfect sense. But I don't understand the math:
". . .
The expression for the mass of an object m as a
function of its velocity v is m=m0/√(1-(v2/c2))
where c is the speed of light and m0 is the
mass when it is at rest. Note that as v approaches c, m
approaches ∞ so it is impossible to push beyond c.
Another way to look at it is from the perspective of energy. The energy
of a particle is E=mc2=m0c2/√(1-(v2/c2)),
so the energy required to accelerate the mass to the speed of light is
infinite and there is not an inifinite amount of energy in the universe."
Can you explain without math why an infinite amount of energy would be needed?
ANSWER:
No, you really cannot do it totally without math, but maybe I can make
it more explicit. Let's calculate the quantity 1/√(1-b2)
for various values of b. If b is the ratio of speed to light speed, then
this factor is what determines how big the energy of the particle is.
For example, if the speed is 50% the speed of light, b=0.5, b2=0.25,
and 1/√(1-b2)=1/√(1-.25)=1.15.
Go faster, say 80% the speed of light, then b=0.8, b2=0.64,
and 1/√(1-b2)=1/√(1-.64)=1.67.
Go faster, say 99% the speed of light, then b=0.99, b2=0.98,
and 1/√(1-b2)=1/√(1-.98)=7.07.
Go faster, say 99.999% the speed of light, then b=0.99999, b2=0.99998,
and 1/√(1-b2)=1/√(1-.99998)=223.6.
Go faster, say 99.99999% the speed of light, then b=0.9999999, b2=0.9999998,
and 1/√(1-b2)=1/√(1-.99998)=2236.
Can you see where this is going? When (never) we go 100% the speed of
light, then b=1, b2=1, and
1/√(1-b2)=1/0=infinity.
QUESTION:
Why is it necessary to orbit Earth and reach an escape velocity to fly away from the Earth? Why can't a spaceship, say destined for the Moon, just fly in a (generally) straight line from the ground to the Moon without orbiting Earth?
ANSWER:
It is not necessary. You could, in principle, go directly to the moon.
Planetary probes do not go into earth orbit on their way out.
QUESTION:
My inquiry is regarding a vertical ascent away from the Earth towards space. I was in a discussion with my father recently and we ran into a disagreement. His stance was that in order to leave the Earth vertically one needed to achieve Escape Velocity consistently through the ascent. My argument was that if there were a source of constant or, maybe consistent is a better word, propulsion an object could rise vertically at any speed.
ANSWER:
Escape velocity is the minimum speed you need to give to a projectile to
go up and never come down. If you had a source of propulsion, you could
escape the earth at 1 mph if you wanted to.
QUESTION:
If you were in a helicopter hovering above a single point on earth's surface for a long period of time, would your helicopter need to have any horizontal velocity to keep up with the rotation of the earth? Would the answer to this question change with the distance you are from the surface of the earth (i.e., boundary layer effects)?
ANSWER:
Certainly not. The helicopter flies with respect to the air and the air
moves (more or less) with the rotating earth. Any lateral velocity
component the helecopter has would be to compensate for wind, not motion
of the earth.
QUESTION:
Someone told me that if one body revolving around another is always facing that body which it is revolving around, that it is also rotating about its own axis, I don't understand how a body can be rotating if it is always facing the body it is revolving around, can you explain how this can be so please?
ANSWER:
To determine whether you are rotating, look a distant objects. If the
distant stars all do not move you are not rotating, if they do, you are.
A good example is the moon, the same side of which always faces the
earth. Over the course of one month, it sees all the stars rise and set.
QUESTION:
I just have a basic question regarding relativity. It's my understanding that for an object traveling at 99% the speed of light, time will slow down by a factor of approximately 7 (from an observer's perspective). So, if I were to travel 4.37 light years to Alpha Centauri at 99% light speed, from the perspective of an observer on Earth I would get there in about 4.41 years, but time would have slowed down for me and I would only have aged 0.63 years. Thus, from my perspective, I just traveled 4.37 light years in a matter of only 0.63 years. So, from my perspective, did it seem like I was traveling faster than light or am I thinking about this in the wrong way?
ANSWER:
Here is what you are missing: you see the distance between the earth and
the star as moving by you at 99% the speed of light. Not only do moving
clocks run slow, moving lengths get shorter. The distance you see
between the earth and the star is approximately 1/7 of 4.37 light years,
so there are no inconsistencies.
QUESTION:
Since the Earth is constantly spinning do you drive faster in one
direction (east or west) than the other?
ANSWER:
You have to ask, faster relative to what? Relative to the ground, 60 is
60. Relative to a stationary point outside the earth, your velocity
would be dependent on the direction of your velocity relative to the
ground.
QUESTION:
To my understanding, the binding energy is defined to be the energy that must be added to separate the nucleons. (i) The binding energy of Uranium-238 is positive, that is energy is required to separate the nucleons of U-238, then why is it still radioactive? (ii) Hydrogen-2 has an average binding energy per nucleon less than that of Uranium-238, but Hydrogen-2 is stable, why?
ANSWER:
Just because a system is bound, that does not mean that another
configuration of that system cannot have a lower energy. Alpha decay
often happens in very heavy nuclei because an alpha particle is very
tightly bound. Energy is released in the fission of a heavy nucleus into
two lighter products because of the systematics of binding energy. You
should read my earlier answer on fission and fusion.
I guess the bottom line is that bound is not synonymous with stable.
QUESTION:
A person is rotating a string with a mass at the end of it above their head. Let's say the plane of rotation is formed by the x and y axes. While rotating, the string (and therefore, the tension force causing rotation) makes an angle A with the plane of rotation. If you are spinning the mass with a constant freqency, the mass has no vertical (z axis) movement. I assume this is due to the z-comp of tension force balancing Fg. As the tension force increases, the angle A decreases.
Question: Is it possible to have A = 0? Why can the mass never go above the plane of rotation?
ANSWER:
If A were zero, there would be no vertical component of the tension to
hold up the weight unless the tension in the string were infiinite which
is not going to happen. To move the mass above the horizontal plane
where your hand is would require a net upward force and there is no
source of such a force.
QUESTION:
If you brought a flashlight into space and turned it on, would the light float away?
ANSWER:
The photons carry momentum, and so it would act like a little rocket to
conserve the momentum; the flashlight would accelerate. However, the
mass of the flashlight is so large that you might wait a long time to
see anything happening. If there were an appreciable effect, you would
feel the thrust when you held a flashlight.
QUESTION:
The magnetic constant (permeability of vacuum) has an exact solution 4.pi/10000000 This solution is in SI units. I cannot find a comparable solution in imperial units. How could I convert to ft, lbs... the solution would be?
ANSWER:
The constant
μ0 has units of N/A2. I presume you would
like to retain the A2, so 4πx10-7 N/A2=1.26x10-6
(N/A2)x(1
lb/4.45 N)=2.83x10-7 lb/A2.
QUESTION:
If Kinetic Energy is a product of mass and velocity does the massless photon in fact have kinetic energy?
ANSWER:
Well, I wouldn't say it is the "product
of mass and velocity"; that sounds like linear momentum. Kinetic energy
is a scalar quantity and equal to
½mv2 classically, but photons are not classical
particles, you have to use relativity. As I have noted many times
before, kinetic energy K of any particle with mass m is
K=E-mc2 where E is the total energy and mc2
is the rest energy. That is, kinetic energy is total energy minus rest
mass energy. The mass of a photon is zero and so, all the energy of a
photon is kinetic, it can never be at rest. So, what is the total energy
of a particle? Relativity tells us that it is E=√(p2c2+m2c4)
where p is linear momentum (but, not mv like classical
physics, it must be redefined). So, you see, for a photon both the
kinetic energy and the momentum are nonzero even though the mass is
zero: K=E=pc. Incidentally, the energy of a photon is E=hf
where h is Planck's constant and f is the frequency of the
associated electromagnetic wave.
QUESTION:
I had a question about Torque, Internal forces & external forces.
Here are 2 examples helping me to state my question:
1) The earth is rounding the sun with respect to the Sun.
The forces which are acting on the system are 2 gravitational forces that are action & re-action.
The Force vector & the Position vector will be in opposite direction; so their cross product is Zero & then the Torque will be zero.
2) In a system of particles, two objects are attracting each other with respect to a point (Q), which is located outside of the system.
With respect to (Q), We say these two forces cancel each other out & there will be no Torque on the system in view of (Q).
Why in case 2, we say these forces cancel each other; but in the first case, we don't consider the re-action of Sun's gravitational force?
ANSWER:
Both cases are the two-body system. Usually, when doing solar system
calculations, we approximate the sun's mass to be infinite (because it
is so large relative to any of the planets). In that case there is one
and only one force, the gravitational force which the sun exerts on the
earth. There is no "reaction" force which is pertinent. There is also no
torque on the earth as you note, because rxF is zero, so
the earth has a constant angular momentum. The whole problem is reduced
to a one-body problem. If we treat the sun and earth as a two-body
system (your case 2), we need to include both bodies. If we consider the
system as isolated, the earth and sun exert equal and opposite forces on
each other and so the net force is zero. Similarly, the net torque is
still zero. Thus both linear momentum and angular momentum of the pair
of bodies are constant. The two-body problem may be reduced to an
equivalent one-body problem and solved for the motion. What you keep
referring to as the "reaction" force does not make sense. If the sun
exerts a force on the earth, the earth must exert an equal and opposite
force on the earth; those are referred to as a Newton's third law pair.
If the sun's mass is very large compared to the earth's mass, you ignore
the force the earth exerts on the sun because it has negligible effect
on the motion of the sun.
QUESTION:
considering that two identical shaped objects of different masses hit the ground at the same time why if I add extra weight (as paperclips) to a paper spinner does it fall quicker when air resistance has not changed?
ANSWER:
The frictional force is approximately independent of mass. However, that
is not the only force on the object —there
is also the weight, mg. The frictional force is up and the weight
is down, so, if you increase the mass, the net force down is larger.
Another way to look at it is to estimate the terminal velocity. The air
drag is approximately proportional to v2, F=Cv2,
so when Cv2-mg=0 the object will fall
with a constant speed v. Hence, v=√(mg/c),
so you see it falls faster as m gets larger.
QUESTION:
If you had a large rock's density but then smashed the rock into smaller pieces. How could the smaller piece's density compare to the larger rock's density...?
ANSWER:
It depends on whether the rock was homogeneous (all made of exactly the
same stuff) or not. Density is mass divided by volume, and any
particular stuff has the same ratio of mass to volume regardless of the
volume. For example, if you had a 3 kg rock of pure quartz and broke
into three pieces of equal volume, you could be sure that each piece had
a mass of 1 kg. The density is determined by how heavy the individual
atoms are and how they are put together and this is the same regardless
of the size of the rock. [One proviso which you may not be interested
in: if you break a material into small enough pieces, nanoparticles, a
cluster of say 100 atoms might not have the same density as the bulk
material. One of the things of interest to nanophysicists is how small a
particle may be and still have the same properties as the bulk
material.]
QUESTION:
is it correct (or at all meaningful) to say that Planck's constant is the quantum of momentum?
ANSWER:
Planck's constant has the units of Joule-seconds, J s=kg m2/s;
momentum has the units of mass times velocity, kg m/s. So it is not
momentum. Instead, the units of Planck's constant are the same as the
units for angular momentum which are also kg m2/s. However,
it would be an oversimplification to say that "Planck's
constant is the quantum of [angular] momentum"; it sort of minimizes the
importance of h as a fundamental constant of nature. Planck's
constant was first used by Niels Bohr in this context (a unit of angular
momentum) in his model of the hydrogen atom. His model assumes that
allowed orbits correspond to angular momenta
Ln which are integral multiples
of
h/(2π), Ln=nh/(2π)
where n is an integer greater than zero. It turns out that this,
although it worked in some respects, is not quite correct. We now know
that angular momentum is given by Ln={√[n(n+1)]}h/(2π)
where n=0 is also allowed.
QUESTION:
When discussing angular rotation, which is the correct phrase to use "the body is rotating about its axis" or "the body is spinning about its axis" or "the body is revolving about its axis"?
ANSWER:
This is really semantics, not physics. I will give some common usages
which are by no means rules. Revolve usually means move around an orbit,
not about an object's own axis; however, the dictionary lists this as
one possible use of the word revolve. Rotate and spin are essentially
synonymous. In atomic, nuclear, and particle physics spin is usually
used as a noun meaning the intrinsic angular momentum a particle or
system of particles has which is a lot like rotating about its own axis
but not to be taken too literally because spin is a nonclassical
quantity. Orbital motion in atomic, nuclear, and particle physics is
usually referred to as orbital angular momentum rather than revolution.
In astronomy, revolve normally refers to orbital motion and rotate
normally refers to spinning on an axis.
QUESTION:
If time is affected by both mass and speed (ie. the faster you go and the closer you are to a large mass the slower time goes realtive to others), does this mean that a planet that is smaller than ours and is orbiting its sun slower than ours experience time faster than us relativly? And thus if life is capable of existing on this planet could it have evolved quicker?
ANSWER:
First I need to note that gravitational time dilation in the vicinity of
a mass the size of the earth is incredibly small; it is observable and
used by GPS software, but really tiny. Similarly, the speed of earth in
its orbit is very small with respect to the speed of light, so any time
dilation due to that motion is also tiny. But the real crux is that time
dilations are the rates of clocks as observed by observers other than in
the clock's frame, the time for any observer in his own frame proceeds
at the same rate as your clock. If you observe a clock at a lower
altitude or one that is moving relative to you, it runs slow; to an
observer riding with that clock, it runs perfectly normally.
QUESTION:
My understanding of physics is that matter can neither be created no destroyed. Rather, it can only be changed. (ex. if a building is burnt down, all the matter would still exist, but just in different forms, such as smoke, dirt, etc.) If this is true, then where did the matter that was exploded in the 'Big Bang' come from? (i.e. it had to exist in some form BEFORE the Big Bang, since matter can neither be created nor distroyed)
ANSWER:
Your "understanding of physics" is wrong.
Matter can be destroyed or created. Mass is a form of energy and it is
energy which cannot be created or destroyed. We consider the total
amount of energy in the universe to be constant. Your notion of the
constancy of mass is from chemistry where, although mass is not really
conserved in chemical reactions, it is so close to being constant that
you can do chemistry assuming it is. So, where did the energy to create
the universe come from? Nobody knows.
QUESTION:
I saw a commercial for a new type of car tire designed to increase fuel efficiency by reducing the amount of friction between the tire and the pavement. This makes it easier to get the car moving which means the car is using less fuel to make the car move. All this I understand. My question is, if we reduce the friction that keeps us from moving, do we also reduce the friction which helps us stop moving? Is braking ability being sacrificed for the sake of a better fuel efficiency?
ANSWER:
The friction used to drive you forward or to brake is static friction,
friction which keeps two objects which are in contact with each other
(tire and road here) from slipping. Sometimes, it is kinetic friction
(if you are "peeling out" or skidding). But there is also friction
associated with the deformation of the tire; because the wheel slightly
"squishes" when it rolls, energy is lost to this kind of friction. Also,
there is something called rolling friction which is related to the tires
sticking to the road so you are continually doing work "unsticking" the
tires, thereby losing energy. The "improved tire" addresses, I presume,
the latter two types of friction.
QUESTION:
I am a volunteer in scouting. I was wondering (although I have my own theory) what may happen if an individual had a magnesium block on their person and was electrocuted or struck by lightning. What do you think would happen
ANSWER:
I don't think the electricity would have anything to do with what would happen, it would be the associated heat. Magnesium is easy to ignite in little flakes but hard to ignite in bulk. So it might or might not ignite under the circumstances. If it did, it would be very hard to put out. That would likely be the least of the victim's worries.
What's your theory?
QUESTION:
This relates to time dilation. I've learned that if a person is passing a motionless observer at the speed of light, he will be observed to be traveling faster (as far as measuring time) than he would observe himself to be moving. My question stems from this notion. If you're in space - is motion relative? Do you have grounds to say one person is traveling at the speed of light whereas another person is motionless verses the opposite? Who is to say - in a perfect, hypothetical environment - which person is moving? If so, would they both observer the other to be moving faster than they observe themselves to be moving?
ANSWER:
As I seem to have to say several times a day, no person (or any object
with mass) can travel "at the speed of
light". You can get close, but not at that speed. See an
earlier answer. That said, the
notion of absolute velocity has no meaning. If one space ship has a
speed of 100,000 mph relative to another, the laws of physics are such
that there is no difference if we consider the speed of the second ship
to be 1000,000 mph relative to the first. See another
earlier answer.
QUESTION:
I'm watching the Empire Strikes Back right now and The Falcon's Hyper Drive is broken right now. Meaning it cannot go in to light speed. My question is, hypothetically of course, can a space ship enter hyper space with in the atmosphere of a planet?
ANSWER:
Physics of 2010 says no space ship can "go
in to light speed".
QUESTION:
http://en.m.wikipedia.org/wiki/File:Beta_Negative_Decay.svg
I found the above diagram while I was reading parts of the wikipedia article on a nutron. After a little thought am confused to how a down quark can decay in to an up quark, if quarks are elementary particles and by definition have no substructure.
ANSWER:
A particle with no substructure is not eternal. A simpler example, and
electron and a positron, each with no substructure, can annihilate and
create two photons. "Elementary" particles can participate in reactions.
QUESTION:
When an acoustic wave travels through a medium of particular velocity, does it change its frequency? In other words, which is fundamental property for a sound wave, frequency or wavelength?
ANSWER:
Wavelength changes, frequency does not.
QUESTION:
does a baseball and tennis ball have a different speed when thrown with the same force?
ANSWER:
Once again we have the question "how much speed does a force cause?"
Read my earlier answer. The
answer is that knowing the force is not enough. But, if you stipulate
that you push on each with the same force for the same time, or that you
push on each with the same force over the same distance, the tennis ball
will have the larger speed because it has a smaller mass and will
therefore have a larger acceleration.
QUESTION:
how were physicists able to determine that vanishingly tiny particles have the property of spin? is it really possible that the spin of such small objects is observable or is "spin" simply a term used to denote some sort of mathematical abstraction? is it correct to think of an electron "spinning" the way a top or frisbee does?
ANSWER:
Nearly all experiments which detect spin are really detecting the
magnetic moment of something. The first experiment was the
Stern-Gerlach
experiment which took a beam of silver atoms and passed them through an
inhomogeneous (that is, not uniform) magnetic field. The idea is that a
magnetic dipole (like a tiny bar magnet) will experience a net force in
such a field. What was observed was that the beam split into two beams.
This implied that the atomic dipoles were half in a N up, S down
orientation and half in the other orientation. Any time you have a
charge distribution which has an angular momentum (the more general
physics term for spin), the result is a magnetic dipole moment. So, if
you observe something about magnetic moments, you are likely observing
something about angular momentum. In this case, the spin angular
momentum of the electron in silver may be either up or down because the
magnetic moment causes the beam to split in two, and from that it must
follow that the spin angular momentum quantum number is
½. Spin of elementary particles is very much like spin of macroscopic
objects like tops, that is it is what we call intrinsic angular
momentum, something which is intrinsic to the particle, not due to
its motion (like in an orbit around the nucleus, which gives rise to a
different kind of angular momentum called orbital angular momentum). On
the other hand, there are distinct differences between micro- and
macroscopic spin. In particular, you cannot explain it by using the
standard classical models; for example, if you take the electron to be a
solid sphere with its mass uniformly distributed and calculate the spin
using a reasonable size, the surface will be moving faster than the
speed of light. Also, unlike a top or frisbee, you cannot stop the spin
or speed it up. The origin of spin can be understood using relativistic
quantum mechanics where it appears naturally.
QUESTION:
If time is affected by travel at the speed of light, (i.e. time travels more slowly for someone traveling at the speed of light). What would happen if you took two people (or clocks), and sent them in opposite directions on an elliptical course that will make them eventually pass by each other. What would the time difference be when they met in the middle?
Say, subject A travels "west" and subject B travels "east" both leaving at the same time, traveling at the speed of light. Would both of their clocks be equally offset to normal time when they pass by each other going opposite directions? Does the direction you travel have anything to do with the time dilation?
ANSWER:
You must not say "at the speed of light"
because nothing can go the speed
of light. For relativistic effects to be important, the speed should be
comparable to the speed of light, say 50% or more the speed of light.
You do not need an "elliptical course" for your question, you just need
to send the two in opposite directions and then bring them back. This
was worked out in an earlier
answer; the bottom line is that each ages the same as the other but
less than if they had not made the trip.
QUESTION:
Two pitches are thrown. Assuming all other variables remain constant such as batting power, wind, pitch, contact point, etc., which pitch would travel further? A 95 MPH pitch or a 85 MPH pitch.
ANSWER:
The important quantity is the impulse which is the average force times
the time that force acts. I found that a
typical impulse is about 13 Ns for a batted ball. The important
thing is that the change in velocity is proportional to the impulse. So
the ball which comes in with the smaller velocity will go out with the
larger velocity. Equal impulses will project the 85 mph ball faster. If
you are interested, the 13 Ns impulse will cause the 85 mph ball to end
up with a speed of 116 and the 95 mph ball to end up with a speed of 106
mph.
QUESTION:
With reference to energy transformation, why is a car's breaking distance greater down an incline rather than on a horizontal plane? I know that the main energy transfer would be of kinetic energy to heat energy [why heat energy?].
ANSWER:
Think in terms of forces doing work on the car. On level ground, the
only force parallel to the car's motion is the friction of the brakes
which takes energy away from the car. But when going down a hill there
are two forces acting parallel to the car's motion —friction
(opposite the motion) and the component of the car's weight parallel to
the road (in the same direction as the motion). Therefore the net force
stopping the car is smaller than the case of a level road so it goes
farther. When friction takes energy away from a system, nearly all the
energy ends up as thermal energy; for example, if you put your hands on
your brakes just after stopping your car you will probalby burn your
hands. Incidentally, the new hybrid cars are designed so that the energy
from the brakes gets put into electrical energy and so this energy is
used to charge the batteries.
QUESTION:
What would happen to the volume of a basketball left outside on a sunny day? Which gas law applies to this phenomenon?.
ANSWER:
The ideal gas law will cover this question; it combines all the other
usual gas laws like Boyle's law, Charles' law, etc. It is
PV=NRT wher P is pressure, V is volume, N is
the amount of gas, R is a constant, and T is absolute
temperature. In the case of your basketball, N is constant, so as
the temperature increases the product PV has to increase.
Basketballs I have seen are really not very stretchy, that is you can
increase the pressure quite a bit without changing the volume very much,
so mostly the volume would stay about the same and the pressure
increase. If the ball starts out not fully inflated, then the volume
would increase more.
QUESTION:
how to compute the amount of power is needed to keep an object floating in the air.
(For example how much power is needed to keep an electric helicopter floating)
ANSWER:
It is much more complicated than you think. At first blush, it would
take no power because if just hovering there is a vertical force equal
to the weight but it does no work. But in order to supply the necessary
force you need a mechanism and energy must be put into that mechanism to
supply the required force. For example, the force might be provided by a
moving airfoil (the helicopter propeller blade) and, as you suggest,
this might be driven by an electric motor. But the required energy input
is determined primarily by the engineering design of this
motor-propeller system, i.e. how efficient it is. So the bottom
line is that there is no way to answer your question in general.
QUESTION:
a weight lifter stands on a bathroom scale. she pumps a barbell up and down. what happens to the reading on the scale? SUPPOSE SHE IS STRONG ENOUGH TO ACTUALY throw the barbell upward. how does the reading on the scale vary now?
ANSWER:
When the barbell is accelerating up (which means going up and speeding
up or coming down and slowing down) the scale reads more than the
combined weights. When the barbell is accelerating down (which means
going up and slowing down or coming down and speeding up) the scale
reads less than the combined weights. If she throws the barbell up and
it is not in contact with her, the scale will read her weight. (I assume
that the scale can respond very quickly so it is really measuring the
force her feet exert down on it at any instant.)
QUESTION:
I was watching a documentary on Einstein, and contemplating his theory of relativity(and the recent debates on the speed of light being constant) and came up with a question, which while I am sure it is non-sense, still begs to be asked. Has/Can the speed of light in a vacuum, free of electromagnetic/gravitational anomalies ever been measured by two items that are truly at rest?
This would seem, by its nature, to have to occur in space, with two items that are not moving with our solar system relative to the universe. It would also seem to need to occur between two man made items since all other objects in the universe are inherently in motion. Feel free to correct me if my assumptions on the requirement of the experiment are wrong.
It would seem, though, that this would be the ultimate test of the speed of light being constant.
ANSWER:
Your whole idea does not hold water for one simple reason —there
is no such thing as "truly
at rest". (See earlier answer.) There is
something called an inertial frame of reference where the laws of
physics as we know them are true (things like Maxwell's equations,
Newtonian mechanics, thermodynamics, etc.). Any other frame of
reference which moves with constant velocity with respect to that one is
also an inertial frame of reference, the laws of physics are exactly the
same. There is therefore no experiment you can perform which
distinguishes any of these as the "truly at rest" frame. The "ultimate
test" of the constancy of the speed of light is that special relativity,
for which that constancy is the cornerstone, works perfectly. Nobody
feels any need to further test this; see
FAQ page for more on why the speed
of light must be the same to all observers.
QUESTION:
I know about Einsteins theory of relativity and how nothing (even an affect like gravity) can travel faster then the speed of light. Does that mean, when I look up at a star at night, if i was able to instaneously travel to the star, it wouldn't actually be there because its light has taken us so long to reach us?
ANSWER:
No, it just means that it would not look like what you are seeing here
on earth. Of course, there is no way to "instantaneously" travel
anywhere.
QUESTION:
A show about space stations were talking about a problem with communication with ground control because radio waves travel in a straight line. I wanted to know why do they travel in a straight line? I thought all EM waves spread spherically?
ANSWER:
How a radio wave is transmitted depends a lot on the design of the
antenna. A point source (very small and more or less spherically
symmetric) will send out waves that spread spherically, but since we
generally do not wish to beam in all directions, an enormous amount of
energy put into an antenna designed to look like a point source would be
wasted. If instead we beam out in one direction by using a "dish"
antenna (like the headlight of a car, for example), we can put our money
where our mouth is (put our power where the receiver is, that is) and
invest very little energy to send a signal. Another advantage is that
the strength of the signal falls off very rapidly for spherical waves
(like 1/r2) but maintains much more of its strength over large distances
for a dish antenna. The disadvantage would be that you have to aim it at
the receiver.
QUESTION:
Will the coefficient of kinetic friction remain constant for a system, even if the mass and acceleration change?
ANSWER:
The whole idea of there being a coefficient of kinetic friction is an
approximation. f= μkN
is not a law of physics but an approximate and empirical statement
that the frictional force is found experimentally to be approximately
proportional to how hard the surfaces are pressed together and more or
less independent of other variables (like the area of contact, the speed
of sliding, etc. for example). But for normal conditions (in
particular, N not too big) you may think of μk
as being a constant.
QUESTION:
I seem to have a paradox. Suppose we have 2 independent waves of amplitude A and energy E and in phase and travelling in the same direction coming from 2 lasers which are wired together. If we combine these 2 waves, by superposition, we will get a resultant wave with the same frequency and wavelength and amplitude 2A. Since the power of a wave is proportional to the amplitude squared and the frequency of all these waves are the same, the energy of the resultant wave should be 4E. However, by conservation of energy, the energy of the resultant wave should be 2E. Doesn't this violate the conservation of energy? Can't we get free energy?
ANSWER:
Well, this is the second time I have answered this question —I
had to delete the first answer because it was flat-out wrong. Maybe I'll
get it right this time. I have talked to a half dozen physicists, one of
whom is an expert in laser spectroscopy and also does extensive computer
simulations of electromagnetic wave phenomena. There are a few facets of
the answer to the question, but the most important overview comment is
that it turns out that the question technically violates my groundrule
discouraging "questions
based on unphysical assumptions".
Of course, I am not criticizing the questioner on this point inasmuch as
it took me 3 weeks to decide that this was at the heart of why I was
having so much trouble answering what seemed like such a straightforward
question. I will try to address the facets of the answer with a bulleted
list:
-
The question is posed as if we are looking
at electromagnetic waves which are one-dimensional, like the idealized
wave on a string. Physics texts do this all the time; so does Ask the
Physicist—just look at an
earlier answer
where I even show a nice picture of such a wave.
-
Now, we need to make sure we know what is
meant by "the
power of a wave is proportional to the amplitude squared" as the
questioner states. This is almost right but it is the power flux, which
is energy/time/area which is the integrated rate of energy flowing per
square meter. Through zero area the power flux would be infinite because
the area would be zero, so the whole amplitude squared thing would be of
no physical consequence.
-
The bottom line,
however, is that there is no such thing as a one-dimensional
electromagnetic wave. Even if there were, we would not be able to
satisfy the conditions of the question, putting two identical waves on
top of each other, as I will argue below.
-
The light from a
laser is, over the cross section of the beam, approximately a plane
wave, that is the wave fronts are disks. This is a good approximation
only away from the edges of the beam, so we will only use the center
portion in our imagined experiment.
-
Now we come to the
pièce
de résistance.
It is not possible to take the beams from two lasers, which are exactly
alike in frequency and geometry, and put them together with their wave
vectors parallel and perfectly in phase. (My laser expert agrees with
this statement). You cannot shine the second laser through the first,
for example. You might think you could do this with mirrors somehow, but
those mirrors steering one beam will inevitably get in the way of the
other beam. So the best you can do is have them almost the way you
stipulate, coming together with the wave fronts almost parallel. Now
there will indeed be places where the intensity over some small area is
twice as large as the sum of the two laser intensities, but this does not
violate energy conservation because there will be other places where
there is zero intensity. If you integrate over the whole area which
includes the intersection of the two beams, you get all the energy which
came from the two lasers, no more, no less. In essence, you have the
double-slit experiment.
-
Another word for
energy/time/area is intensity and there is no such thing as conservation
of intensity. A much more mundane example would be a lens: here we take
a beam of light and focus it to a small spot hundreds of times more
intense than the incident beam and do not worry about what that tells us
about energy conservation.
-
One colleague
advised me to tell you to just think of the two beams as being comprised
of photons, each with a certain amount of energy and each
indestructable, so energy has to be conserved. Of course, we both knew
we wouldn't be getting any "free energy" anyway, didn't we?
QUESTION:
Why does a superconductor have no resistance to a current. I mean what is the quantum state of a superconductor that allows it to have the properties that it has both with current and repultion of any magnetic field. Thanks for your time and hope to here from you soon.
ANSWER:
The basic idea is that, at low temperatures, electrons can pair up and
these Cooper pairs become the current carriers. The theory of
superconductivity is called
BCS theory for its
authors Bardeen, Cooper, and Schriefer; they won the Nobel prize in
1972. Although discovered in 1911, superconductivity was not understood
until the 1950s. The mechanism for the more recently discovered
high-TC superconductors is still not fully understood
theoretically.
QUESTION:
As an English major, you can imagine I've not done a whole lot of math. In movies and TV portrayals of mathematicians and physicists, we always see them working on blackboards with chalk or, more recently, on whiteboards using dry markers. These portrayal may well be stereotypes created by writers which have been emulated by subsequent writers. However, if these are true to life, why don't they use paper and pencil instead? I can think of a couple of likely reasons., but I'd like to know the real one.
ANSWER:
Sorry to disappoint you, but there is no "real one". Reasons to work at
a board are that
-
science is often
collaborative and this is a convenient way to show and share a train of
thought;
-
it is easier to erase and
revise than paper and pencil; and
-
some folks think better on
their feet and while moving around.
Often the only contact with
scientists that you humanities guys get is seeing us teach a class and we
couldn't very well do that on paper and pencil. Finally, most scientists
probably actually spend more time with paper and pencil or at a computer
keyboard than at a blackboard.
QUESTION:
I know that as an object moves though space it gains mass. Is there an equation to find the mass gained.
ANSWER:
If the mass of a particle at rest is m0, its mass m
when traveling a speed v is given by m=m0/√(1-(v2/c2))
where c is the speed of light.
QUESTION:
my question is about which equation properly governs the situation where an electron is approaching an electric field.
ANSWER:
I am not sure what you are after here. The force F felt by
a charge q in an electric field E is given by
F=qE and knowing the force you can calculate the
motion of the electron. Since the charge of an electron is negative, the
force it feels is opposite the direction of the field.
QUESTION:
I am trying to calculate the force involved in one American football tackling another, assuming both are travelling at full speed and hitting head on, will it be the sum of the momentum of both players ?
ANSWER:
As I have explained many times before, there is no way to calculate the
force from such information. It depends on the following:
-
What are the masses of each?
-
What are their speeds?
-
How long does the collision
last?
-
What is the nature of the
collision? Do they stick together? Or, if they bounce off, how much
energy is lost?
FOLLOWUP QUESTION:
2 object collide,
1 weighing 210 lbs travels 6 metres at 9.52 metres per second with acceleration of 5.66 metres per second squared. It's force is equal to 1188.6 lbs per metres per seconds squared and it's momentum is 1999.2 lb metres per second
the other object is 268 pounds, travels 4 metres at 8.49 metres per second with an acceleration of 4.51 metres per second. It's force is equal to 1208.68 lbs per metre per second squared and it's momentum is 2275.32 lb metres per second
the collision last 1 second and is non elastic.
What is the Impulse caused by the collision and how do i calculuate the force of generated during the collision ?
ANSWER:
Now, you have given me too much information! Since you give me masses
and momenta and velocities, there is no need for the distances and the
accelerations. Let me convert your weights to masses: 210 lb=95 kg and 268
lb=122 kg. Momenta:95x9.52=904 kg-m/s and -122x8.49=-1036 kg-m/s, so the
momentum before the collision is -132 kg-m/s. Using momentum conservation
for the collision and assuming a perfectly inelastic collision (stuck
together), -132=(122+95)v so v=-0.61 m/s, that is in the
direction the 268 pounder was going. So, the impulse delivered to the 268
pounder is equal to his change in momentum, J268=(122)(-.61-(-8.49))=961
Ns=F Δt
where F is the average force during the time of collision
Δt.
Since you say the collision time is 1 s, the average force is F=961
N=216 lb. The other player feels the same force in the opposite direction.
QUESTION:
Why do photons lack mass?
ANSWER:
Because, being the particle associated with electromagnetic waves which
have no mass, they could not. Also, according to relativity, only a
massless particle can go the speed of light.
QUESTION:
Due to the length contraction, you notice that a passing train appears to be shorter than when it is stationary. What do the people in the train observe about you?
If you are on a train that is going really fast, do the people on the ground look shorter, longer, or the same?
ANSWER:
Length contraction causes the lengths parallel to the direction of
motion to be shortened. So, a fat man standing at the station would
become a skinny man (side to side, but not front to back) but no shorter
as measured by someone on the train. Similarly, as measured by someone
on the platform, a fat lady standing on the train would become a skinny
worman but no shorter. You will note that I did not say that these folks
"look skinnier" because physicists normally do not care how something
looks, they care about how something is. This is a very
important distinction and one which even authors of physics books often
fail to make. How something looks may be very different from how
something is. Hence, your question is incorrectly stated (" …appears
to be shorter…")
although I believe I know what you meant.
I want to, in this answer,
provide a very detailed discussion of how moving objects look (I will
restrict this to one-dimensional objects like sticks moving along the
direction of their lengths, directly toward or away from the observer). I will be able to refer to this answer when
similar questions are asked in the future. When a physicist talks about
the length of something, here is what he/she means: measure the
positions of the two ends of the object at the same time; the
difference of those positions is the length. When you look at a stick,
you are not observing the stick ends where they were at one time but you
are seeing the farther end as it was sometime earlier than when you see
the closer end. Of course, this does not matter if the stick is at rest,
but if it is moving it does matter. For everyday moving sticks, there is
no perceptable change in the
apparent
length of sticks because speeds are much less than the speed of light.
But what if the speed is really big, let's say 80% the speed of light?
Then, as I will shortly show, the effect is really big. But before we go
into how long the stick looks or appears, we better be sure we
understand how long the moving stick is. The result from special
relativity, using the definition of length I gave above, is that the
moving stick is shorter by a factor of
√(1-(v2/c2)), so if v=0.8c
(i.e. 80% the speed of light), the length of the moving stick is
only 60% its length when at rest. (This effect is called length
contraction.) So now, the first picture shows the situation if the stick
is coming toward you (you are on the right). Light (red arrow) leaves
the far end of the stick and does not catch up with the near end of the
stick until the stick has gone a long way (four stick lengths) and now
light from the far (red arrow) and near (green arrow) ends move forward
to your eye. So the stick looks to be 5 times longer than it actually is
and 3 times longer than if it were at rest! Now, if the stick is moving
away from you, the situation is very different. The moving stick is
still 60% its at-rest length, but now the near end moves away to "meet"
the light from the far end; the result is that the stick, as shown in
the second figure, looks much shorter than it is. It now appears to be only 1/3 the
rest length or 5/9 the actual (moving) length. Note that in neither case
does the stick appear to be its actual length. (The scales of the two
figures are different; note the different rest lengths. I had to do this
so the "much-shorter" and "much-longer" figures would be about the same
size.) So, maybe you can now understand why I often make a big deal
about relativity being about how things are, not how things appear.
The same kind of arguments may be made about
time dilation: moving clocks run
slower, they may or may not appear to run slower.
QUESTION:
I am writing to you today to see if you can help me to understand the increase in velocity you are able to achieve by pumping a skateboard. I am not referring to pumping while inside of a pool or halfpipe, but instead pumping across a flat surface by carving back and forth left and right. How does this work?
ANSWER:
This is a bit involved, too much so for me to give a concise answer. The
idea is much like roller skating, though, where you manipulate things so
that the friction between the wheels and the ground is a force forward.
There is lots of detail (including the physics) at
silverfishlongboarding.com.
QUESTION:
Re: The life cycle of matter. Does matter ever really disappear or does it simply change form? i.e - When something burns and produces heat, does the heat contain matter? Obviously heat dissipates but if it does contain matter, could that matter be reconstituted into something else later?
Bottom line, is our universe a never ending cycle of matter into energy and energy into matter?
ANSWER:
The crucial idea is simply that mass is simply a form of energy and the total energy of an isolated system does not change. When something burns, the released energy is in kinetic energy of the reaction products (they move faster). This energy came from chemistry, specifically the binding energies of molecules. The root source of this energy is mass and a tiny amount of mass disappears when you burn something. It is very small because chemistry is really a poor source of energy. Nuclear
reactions, fission and fusion, are a much better source of energy and there you can rather easily measure the loss of mass of a nuclear system which releases energy.
QUESTION:
what percent of its hydrogen mass could the sun actually convert into helium?
ANSWER:
About 0.8%. That is how much mass is converted into energy in the fusion
process.
QUESTION:
does a single photon produce an interference effect or not?
ANSWER:
Yes. If you have a slit and a photon passes through it, the photon may
end up being "deflected", that it will be diffracted. To see the single
slit diffraction pattern, however, you need very many photons to "flesh
it out", but you can send them through the slit one at a time so the
interference is not with other photons. In essence, you must acknowledge
the duality of the radiation, it is both a photon and a wave, and
interference effects are manifestations of the "waveness".
QUESTION:
Phobos, one of the moons of mars, orbits at a distance of 9378km from the center of the red planet. What is the orbital period of phobos?
I would easily know how to do this if I was given the mass of mars, I am unsure if I am simply expected to look that up, or if there is a way to solve for this/ solve around this?
T= 4pi2r3/GM
ANSWER:
Your equation is wrong, should be T2=4 π2r3/GM;
that is Kepler's third law. Yes, you do need the mass of Mars (6.42x1023
kg) to do this calculation.
QUESTION:
This is quite possibly a fizzics question rather than a physics question, nonetheless, I ask you: Why don't sodas retaining their fizz like they used to? Is it the recipe, something to do with the planet, the atmosphere or what? How on earth can we get back our fizz?
ANSWER:
Funny, I have not noticed this at all. Maybe it is a case of misplaced nostalgia on your part?
When I was a kid I thought Twinkies were delicious but when tried years
later …well, yuk! How on earth can I
get back my delicious Twinkies?
QUESTION:
If I drop an object into a pool of water, is the wave generated proportional to the size of the object dropped? Example, if I drop a 1" and 4" ball bearings into a pool of water, will the the wave projected by the 4" ball bearing be 4X bigger than the wave generated by the 1" ball (keeping in mind that the 4" bearing is 4X heavier than the 1" bearing). Also, how does the height from which and the ball bearing is dropped affect the size of the wave?
ANSWER:
This is a problem which is very difficult to try to solve exactly
because of the complicated way in which the dropped ball interacts with
the water. If we assume that each ball were to give all its energy to
the wave generated, we can make an estimate. First of all, your
statement that "the 4" bearing is 4X
heavier than the 1" bearing" is wrong. The weight will be proportional
to the volume, not the radius (V=4 πR3/3),
so the 4" ball will be 64X heavier than the 1" ball. Therefore the
energy that each ball brings to the water will be in the same proportion
(64:1) if they are dropped from the same height. So the larger wave
would have 64 times more energy.
The energy of a wave is proportional to the square of the amplitude (the
height of the wave); or, the height of the wave is proportional to the
square root of the energy. Therefore, the 4" ball would make a wave 8
times bigger than the 1" ball but only if all the energies went into the
waves which is certain not to be exactly the case. (Incidentally, if you
were particularly interested in the relative wave heights for one ball 4
times heavier than another, it would be a factor of 2.)
QUESTION:
I heard that you can die or pass out from an acceleration beyond 4 or 5 g's. Does this mean that if you are going, say 5 miles per hour, and you decelerate greater than 5 g's you could pass out?
ANSWER:
Your numbers are a bit low. Fighter pilots routinely experience around
10g in tight turns but they do wear special suits to help the
blood being pushed from the brain causing loss of consciousness. Also,
duration is an issue; you will not pass out immediately. Certainly the
case you state will not cause you to pass out; the time to stop would be
only about 0.05 seconds at an acceleration of 5g. Whatever was
restraining you, though, might cause pain but you would not pass out
from the acceleration. Finally, you will certainly never die from a 5g
acceleration. You might read Wikepedia for more information on
g-forces.
QUESTION:
Why is kinetic energy a scalar even though it contains v in the formula which usually means a direction involved?
ANSWER:
Well, partly by construction; energy is defined in such a way that it is
a scalar quantity. But the easiest way to answer the question is to note
that the way v appears is as v2 and v2
is the scalar product of the vector v with itself, v ·v=v2.
QUESTION:
Why must a horizontally moving projectile have a large speed to become an Earth satellite?
ANSWER:
Because the harder you throw something horizontally, the farther it will
go until eventually it will go all around the world. Newton realized
this and discussed it in his famous book Principia. You might
enjoy an
applet which uses Newton's original sketch.
QUESTION:
We are studying free-body diagrams. Say an object is tossed into the air and then reaches its highest point, does this mean that all the forces acting on the object are balanced?
ANSWER:
Absolutely not. You cannot tell whether an object is in equilibrium by
knowing its velocity; its acceleration will tell you this. In this case,
the object is at rest but an instant earlier it was not and an instant
later it will not be. It is therefore accelerating and there must be an
unbalanced force; this force is the object's own weight which does not
disappear just because it stops for an instant.
QUESTION:
Why does a bouncy ball bounce back up after it huts a surface?
ANSWER:
During the time the ball is in contact with the surface it is
experiencing an upward force greater than its own weight. This force
causes the ball to have an upward acceleration (Newton's second law)
which causes it to acquire an upward velocity after the force has
momentarily stopped it.
QUESTION:
Does an electric arc generate an electromagnetic field??? Can a electric arc be be generated in complete vacum, for example in open space???
ANSWER:
Do three question marks make a question more pressing? Just kidding!
Yes, an arc has electric charges in it and these charges are moving, so
there will be fields generated. In fact, many of the electric charges
have acceleration and so electromagetic waves are also generated. This
is the origin of static on AM radio during thunderstorms. Also, Marconi,
the discover of radio transmission, used spark gap transmitters to send
his earliest radio signals. Since an arc is a plasma breakdown in the
gas, it cannot happen in a vacuum. What can happen is corona discharge,
where the electric field becomes sufficiently strong at the surface of a
metal that electrons stream into the vacuum.
QUESTION:
In two boys of unequal weights running towards each other with the same speed meet lead-on what is the result of the collision?
ANSWER:
It depends on how elastically they collide. For example, if they stick
together after the collision, they will move in the direction of the
heavier boy. In any case, the two will both move in the direction of the
heavier boy after the collision.
QUESTION:
"The laws of physics are the same for all observers in uniform motion relative to one another." But theoretically if one had a space shuttle that could travel at 2% the speed of light and on board it had a particle accelerator the could compensate for 99% the speed of light then relative to an observer out side the craft wouldn't the particle at times be moving at ~101% the speed of light. Why is this impossible?
ANSWER:
I have answered this question before. It is
also linked to on the FAQ page.
QUESTION:
Physics books and physics professors routinely explain gravity with the Einsteinian theory, that mass warps space. I have no evidence to dispute that and I have no reason to doubt it. My problem is with the model commonly used to illustrate it. A rubber sheet with a steel ball on it, hence gravity warped. If the universe were two dimensional then the analogy would make sense to me. Since the universe is at least three dimensional, then to be a valid model and become three dimensional, the warped rubber sheet has to be rotated through infinitely small arcs through 360 degrees at right angle to the plane of the rubber sheet before warping by the ball. When that is done the warping shape disappears. Remaining is possibly a model of density gradation but not of warping. If that is true then the model of the rubber sheet analogizes nothing, in my opinion. I would appreciate enlightenment if I am missing something.
ANSWER:
See an earlier answer.
QUESTION:
A friend of mine and I have an argument over what is a faster sport tennis or badminton. The criteria is how fast it would take to serve a tennis ball/shuttlecock from one side of an olympic sized tennis/badminton court to the player waiting on the other side assuming that both are standing on the out of bounds line. We are assuming ideal conditions and that the players in both cases are equally strong and fast.
ANSWER:
You may not realize it, but your question is mostly about air drag on
projectiles. I seem to get more questions about air drag than just about
anything else except maybe variations of the twin paradox. Maybe that is
because it is perhaps the most important phenomenon mostly swept under
the rug in most elementary physics courses. There are several instances
of earlier questions involving
baseballs and
lacrosse balls
which are very similar to this one. For
high speed projectiles, air drag is very important; e.g., a 100 mph
baseball loses about 10 mph by the time it crosses the plate.
Approximations have to be made to quantify the situation you are
interested in, but I feel the results I will present are pretty close to
what happens on the court. (The following is probably way more detail
than you want, but I put it here for anybody who might be interested.)

The approximations are:
-
I neglect gravity because
the times involved are are sufficiently short that the
ball/shuttlecock will not fall far or very much change its vertical
speed.
-
I assume that the drag is
proportional to the square of the speed—twice the speed, four times
the force of drag. This is an excellent approximation for these
speeds, these objects.
-
The form of the force I
use is F≈¼Av2 where A is the cross
sectional area presented to the wind. Here A=πR2
where R is the radius of the ball or the outer circle of the
feathers. This probably slightly overestimates the force for the
tennis ball (whose "hairs" have the function of decreasing the drag)
and underestimates it for the shuttlecock (whose "feathers" are
designed to increase drag).
-
Data for tennis:
-
Data for badminton:
I used the fastest recorded
serves for the velocity off the racquets, v0. If you
integrate F=ma, you get the following solutions:
v=v0/(1+kt) and x=(v0/k)ln(1+kt)
where k=¼Av0/m. Here are the results:
-
The tennis ball takes 0.39 s to travel the
distance, arrives with a speed of 62 m/s (139 mph), a loss of 11 m/s (24
mph).
-
The badminton shuttlecock takes 0.30 s to
travel the distance, arrives with a speed of 25 m/s (56 mph), a loss 67
m/s (150 mph).
I
will leave it to you to argue about what these numbers tell you about which
"is the fastest sport". The shuttlecock starts off the fastest because is
has a smaller mass and can therefore have a larger acceleration from the
force from the racquet. But it slows down very rapidly mainly because of its
small mass. The graph shows the speeds as functions of time.
QUESTION:
What is the origin of the word "magnet"? I have heard that there are two different explanations. I have found a lot of information referring to the ancient Greek city of Magnesia and a Shepard named Magnes. Is there any other possible explanation?
ANSWER:
From the Online Etymology
Dictionary:
magnet
mid-15c. (earlier magnes,
late 14c.), from L. magnetum (nom. magnes)
"lodestone," from Gk. ho
Magnes lithos "the
Magnesian stone," from Magnesia,
region in Thessaly where magnetized ore was obtained. Spread from Latin to
most W. European languages (cf. Ger., Dan. magnet,
Du. magneet,
It., Sp., Port. magnete),
but superseded in Fr. by aimant.
QUESTION:
In a pendulum there is a force exerted on the mass by the string but why doesn't this force contribute to the energy of the pendulum? Is the force of the string simply counteracting the force of gravity?
ANSWER:
In order for a force to add or subtract energy it must do work. The
tension in the string is always perpendicular to the motion of the mass
and so it does no work.
QUESTION:
The speed of wave works it way up the spectrum (i.e. sound, rf, microwave, light etc) The deeper the sound the slower and conversley the higher the sound the faster the wave. When measuring light speed, what "color" is used as the optimal for speed? I would have to assume InfraRed would be the fastest but that does not necessarily mean it is the benchmark used for determining the speed of light. Also is the variance in speed between ultraviolet and infrared a measured value? I know you can find the wavelength with a quick search, but are the differences in speed of the wavelengths a measured factor? (Yes, we often have some "off the wall" conversations at lunch)
ANSWER:
You start with a statement, not a question, which is wrong. First, sound
is a completely different thing from the others you have listed. The
speed of sound in air is independent of frequency; if this were not true
you would not be able to listen to music because the different pitches
would reach you at different times. In some media, there might be a
slight difference but it is a very small effect. Electromagnetic
radiation (all your other examples, rf etc.) is completely
different from sound; sound is propogation of pressure variations in a
medium like air whereas
EM radiation
is a traveling fluctuation of electric and magnetic fields. EM waves in
a vacuum all travel with precisely the same speed, 3x108
m/s=186,000 miles per second. It does not matter if it is a radio wave
from your local AM station, a microwave in your oven, the light you can
see with your eye, or an x-ray to check your arthritis —all
have the same speed. In a material, like glass or water, for example,
light goes a bit slower and there is a slight difference for light
with different colors; you stated that higher frequency waves have
larger velocities, but actually it is the other way around. The slight
difference in materials is called dispersion and it is the explanation
for rainbows, prisms splitting white light, and pretty diamonds. To a very
good approximation, though, the speed of light (and all other EM
radiation) is independent of frequency; when the speed of light is
referred to, it usually means the speed in a vacuum. Toss that all
around at lunch!
QUESTION:
At the Large Hadron Collider at CERN what is the mass of a proton at it's maximum speed, what kind of gravity is produced by that mass?
ANSWER:
The proton energy is about 7 TeV=7x1012 eV. The mass is given
by m/ √(1-(v2/c2))
and, for this energy (see answer below
to see how to calculate this), 1/√(1-(v2/c2))≈7000,
and so the mass is about 7000 times greater than the mass of a proton at
rest. The gravity of such a mass is totally negligible. The mass is only about 10-22 kg, much heavier than a proton but much
lighter than a speck of dust.
QUESTION:
Will a car go faster if the body is 2" off the ground are 4" off the ground
ANSWER:
There is no way to answer this question.
FOLLOWUP QUESTION:
If a nascar car's front spoiler were raised 2 more inches in order to let more air pass underneth the car would they go faster?
ANSWER:
I guess I did not give enough detail in my first answer! The
aerodynamics of a car can be very complicated and often not intuitive.
This is a very difficult engineering problem and much computer time and
wind tunnel time is usually consumed studying how best to design a
vehicle to minimize drag. The various parts of the vehicle interact with
each other and so messing with one part affects the way other parts
contribute to drag.
Here is an anectdote which illustrates that your intuition is not always
right regarding drag. Some years ago somebody called in to
Car Talk on NPR and asked
about these nets you can buy to replace the tailgate in a pickup truck
to reduce air drag. Makes sense, right? The tailgate is like a wall in
the wind and to get rid of it will reduce drag and increase your
mileage. Click and Clack said that they thought these things were a
great idea for reducing drag and increasing fuel efficiency. During the
intervening week before the next show an engineer from GM called in and
told them that removing the tailgate in fact greatly increases the
overall drag on the truck. The reason is that the tailgate traps a
bubble of air which rides along with the truck and the headwind slips
over it. There was a lot of crow-eating that week at Car Talk Plaza!
QUESTION:
Is the downward pressure of where a cars tire and the surface of the road meet the same when the car is moving 60 mph, or not moving at all? I had a friend tell me he drove across a frozen lake and could hear ice cracking while he drove 60 mph and made it to the other side. The lake was about 1 mile across and thinner ice toward the middle because of a creekbed that runs the lenght of the lake. everybody else just laughed in disbelief.
ANSWER:
The force the wheels exert down on the ice will be equal to the weight
of the car regardless of whether the car is moving or not. If, indeed,
the weight of the car was big enough to break the ice, then the
explanation you seek is likely that it takes time. That is, if the car
is placed on the ice at rest, small cracks will start to spread, get
bigger until the ice fragments and the car falls through. If moving, the
network of cracks likely would not have time to spread enough to
sufficiently weaken the ice.
QUESTION:
An electron accelerates through a potential difference V = 1000
keV. How do we find the speed of electron?
ANSWER:
When an electron, charge e=1.6x10-19 C, accelerates
through a potential difference V, the kinetic energy acquired is
K=eV. The energy acquired when accelerated through 1.0 V is 1.6x10-19
J and this amount of energy is also called 1.0 electron-volt (eV). You are
asking to accelerate an electron across 1000 kV=1,000,000 V (you say keV,
but you want to specify the voltage in kV, not the energy) which is 106
V, so K=1.6x10-13 J. It is now tempting to just set K=½mv2
and solve for v, but, if you do (m=9x10-31 kg), you
will find that the speed is greater than c, the speed of light! The
classical expression for kinetic energy is only true if the speed of the
particle is much less than c. The correct relativistic expression for
K is K=E-mc2=mc2[(1/√(1-v2/c2))-1]
where E is the total energy and m is the mass of the particle
at rest; it may not look like it, but this equation reduces to
K≈½mv2 if
v is much smaller than c. Before I finish your calculation, I
will give you a handy-dandy way to determine whether you need to use
relativity or not in this kind of calculation. If the kinetic energy is much
less than the rest mass energy (mc2) of the particle, you
may safely approximate
K=½mv2.
For your example, K=1 MeV and, for an electron, mc2=0.51
MeV (electron volts are a much more convenient unit of energy than joules
for elementary particles); so, for your problem, the kinetic energy is twice
the rest mass energy, so you have to use relativity to compute the speed.
So, from our equation above, 1=0.51[(1/√(1-v2/c2))-1];
solving, v=0.94c=2.8x108 m/s, 94% the speed of
light.
QUESTION:
If you took an electron away from Iron would it still be Iron? I know if you took a proton away it would not be iron and if you took a neutron away it would still be iron,
ANSWER:
It is still iron but is now an iron positive ion, Fe+.
QUESTION:
The scenario is three car collision. Car 1 is first in line in stopped traffic. Car 2 is stopped behind Car 1. Car 3 fails to stop and runs into Car 2, pushing Car 2 into the back of Car 1. Car 3 was the 100% cause of the accident, yet the driver of Car 1 says he felt "2 impacts." How is this possible?
ANSWER:
I am sure there could have been several ways this could have happened.
Here is one that occurs to me. Car #3 is heavier than car #2 and their
bumpers are sort of elastic; so car #2 rebounds forward but car #3 keeps
going but with a reduced speed. Car #2 hits car #1 and both stop. Car #3
hits car #2 for the second time and then car #2 hits car #1 for the second
time.
QUESTION:
One of the most accurate clocks ever, I recently read, is accurate to one second in the next 3.7 billion years. Minutes before, I read an article about the discussion of whether time exists in the universe or not, and if so, how it exists in our world.
My question is: Is it even possible to have a perfectly accurate clock? Furthermore, is it possible to keep that clock in a fixed point in space so it remains accurate?
ANSWER:
I am sure the article about whether time exists was interesting, at
least philosophically. But if we are going to discuss clocks, I guess we
need to assume that it does exist since a clock measures something. Our current
understanding of time, based on the theories of special and general
relativity, tells us that the rate that time ticks depends on two things,
the speed of the clock relative to the observer and the gravitational field
the clock is in (or, equivalently, if the clock is accelerating). If we
construct a clock in a particular frame of reference such that it is at rest
with respect to us, with a constant acceleration and/or gravitational field,
the accuracy of the clock is ultimately determined by quantum mechanics. A
time can not be measured with arbitrary accuracy because of
the Heisenberg uncertainty principle,
∆E∆t≥h/(2π).
Precision measurents of time always depend on having some precisely known
energy, such as the energy of some atomic state, so the uncertainty in the
energy is linked to the uncertainty of the time measurment. The clock will
remain accurate to its design specifications in the frame where it started.
Change the gravitational field (by changing its altitude, for example) or
make it move, and it will not continue running at the rate it would have if
left alone. One of the reasons we need such accurate clocks is that without
them GPS would not work.
QUESTION:
What are Alpha Particles, Beta Particles, and Gamma Rays? What is the differance between them?
ANSWER:
Alpha particles are the nuclei of 4He atoms, consisting of
two protons and two neutrons. Beta particles are either energetic electrons
or positrons. Gamma rays are energetic photons (electromagnetic radiation).
QUESTION:
When we heat a metal, the positive kernels begins to vibrate.Will this vibrations produce electromagnetic waves ?
ANSWER:
All objects are continually radiating (and absorbing) electromagnetic
radiation. Until they get very hot, however, they do not radiate in the
visible range.
QUESTION:
Imagine we are in a space craft which is moving with a constant velocity in empty space. If we are not influenced by any gravitational forces, and if we restart the engine, will it be accelerated ?
ANSWER:
Yes, of course. This is what classical physics is all about—an
unbalanced force causes an acceleration.
QUESTION:
Say there is a father and son. The father is the first astronaut to attempt to "time travel" into the future by flying his rocket around a black hole at extremely high velocities, so that for a given period of time (say an hour) it is a lot longer on earth (say 10 hours). My true question is, if the father could somehow communicate to his son in real time, what would this conversation sound like? Would the son hear his dad talking extremely fast? or would the distance between them make up the distance in "time travel". If it was the distance that is the factor, what if the dad was on a super train traveling at similar speeds on Earth?
ANSWER:
Below I have copied a figure from my
earlier answer where I talk about
the twin paradox, the situation you allude to in your question. Here there
are specific numbers (given in the caption) to make it concrete. As
explained in the earlier answer, the traveling twin (the father in your
question) takes 6 years to go each way while the stationary twin (son) has
ten years elapse. Each (father and son in your case) sends out one light
pulse each year and by looking at the spacing of those pulses you can deduce
how a conversation would sound. Here is a summary of how each sounds to the
other:
- On the trip out, the father hears the son slowed down by a factor of
3 (2 yearly signals from home in 6 years).
- On the trip home, the father hears the son speeded up by a factor of
3 (18 yearly signals from home in 6 years).
- For the first 18 years, the son hears the father slowed down by a
factor of 3 (6 yearly signals from dad in 18 years).
- For the last 2 years, the son hears the father speeded up by a
factor of 3 (6 yearly signals from dad in 2 years).
Of course, it cannot really be a conversation because of the long transit
times of the signals; rather each is just speaking, reciting poetry or
something. Higher speeds would lead to more extreme numbers but similar conclusions.
Overall, note that the father has aged 12 years while the son has aged 20
years. I always like to emphasize that how time appears to elapse on
a moving clock is not the same as the time which actually does
elapse; for example, during the last two years for the son, the father's
clock looks like it is running faster than the son's whereas it
actually is running slower.

QUESTION:
If I understand it correctly, Hubble stated that the further away a galaxy is from us the higher its red shift and therefore the faster it is moving away from us.
My question is if the galaxy is 5 billion light years away the light we now receive is also 5 billion years old. To me that would indicate that the galaxy was moving away from us 5 billion years ago. How do we know if that galaxy is still moving away from us?
ANSWER:
We do not know what the galaxy is doing right now. Information cannot
travel faster than the speed of light, and so there is no way to know what
it is doing right now. We can make a very intelligent guess based on the
systematics of many galaxies at different differences, but we cannot "know".
QUESTION:
Is it possible that the earth and everything in the universe has mass just because they are moving?? How is it possible to know that a spacecraft in space is still or not if everything else in the universe is in motion??
Is it possible that the speed at which we (humans) perceive time depends on the intelligence of humans?? Could it differ based on individual IQ? And is it possible to disprove this??
ANSWER:
No, that is not possible because "moving" has no absolute meaning. This
is one of the fundamental cornerstones of physics, both classical and
relativistic. If you find the laws of physics (mechanics, electromagnetism,
etc.) in one frame of reference, then any other frame of reference
which moves with constant velocity relative to yours has exactly the same
laws of physics. So there is nothing which defines what "still" means.
Regarding your second question(s), physicists have no interest in how time
is "perceived". We define what we mean by a time interval; how it appears or
is perceived is a subjective thing which has no quantitative value for a
scientist. (Well, if a psychologist is a scientist, she might be
interested!) A time interval is the difference between two time measurements
at the same point in space; length is the difference between two position
measurements made at the same time.
QUESTION:
I recently read in the NY Times Science News section that a groundswell of physicists are challenging the law of gravity, saying what we are really observing is ENTROPY (disorder) when an object drops. What say you?
ANSWER:
I read that and it was interesting. Let me give you my overview, from
the perspective of a nonspecialist in the field of gravity. For more than
200 years, gravity was thought to be understood, F=-GMm/r2,
à
la
Isaac Newton. Then, in the early 20th century (ca. 1918), Albert
Einstein published the theory of
general relativity which gave us a much deeper understanding of gravity
in terms of the warping of space time by mass. But, as the 20th century
progressed, quantum mechanics was developed to great success; it seemed that
all fields needed to be "quantized" at small distances, and so it was
natural to seek a theory of quantum gravity. To this day, there is no
successful theory of quantum gravity. Hence, gravity continues to be one of
the hottest areas of physics and the thermodynamic view of gravity, very
nice, is one of many attempts to better understand this rich field (the
proponents can hardly be described as a "groundswell", however!) To further
muddy the gravitational waters, the recent "discoveries" of dark matter and
dark energy are still not understood. There are lots of ideas of what they
are, but my own feeling is that, until somebody starts actually observing
and measuring a new kind of dark matter particle, they are possible symptoms
that we do not understand gravity as well as we think we do.
QUESTION:
Why do charges reside on the surface of a conducting sphere? Why not inside it? Do charges gained by a conducting sphere not distribute equally all through the body?
ANSWER:
The definition of a conductor is that electric charge inside is free to
move. For electrostatics, all charge at rest and in equilibrium, this
implies that the electric field inside a conductor must be zero. Any charge
inside a conductor will cause there to be an electric field; only by having
charge on the surface can you find a solution where there is no field
inside. You can have charge inside a conductor, but it cannot be static.
QUESTION:
say we have a room that the length from wall to wall is the distance that light can travel in 2 seconds. on one side we have a flashlight. we flip it on for only a second would the light hit the farthest wall or would the light only reach the middle?
ANSWER:
Your room is 2 light seconds long. You create a pulse of light waves
which is 1 light second long and which travels toward the other wall for 1
second and then illuminates it for 1 second.
QUESTION:
I thought Specific weight = density x acceleration of gravity.
Why do I keep seeing the same values for specific weight and density for water, i.e. 1000 kg/m3 or 62.4 ibs/ft3?
ANSWER:
Your definition is correct, it is weight/volume=mass density times g.
So, wherever you see 1000 kg/m3 is wrong; this is a mass density.
62.4 lb/ft3 is correct since weight may be measured in pounds.
Specific gravity is density/density of water, so specific gravity of water
is 1.
QUESTION:
I was watching the movie Open Range yesterday and there was a scene from the movie where a guy shot his gun at another man and the man who got shot went flying 10 feet back. My dad says the shooter should have also went flying 10 feet back according to Newton's Law because every actions has an equal and opposite reaction. Does size and weight of either man matter in how far either one would have flew back? Could the one being shot fly back further than the shooter if he was a smaller man?
ANSWER:
Just Hollywood drama! If the gunner did not jump back similarly, the
gunned should not either. I did a quick calculation and found that the
recoil should be about 0.04 m/s for a typical bullet hitting a 200 lb man.
The recoil from a typical hand gun as well as the recoil of the victim is
negligibly small.
QUESTION:
what if you have a cart that is going up an inclined plane, and then it comes back down due to gravity; is the acceleration the same?
ANSWER:
Only in the ideal case of no friction. If there is friction, the
frictional forces flip directions depending on up or down whereas other
forces do not. So the net force along the incline will be different in the
two cases leading to different accelerations.
QUESTION:
Hi, I am a high school senior learning about the Biot-Savart Law. However, that law only applies for circuits but I was not taught any expression for permanent magnets. I have done some research on the Internet, but I have not found anything. I am curious to know if there is any formula for magnetic field strength in permanent ring magnets as a function of distance away from the center.
ANSWER:
Every permanent magnet may be represented by an equivalent distribution
of currents, but that depends on how the magnet is magnetized. So, the
answer to your question is that, no, there is no handy-dandy expression you
can use to get the field. Qualitatively, what I mean by magnetization is the
following. A permanent magnet may be thought of as a large number of aligned
tiny (atomic size) bar magnets. So, one way you could magnetize a ring would
be for all the north poles pointing away from the axis. Another way would be
to have all the north/south poles pointing parallel to the axis with all the
north poles pointing in the same direction. You can see, I am sure, how
these two different magnetized rings would have very different fields. You
need to check with the manufacturer to see what your particular ring
magnet's field is like.
QUESTION:
Does light produced by sun and that hits the surface of the earth, come from a specific section of the sun's surface. Or does the earth receive light from every area of the sun that faces the earth.
ANSWER:
You see light from the whole side of the sun facing us. If you did not
receive light from a part of it, you would not see it at all. Each point on
the surface acts like a point radiating light in all directions out.
QUESTION:
Quantum Mechanics says that until we make a measurement of a particle (an electron, say), we really only know the probability of where it's located and, in addition, there is a non-zero, however small, probability of it being anywhere (although some locations will definitely have larger probabilities). Hope I'm making sense so far. Now, it occurred to me that when I see the trackings of a cloud chamber, don't we "know" then where the particle was over a period of time? Is the cloud chamber really, in some sense, taking a measure of the particle, thus collapsing the wave function? If so, since we see it over a course of time, is it making continuous measurements?
ANSWER:
"Collapsing a wave function" usually refers to putting a quantum system,
originally in a superposition of many possible discrete states, into a
single one of them. Position is not "a discrete state" since you cannot put
the electron to a perfectly precise position because of the uncertainty
principle. What you are doing with a cloud chamber is making succesive (not
continuous) position measurements but even this is not what is happening
because it takes some time for the condensation on the ion to occur so the
electron will be long gone before you see a place where it was. At best,
this just lets you visualize where (roughly) the electron was as it went
through the chamber. If you put a magnetic field in the chamber and measure
the curvature of the path, you can deduce the momentum of the electron.
Rather than thinking of "collapsing" the wave function, I would think of
"focusing" it. Before I made any measurements, I was totally ignorant of
both the position and the momentum of the electron; after I watch its track
in the cloud chamber, I now have a better idea of its position and momentum.
QUESTION:
why does the golf ball whitch weighs about 18 times more then a ping pong ball fall at the same times or other words hit the ground at the same time if you drop them from the same distance
ANSWER:
Actually, a golf ball and and ping pong ball will likely hit the ground
at noticeably different times if dropped from a height of more than a couple
of feet. You have been told that the acceleration due to gravity is the same
regardless of weight; see my earlier explanation
why this is true. But, if there are other forces on the balls, they might
have different accelerations. One force which is always present when an
object moves through air is air drag. There is an
earlier answer where I discuss the nature of air drag for balls. If you
read that, you will see that when there is air drag, which gets bigger as the
object goes faster, the ball will eventually stop
speeding up and just drop with constant speed; that speed is called the
terminal velocity and does depend on the mass. I did some rough
calculations and found that the terminal velocity of a golf ball is about 20
m/s and the terminal velocity of a ping pong ball is about 5 m/s. It turns
out that it only takes a freely falling (with negligible air drag) dropped
object about a half second to reach 5 m/s and it does so after falling about
1 meter. So, dropping the two balls from more than a meter or so will result
in the golf ball winning the race to the ground. Incidentally, the terminal
velocity also depends on how large the object is and so you cannot simply
assume that the more massive will win. A parachute, for example, will have a
much bigger mass than a golf ball but will surely lose a race to the ground.
QUESTION:
Do all particles decay? I understand that some, e.g., the proton, have very long expected lives. But are there any particles that are known (to the extent that theory can know these things) not ever to decay? What about quarks and photons?
This site says that guage and higgs bosons are stable. Does that mean that they never decay?
A related question is whether there are any particles that are indestructible, i.e., no matter how much energy is applied to them, they can not be forced to fragment into components or combine with something else and in doing so lose their identity?
ANSWER:
Electrons do not decay. Photons do not decay. Protons do not decay
(although we are not really sure about that). I do not think positrons
decay. Yes, stable means they never decay. Just because a particle is stable
does not mean you cannot destroy it or make other particles from it. A
simple example is bringing a positron and electron, both stable, together;
you end up with two photons (usually).
QUESTION:
Where is the proton?
When using an accelerator to fire a proton into a target does the proton or just the energy of the proton get delivered and the actual proton stay in the accelerator.
ANSWER:
The proton and its energy are "in the same package". What happens to the
proton itself depends on how it interacts. The proton can just scatter off
something elastically, that is it just bounces off with most of its energy;
the proton can interact with a nucleus and excite it and leave the scene
with some of the energy it came in with; the proton (if sufficiently
energetic) can create new particles and disappear itself (or not); the
proton can get absorbed into some nucleus and just disappear; the proton can
fly right on by and do nothing (this is what happens in the overwhelming
majority of the time). In most accelerators, the beam is deflected out of
the accelerator and focused on the target. None of these protons ever get
back into the accelerator. In a collider accelerator, the particles which do
nothing may be recirculated and come back later for another pass.
QUESTION:
this is what it said about radio waves on
wikpedia "although commercially important uses of radio use only a small
part of this spectrum" what is the small part of that spectrum between
30kHz and 300 GHz that is most commonly used?
ANSWER:
Frequencies used is not really physics, it is just how the use is
allocated by government agencies. Here is a
chart which shows allocated frequencies.
QUESTION:
My question is about gravity...
In the depictions I have seen of the Einstein model of gravity, planets and stars are shown as depressing a plane of time space into a well like depression into which other objects tend to fall
I am ok with this depiction
However, it seems to make the assumption that space is a plane and has only two dimensions
When I observe the universe, I see three dimensions
It would seem to me that these "gravity wells" should exist in three dimensions not the two generally depicted
In the two dimensional illustrations, these gravity wells seem logical and simple...the sun for example presses down to form a depression in the two dimensional plane and the earth falls in towards it in an orbit
But space is not two dimensional
These "wells" or depressions should exist in an infinite number of orientations in a three dimensional space
Why are they only shown as if the fabric of space is like a sheet of paper, in two dimensions and not in an infinite number of orientations as would be the case in a three dimensional space?
ANSWER:
My stock answer to this kind of question is that the "trampoline
illustration" of deformed space-time is meant to be a cartoon to illustrate
the idea, not an accurate rigorous representation of the theory of general
relativity. You must not take it too seriously or literally. It is also
practically impossible to draw a picture of deformed three-dimensional
space. To draw deformed 2-D space is easy because you use the third
dimension to show the deformation; to draw a deformed 3-D space would
require a fourth spacial dimension which cannot be drawn.
QUESTION:
I have searched on the internet and can't seem to find an answer to what I thought would be simple aerodynamic questions.
The first one is, unlike a regular airfoil surface, why does a spinning horizontal cylinder produce lift? I've seen several articles mentioning this effect, but without explanation of the dynamics. I understand that moving air produces a low pressure over an object, but since a cylinder is spinning and air is moving all around it on all sides, wouldn't the pressure differential be canceled out? If it is spinning clockwise, as the right side is turning downward, the left side is turning upward. I would think this would cancel any lifting effect.
Also, would a sphere that is spinning, not top to bottom, but around like a top, produce lift or low air pressure at the top? Does the orientation of the spinning matter for lift effects, as long as the surface is moving?
ANSWER:
The cylinder must also be moving forward through the air. There is a
nice NASA
article about this "wing". Now that you know how it works, you see that
a sphere spinning on a vertical axis would not work to give lift but, if
moving through the air also, would result in a sideways force (a slider in
baseball, I believe). Yet another example is if you put topspin on a tennis
ball, it curves down.
QUESTION:
I know that the electromagnetic field propels electrons around the nucleus and that the strong force binds the atomic nucleus together. BUT, are electromagnetic particles found INSIDE the nucleus?
ANSWER:
It is really not correct to say the electromagnetic force "propels" the
electrons in the atom; but, let's not split hairs, the electrostatic force
binds the atom together. The nucleus is composed of protons and neutrons,
the protons having positive electric charge and both neutrons and protons
having magnetic moments (they look like tiny magnets). Because the strong
force is much stronger than the electromagnetic force, it holds nuclei
together in spite of the fact that the repulsive electromagnetic force is
trying to blow the protons apart.
QUESTION:
Ok. This question has been bothering myself, my Dad and a couple of my friends for weeks now, and we just can't seem to come to a logical answer. So here goes:
You are travelling in a car at 100mph. You have a gun which launches the bullet at 100mph. Firing the gun directly forward (the direction you are travelling) causes the bullet to move at 200mph (This bit we think we got right... please correct us if we are wrong).
However. If you fire the gun directly behind you, whilst directly inline with an observer standing outside the car. To the observer... what happens to the bullet? We reached many conclusions, one being that to the observer, the bullet hangs in mid air until dropping to the ground as its acceleration finishes... This seemed logical... But wrong... which just confused us more...
ANSWER:
It may seem wrong, but the bullet fired backwards will drop straight to
the ground as seen by a stationary observer. This is what is called Galilean
velocity transformation. You can see more detail in my
answer to another recent question
nearly identical to yours.
QUESTION:
What are the bases that scientists used to divide the electromagnetic spectrum into these bands ? I mean it is obvious that the visible light is the part of the spectrum that human eyes can perceive, but what made physicist define a boundary between ultraviolet rays and x-rays? or between x-rays and gamma rays ?
ANSWER:
There is nothing profound here. There are no hard boundaries between
these classifications and they are mainly semantic and qualitative
groupings. Historically, UV is just beyond (shorter wavelength) our vision
and usually this radiation comes from dexications of atoms just like visible
light normally does. When Roentgen discovered more energetic x-rays, which
are still atomic deexcitations of atoms but involving the very innermost
electrons, it was natural to give this region a new name. And, when it was
discovered that
γ-radiation from nuclei was just another higher-energy electromagnetic
radiation, they were given a new classification. There is definitely overlap
between categories; for example, some radiations called γ-rays by nuclear
physicists have less energy than some radiations called x-rays by atomic
physicists.
QUESTION:
I have a question for a physicist about particle-wave duality of matter. If you fire one electron on at a time, does the electrons still exhibit their wave nature?
ANSWER:
Absolutely yes. Electrons, one at a time, just like photons one at a
time, will exhibit wave properties if you look for them. For example,
electron diffraction can be observed by sending in electrons one at a time,
although you will have to wait a long time to see the pattern build up. In
essence, the electron interferes with itself.
QUESTION:
The office has a little on going arguement about force on a lever. Does it take more force to break a long stick or short stick. If a snowboarder hit a jump and came down on his tail that had 58cm between the end and his binding and another dude hit the same jump at the same height with the same weight and board and every thing is exactly the same, but the second guy come down on the tail that only has 38cm between the end and his binding; which board would break?
ANSWER:
One's first reaction is to say that the long tail will break more easily
because we all know that it is easier to break a long stick than a short
one. That is, the force required to bend a long stick far enough to exceed
the strength of the material is less than for a short stick. I think back to
breaking up sticks for a camp fire by wedging a long branch in the fork of a
tree and pushing on it—it gets harder
and harder as I break more and more off.
But there is a lot more to this problem than that. When you state "every
thing is exactly the same", it is easy to get deceived as to what that
actually means. Until the time of impact, everything is the same, but then
things get very different. What is going to happen when the tail hits the
ground is that it will begin to bend, acting like a spring. But, the
short-tail board will be very stiff, act like a stiff spring and the
long-tail board will act like a "squishy" spring. What this means is that
the short tail board will stop the downward motion in a shorter time than
the long-tail board. Now, let's review Newton's second law: the force you
experience is proportional to the acceleration you are subjected to. When
you jump 20 feet to a concrete floor it hurts more than if you jump onto a
matress; the reason is that the time it takes you to stop is much longer
when hitting the mattress, your acceleration is smaller, so the force you
experience is smaller. We can therefore conclude that, during impact, the
short-tail board will experience a greater force during impact; it could
therefore very well break more easily. From here it becomes a materials
engineering problem—what is the
board made of, what are the properties of that material, what is the
snowboarder's weight, what is his velocity at the moment of impact, etc.—to
determine which, if either, will break first.
QUESTION:
Why is it important for you to have a “feel” for length, time, and mass?
ANSWER:
Sounds like you are a student in my class! The whole of physics is based
on these three concepts. Everything we encounter in classical (Newtonian
mechanics and Maxwellian electromagnetism) can be expressed in terms of the
three fundamental quantities. It turns out that our intuitive "feeling" for
these is wrong, they are interconnected and not universal; this is what we
learn when we study the special theory of relativity. As long as speeds do
not become comparable with the speed of light, though, you intuitive
feelings for what these three quantities are is valid to a superb
approximation.
QUESTION:
I found this question in a chat forum in the "Games" section. Apparently, the answers are 200 mph and 0. 100 mph train motion + 100 mph throwing force of ball = 200. Ok, I can see that, but 0 for the second part? Why would a ball appear to be floating in one spot then drop to the ground to a bystander? Once I released the ball, why does it matter if I'm moving or standing still?
Here is the question posted in the forum. I did a copy/paste so I wouldn't change the wording.
"If you are on a train that is traveling at a speed of 100 miles per hour and at the front of the train you throw a ball. the ball is leaving your hand at a speed of 100 miles per hour going ahead of the train. to a man that is not on the train but standing by the way, what speed is that ball passing him?
reverse the situation, the train is still going at 100 mph but this time you are at the back of the train and you throw the ball the opposite direction and it leaves your hand at 100 mph. to the man on the road what speed is that ball doing?"
ANSWER:
Maybe you would find this more plausible if you imagined the train
moving at 5 mph and you walk backwards in the train with a speed, relative
to the train, of 5 mph. If your friend were standing on the platform
watching you he would see you stay right in front of him. Can you see this
better? It is exactly the same idea.
FOLLOWUP QUESTION:
Actually no I can't see it better. Why would my friend see me right in front of him if Im walking backwards in a moving train?
What is the math behind this?
ANSWER:
Try this: there is a conveyer belt traveling north 5 mph, so if you
stood on it you would go north 5 mph. Now you start walking (on the
conveyer belt) south with a speed 5 mph. If the conveyer belt were to
stop you would travel south 5 mph because of your walking, but if the
belt moves, you stand still relative to the ground.
[The math is as follows: vAB means the velocity
of A with respect to (wrt) B. Then vAB=vAC+vCB;
this is called the velocity addition formula. Here is your original
specific case: A=ball, B=ground, C=train. Then the velocity of the train
wrt the ground is vtrain,ground=100; if the ball is
thrown in the same direction as the train is going, the velocity of the
ball wrt the train is vball,train=100; so, the
velocity of the ball wrt the ground is vball,ground=vball,train+vtrain,ground=100+100=200.
If the ball is thrown in the opposite direction the train is going, the
velocity of the ball wrt the train is vball,train=-100
because velocity is a vector quantity and we have chosen the direction
the train is going as postive; so, the velocity of the ball wrt the
ground is vball,ground=vball,train+vtrain,ground=100-100=0.
You asked for it!]
QUESTION:
According to Bohr's atomic model, each shell is associated with a definite amount of energy and the energy of an electron remains constant so long as it stays in the orbit. But how? How can the energy of moving electrons be constant? If the electrons are moving? Why not is energy continuously lost?
ANSWER:
Well, your question is a good one, but I am not sure about why you are
asking it. You seem to imply that a moving object cannot have constant
energy. How about the earth orbiting the sun? It has constant energy. So an
electron in orbit should also, right? The difference is that the electron
has an electric charge and electric charges radiate energy away if they
accelerate (that is how transmitting antennas work). An object which moves in a circle is accelerating, even if its
speed is constant, because its velocity is always changing direction. So the
question is why does an electron in a Bohr orbit not radiate? But that is
the triumph of the Bohr model—to
conclude that certain special orbits simply do not radiate; it is just a
postulate that orbits with particular angular momenta are stable.
Subsequently, when models became more advanced, we were able to understand
it in other ways. One of the best is using the deBroglie hypothesis which
asserts that particles are waves. A Bohr orbit is stable is it is a standing
wave, that is exactly an integral number of waves can fit in one
circumference.
QUESTION:
I am an avid runner and a sports medicine doc. Common "wisdom" is that you burn the same number of calories per mile walking or running. The explanation given is that since it takes longer to walk a mile, more time is spent burning calories.
I intuitively disagree, and here is my reasoning based on physics:
Calories are burned by the body as it performs Work--muscle contraction, respiration, cardiovascular output, etc.
Work=ForcexDistance
The distance is equal but it obviously takes more effort or Force to run the distance. Force=Mass x Acceleration. The body mass is the same but the acceleration of the heart, lungs, and skeletal muscles are much greater during running, therefore you should burn more calories for a given distance and time is not a factor.
Am I correct?
ANSWER:
I will not argue that you are right or wrong in terms of the final
conclusion. However, your reasoning is flawed for the following reason. In
each case, work is being done at a different rate. But if the rate is low
and the time is large, as for the walker, the net work done can be greater
than or equal to the net work done by the runner where the rate is large but
the time is short. Obviously, you need to know rates and times to make a
sensible comparison. The assumption made in the "common wisdom" assertion is
that the rate at which work is being done is proportional to the rate at
which distance is being covered (also known as speed). I have no idea to
what extent this is true, but it sounds like a pretty realistic first
approximation to me. Applying physical principles to biological situations
is often very tricky. An example is simply holding up a weight in an
outstretched hand. Physics would say no work is being done because the force
on the weight is not acting over a distance; you and I both know, however,
that sugar is being burned to provide the energy necessary to hold this
weight stationary. What is going on there, as I understand it, is that the
muscle fibers in your arm are continually slipping and retensioning thereby
doing lots of little parcels of work to hold your arm steady.
QUESTION:
Why as you get farther from the Earth's equator does your weight not increase or if you stand on the Earth's rotational axis, why are you not crushed by the gravity. I would think one's centrifugal force or inertia to fly off the earth would decrease in proportion to the distance from the equator and aproach the axis but the gravitational pull would remain the same.
ANSWER:
There is an effect on your apparent weight due to the earth's rotation
and your apparent weight decreases as you move away from the equator, just
as you surmise. However, because the earth is so large and rotates so
slowly, the effect is tiny, less than
½%. So it would take a very careful measurement to see an apparent
weight difference at the equator and the poles.
QUESTION:
I recently read that if a spacecraft could travel very close to the speed of light for a period of 7 years approximatly 500 years will have passed on earth resulting in foward time travel. Doe's this mean that a craft sitting stationary in relation to the earth in space,(for a much longer time) would result in backward time travel since the earth's speed would slow relative time on earth?
ANSWER:
No, it does not mean that. Once the two are at rest with respect to each
other their clocks run at identical rates. I suggest you read my earlier
answer on the twin paradox and on
the situation you describe, going out and stopping.
QUESTION:
When different types of balls are launched, which will go the farthest
ANSWER:
The force of air drag can be very complicated as you can see from many
of my earlier answers. However, if
you want to compare balls of different sizes and masses moving through air
near the ground and with speeds less than a few hundred miles per hour,
there is a very useful approximation for the drag force: F≈¼πR2v2
where R is the ball's radius in meters and v is its speed in
meters/second. (Note that πR2 is just the ball's cross
sectional area, so the force is proportional to the area times the square of
the speed.) But, since what matters is the ball's acceleration (the rate at
which its speed changes), we can use Newton's second law, F=ma where m
is the mass in kilograms and a the acceleration in m/s2.
Equating the two expressions for F, a=-¼πR2v2/m.
I have added a minus sign to make clear that the ball slows down as a result
of this force, a is a "deceleration". So, for example, for two balls of
roughly equal size but different masses (a baseball and a tennis ball,
perhaps) launched with identical velocities, the baseball will go farther
since it has a larger mass and hence a smaller deceleration. On the other
hand, two balls of comparable mass but different sizes, when launched with
equal velocities, would have the smaller ball go farther. It is important
that the balls be launched with equal velocities; for example, if you threw
a tennis ball and a baseball as hard as you could, the tennis ball would
have a larger velocity to start with, an unfair advantage; it is hard to
make comparisons if you do not control some of the variables. Still, common
sense tells us the answer sometimes; for example, a basketball will go
farther than a balloon of equal size regardless of how hard you threw the
balloon. Of course, balls with both different sizes and different masses
would have to be compared more quantatively. A bowling ball with a radius of
0.1 m and a mass of 7 kg going up against a golf ball with a radius 0.04 m
and mass 0.05 kg: the deceleration of the bowling ball would be 0.0011 m/s2
and the deceleration of the golf ball would be 0.025 m/s2. The
bowling ball would go farther because it slows down at a slower rate. (Note
added: this would have to be a smooth golf ball; the dimples are designed to
reduce drag and so our equation for drag would not be correct.)
QUESTION:
if an object was sent in to the future instantaneously lets say one minute would we ever be able to catch up with it or would it always remain one minute ahead? If it takes us one minute to catch where it was sent then that object would've already been there for 1 minute as well, causing it to be 2 minutes ahead of its original time and constantly one minute ahead of the source.
ANSWER:
We can catch up with him but he cannot come back to our time. The only
way we know how to time travel is to move at a high velocity and then stop.
At the time we stop our clock will be behind a stationary clock we left
behind, in other words we are in the future of the frame we left behind. If
the clock we left behind now takes a trip identical to the one we took, when
he stops he will be with us and our clocks will be again in agreement. You
might understand this better by looking at an earlier
answer. (By the way, you can't travel to the future instantaneously, but
I do not think that is what you are most interested in here; rather you want
to know, if somebody is in the future, whether we can get there too.)
QUESTION:
My co-workers and I are having a discussion about age vs time. Some of us acknowlege time dialation, one however, does not. We use the example of two 10 year old twins. 1 twin goes off to outer space near the speed of light for 10 years. When he comes back to Earth the twin who went to outer space is 20 years old, however, the twin on Earth is say 90 years old. My question to you is time and age directly related? Will the 20 year old twin look like a 20 year old person or will he only be considered 20 years old while having the body of a 90 year old?
ANSWER:
Biological systems are just clocks, they are just not as accurate as
mechanical clocks. Still, nobody lives past 120 so they are a clock of
sorts. Also, nobody would argue that a body which aged, relative to a
mechanical clock, 20 years could not be distinguished from a body which
aged, relative to a mechanical clock, 90 years. If the traveling twin
carried a mechanical clock with him and it went forward only 20 years, he
would be a young man at the end of the trip. If his brother's mechanical
clock went forward 90 years, he would surely be an old man. I recommend two
of my earlier answers to be read by your doubting Thomas: the
light clock and the
twin paradox.
QUESTION:
If a fly and a Train are travelling towards each other and collide head on. Does the train stop for an instant before continuing? At some point the fly must stop going forwards for the train to send it backwards!!! If you do this with a car, it must stop at some point before it changes direction!!
ANSWER:
The train definitely does not come to rest for an instant. The fly does
because its velocity changes direction during the collision but the train
does not. So, the fly experiences a large change in velocity in a short time
which means a huge acceleration. Using Newton's second law, F=ma, a small
mass times a big acceleration is a modest force, but likely big enough to
destroy a fly; bye bye fly. The train experiences a tiny change in velocity
in a short time but exactly the same force as the fly did. Because the train
has a huge mass, it experiences virtually no acceleration.
QUESTION:
what does it mean for a picture of the dead to fall to the floor?
ANSWER:
It means that the force of gravity on the picture was larger than the
force which previously held the picture on the wall. I am not a psychic,
by the way, I am a physicist.
QUESTION:
I was watching a TV show on dark matter, and can't seem to wrap my head around it, if it is real shouldn't we be able to see it at the space station or measure it in deep mines? What if ,once you get to certain mass, space time does not just warp it creates a crater, with sharp drop offs? Sort like a hunting bow at first it is hard to pull but once get to a certain point it folds over. So when your in the creator, gravity behaves normal like our solar system , If a kid throws a paper airplane on a school bus that is traveling 55 mph; if you are out side the bus you can say the airplane is traveling 57 mph but if your inside the bus its only going 2 mph. Dark matter does not seem real, its like a god factor we create it to make since of the world around us. I don’t get it.
ANSWER:
Wow, your question is all over the place. Here is the thing about dark
matter: it is very diffuse, that is, there is generally very little of it in
a cubic meter of space, but it occurs all through the universe where there
is almost no normal matter and ends up dominating the mass of the universe.
Well, that is the party line anyway. I actually am not convinced that dark
matter exists and feel that we do not understand gravity as well as we think
we do. I am perfectly willing to change my mind when convincing direct
experimental evidence for dark matter is found.
QUESTION:
I'm currently having a discussion with someone regarding the spin of a bowling ball and how it effects it's degree of hook (neither of us are physics students nor have we taken a physics class).
My question to you is as follows: It stands to reason that if you throw a bowling ball with complete backspin (no sidespin whatsoever) that it will travel down the land and depending on whether the lanes are oily it will either skid with that backspin until hitting the pins or it will, on dry lanes, stop spinning backward and develop a forward roll continuing to travel in a straight line from where you released the ball.
If you impart some side spin to go along with the back spin, will the ball hook at all in the direction of the side spin? You don't have to be a physics expert to conclude that yes, the ball would move in the direction of the side spin.
Now, my primary question is, if you threw a ball with a certain amount of revolutions (say 15 or so) and imparted a spin that was exactly between a full forward roll (no side spin) and a complete sideward spin, it will hook a certain amount in the direction of the side spin before it reaches the pins. **If you throw the ball with the same degree (amount;strength) of spin, but instead have it halfway between a full backspin and a full sidespin, will it hook further in the direction of the spin than it would in the previous 'forward-spin' example?
I hope you understand what I'm trying to ask you, I doubt that I worded it very well.
ANSWER:
Let's first note that we need to specify the spin by an angular
velocity, so many rpm (revolutions per minute) or revolutions per second or
whatever. Next, we need to ask what each kind of spin does. A spin causes a
force in some horizontal direction because the sliding of the ball on the
lane results in a frictional force. A ball which has purely top spin
(forward spin as you call it) will speed up in the direction in which it is
moving. Similarly, back spin causes the ball to slow down, clockwise spin
(from the bowler's perspective) causes the ball to curve right, and
counterclockwise spin causes it to curve left. In all cases, if the alley
were long enough, the ball would eventually stop slipping and simply roll in
a straight line. If the ball starts with top spin and left spin it will
curve less over the length of the alley than if it just had left spin
because, since it speeds up, it would have less time to curve. You would get
even more curve if you also had back spin on the ball. It is surely more
complicated than this, but this is the basic physics. I am not sure that I
answered your question.
QUESTION:
I always thought that the energy of a photon was an intrinsic property of the photon, and represented some multiple of a quantum amount of energy (E = hf). But light from a receding star undergoes a red-shift, meaning that the frequency of a photon is a function of the speed of the observer. Two observers moving at different speeds with respect to a distant star see two different frequencies implying that the observed energy for a photon is different. So where did the energy go?
If the light traveling around the universe isn't homogeneous, is the sum total of energy in the universe a function of where you are standing and your relative velocity with respect to some other object?
ANSWER:
Imagine a 2 kg ball moving past you with speed 1 m/s. This ball has a
kinetic energy of
½mv2=1 J. Now imagine running alongside the ball with
a speed of 1 m/s. Where did the ball's energy go? The simple fact is that
kinetic energy is not an invariant quantity, either classically or
relativistically, that is, it depends on the observer. A photon's energy is
purely kinetic since it has no mass. Yes, the energy of the universe does
depend on your reference frame (assuming "the universe" means everything
except you). However, physical laws like conservation of energy
will still be true.
QUESTION:
I was reading through the driver qualification handbook which all drivers need to read before they take on the driver qualification test.
In the book it says:
"Overtaking other vehicles is hazardous. If you misjudge the gap needed to overtake safely you could collide head-on with an on coming vehicle. Head-on crashes are usually very severe as the speed of your car combines with that of the other. For example, a head-on crash where both cars are travelling at only 50 km/h gives a collision speed of 100 km/h – equivalent to driving into a stationary object at 100 km/h!"
Now, wouldn't the energy be divided and only be the equivalent of crashing into a non moving object at 50km/h?
ANSWER:
Here is the way to think about it. What matters is the force you feel.
The force something experiences is proportional to its acceleration, the
rate at which the speed changes. During the collision your speed goes from 50
km/hr (or 100 km/hr) to some constant speed. (Eventually you come to rest
because of friction, but what matters is how fast you are going after the
collision per se has finished, the cars mangled and stuck together.) What is
your speed just after the collision? If the other car has about the same
mass as yours and the opposite velocity, the two cars come to rest just
after the time of the collision; but, if the other car is at rest, the two
cars have a speed of half the speed you came in with. The time which the
collision will last will be very short and roughly equal for the two
situations. So your change in velocity (50 km/hr) for the head-on collision
will be twice as great as for your change in velocity (25 km/hr) for the
collision with the stationary car in roughly equal times. Hence the force
will be twice as great. If you collide with a stationary car while going 100
km/hr, your speed right after the collision will be 50 km/hr so the change
in velocity will be 50 km/hr, the same as the head-on collision. [To
estimate the speed after the collision I have used momentum conservation,
the product of the mass times the velocity does not change. In the head-on
collision the total momentum is zero. In the other case, the mass after the
collision is twice as big so the velocity is half as big.]
QUESTION:
The potential midway between two charges of equal magnitude and opposite
sign is zero. is it possible to bring a test charge from infinity to this
midpoint in such a way that no work is done in any part of the displacement?
if so, describe how it can be don. if it is not possible, explain why?
ANSWER:
It is possible. The plane which is the perpendicular bisector of the
line connecting the two
charges has electric field everywhere normal to it. It therefore takes zero
work to move a charge around on that plane so it is an equipotential plane
at zero potential extenting all the way to infinity.
QUESTION:
I have been thinking about this for quite some time and have searched the internet for anything like it and have found nothing. If an orbit is perpetual, as i have read, why has it not been looked at as an energy source?
ANSWER:
An orbit is "perpetual" only if left alone. If you take energy away from
an orbiting object, its orbit will decay and it will eventually drop out of
orbit.
QUESTION:
What would happen to the earth's orbit is the sun were to change it's mass? I understand what would happen to the period if the semi-major axis remained the same or what would happen to the semi-major axis if the period remained the same, but presumably changing the mass of the sun would affect both these things and create a completely new orbit. But how do you determine the effect it would have?
ANSWER:
Assume that the earth is in an approximately circular orbit. If the sun
became more massive, the earth would be going too slow for a circular orbit
so its orbit would become an elipse with the earth at the aphelion (furthest
point to the sun); so the semimajor axis would be smaller and the period
smaller. If the sun became less massive the earth would be going too fast
for a circular orbit so its orbit would become an elipse with the earth at
the perihelion (nearest point to the sun); so the semimajor axis would be
larger and the period larger. In my reasoning I have used T=2π√(a3/GM)
where a is the semimajor axis, T is the period, G
is the universal gravitational constant, and M is the mass of the
sun.
QUESTION:
What is fire?does it have a mass?
ANSWER:
Fire is just hot gases undergoing chemical reactions. Yes, gas has mass.
QUESTION:
Let's say that Bob is in a train travelling at relativistic speed. Then, Bob decides to make a cell phone call to his friend Jack, who is at home. Would there be any anomalous occurences during the phone conversation? Or would a cell phone conversation not even be possible at relativistic speeds?
ANSWER:
There are a couple of reasons a cell phone would not work. One is that
there would be a big doppler shift so the signals you actually receive would
not be the frequency your cell phone is designed to receive. Also, we would
have to have cell towers stationed all along your route. But these would not
be insurmountable obstacles and you could redesign the phones and
infrastructure to work under these conditions. (Or maybe just communicate by
radio which is essentially what a cell phone does anyway.) What would then
happen would depend on whether you were going away from of moving toward the
other phone; your question seems to imply you are going away. What both Bob
and Jack would hear is the message from the other slowed way down, and by
equal factors. Also, of course, a conversation would be very difficult
because Bob would be very far away and therefore the transit times of the
signals would be very long. To understand this in detail, study my
earlier explanation of the twin
paradox and focus only on the outward journey.
QUESTION:
If your in a n elevator that is falling, you should jump in the air right before it hits the bottom to survive. Why or why not ?
ANSWER:
It will make practically no difference, you're dead either way. Suppose
you fall from about 20 stories, about 100 m. The speed the elevator would
hit the ground would be about 70 m/s (about 154 mph). How high can you jump?
Maybe 1 m? The corresponding speed would be about 4 m/s. If you jumped an
instant before rock bottom you would end up hitting the ground with a speed
of only 66 m/s (about 150 mph).
QUESTION:
If you made a hole through the centre of the earth large enough for a large round rock and threw that rock into to that hole what would happen when it reached the centre of the earth, I realize it would probable melt but supposing it didn't, an object can not fall up, so what would happen after the object had passed the centre because then it would be falling up?? or would it just stay in the middle??
ANSWER:
Neglecting air resistance, the stone speeds up until it gets to the
center and then slows down until it gets to the other side of the world. You
should read my
earlier answers for more detail.
QUESTION:
Air is thrown on a sail attached to a boat from an electric fan placed on the boat.but the boat will not move.acc. to answer when fan pushes the sail by air,air also pushes the fan in opposite direction.plz explain
ANSWER:
This is a complicated question because the boat and fan are not really
an isolated system. But let's us assume they are. The fan pushes the air
forward and the air pushes the fan backward. Now the air pushes the sail
forward and the sail pushes the air backward. All told, the net force on
fan+air+boat is zero. A simpler example which is easier to understand
because there is not the complicating factor of the air is the following:
you, standing on the deck, push the mast and the boat does not move forward
because you are "part of the boat" and the mast pushes back on you with an
equal and opposite force.
QUESTION:
when a ball is thrown upwards,its momentum first decreases and then increases.is conservation of momentum violated?
acc to answer momentum is conserved.how?
ANSWER:
Momentum is conserved only for systems where there are no external
forces. The ball's momentum is not conserved because there is a force on it,
its own weight (the gravity the earth exerts on it). The momentum of the
ball plus the earth is conserved because, according to Newton's third law,
they exert equal and opposite forces on each other, that is gravity is an
internal force for the earth+ball system.
QUESTION:
how can we make the antimatter.can it be made by moving matter in the velocity of light.has CERN prepared so?
ANSWER:
You cannot turn something into antimatter just by making it go fast. You
can, however, create antimatter by colliding very energetic matter with
other matter. You never make it by itself, though; usually it is produced in
pairs with its normal matter counterpart, for example proton/antiproton
pairs are created at accelerators like CERN. See an
earlier answer.
FOLLOWUP QUESTION:
how fast should it travel?
ANSWER:
It depends on what you want to make and what the type of accelerator is.
The incident particle(s) must have enough energy to create the new mass
and to conserve energy and momentum. For example, to create an
antiproton in a conventional accelerator requires the incident proton to
have a speed of 99.4% the speed of light if it collides with a proton at
rest; most of this energy is "wasted" conserving energy and momentum.
For a proton collider, like the new machine in Switzerland, the momentum
of the system is zero and so much less energy is wasted; that is why we
build colliders. In a collider, each proton must have a speed of about
90% the speed of light to create an antiproton.
QUESTION:
My question is related to gravity and I hope you will be able to answer it.
On a documentary on television (I think it was called Invisible Worlds), I saw that the density of the earth’s crust may be the reason why a person’s weight will vary depending on where in the world he decides to weigh himself. This was apparently established by data received from two satellites following one another while orbiting earth.
I immediately though of my bathroom scale and an effect I noticed once by chance. When I weighed myself on a carpet, I weighed more than when I weighed myself on a tiled floor.
This now suddenly baffled me since I was always under the impression that a surface with higher density will have a stronger gravitational pull.
I searched the internet and found an article by Ian Sample (http://www.newscientist.com/article/dn2462-people-weigh-less-on-a-hard-surface.html) where another physicist, David McKay at Cambridge, decided to get someone to investigate this phenomenon. One of McKay’s students, Jon Pendergast, found that on a hard surface, “the base of the scales bows. This makes the fulcrums at each corner of the scales tilt in slightly, shortening the distance between each fulcrum and the point at which the load pushes onto the lever.
“Put the scales on a deep carpet, however, and the scales sink into it, so the carpet supports the base, which prevents it from bending. This increases the distance between each fulcrum and the point at which its lever is loaded, so for the same force the lever moves further. Even a small increase in this distance can add several kilograms to the weight registered on the display.”
This explanation seemed logical enough, but I decided to test it anyway since I thought I saw another test that Mr Pendergast may have missed in the experiment.
I found a solid board and placed it on two books, forming a bridge of sorts, to test the board’s strength. This board proved to be so solid, it did not even bend slightly under my weight. I then put the scale on it and weighed myself on a tile floor. I then moved the board, with the scale on it, onto a thick carpet and weighed myself again.
To my surprise, I still weighed more on the carpet!
I went to find a water level to make sure that the board was level and that it did not bend. I am thus sure that this has nothing to do with something from below supporting the base of the scale. In addition, the water level remained dead centre during my little experiment.
My question: Is it possible that the lower density of the carpet compared to the higher density of a tiled floor may increase the gravitational pull?
ANSWER: It has been
known since long before satellites that local variations in the earth's
density could affect the acceleration due to gravity and therefore one's
weight. However, this is a very tiny effect because the earth is so massive
(like 6x1024 kg) and close to spherical. The effect is so small
that you could never hope to observe it with your bathroom scale. When you
did your experiment, the rigid board was exactly the same as the tile floor,
a hard flat surface. The mass of the board or of the floor is of no
importance compared to the mass of the whole earth. Read the article you
found more carefully: the fact that the scale reads more on the
carpet is a purely mechanical effect having nothing whatever to do with
gravity. You do not weigh more, the scale is simply making a measurement
error.
QUESTION:
when one moves forward he interacts with the earth. what is the momentum of recoil of the earth? why dont we feel it?
ANSWER:
Suppose you walk forward with a speed of 1 m/s and your mass is 100 kg.
The earth has a mass of 6x1024 kg and so it would recoil with a
speed of v=(1)(100)/6x1024≈2x10-23
m/s. At this speed it would take the earth about 3,000,000 years to move the
diameter of one atom. No wonder we are not aware of the recoil! For all
intents and purposes, the earth's mass is infinite compared to yours.
QUESTION:
I understand that if someone were to fly a space ship at the speed of light for say 8 years (4 out 4 back) due to relativity they would be returning in 80 years our time(these numbers I believe they were given as an example, not as a precise calculation). If this is so, would some who flew jets often travel a few seconds in time every flight? Or more realistically at what speed does any change in time flow begin?
ANSWER:
First of all, you cannot fly
the speed of light and the groundrules
of the site say you cannot ask such questions. But I will answer your
question since the focus is more "at what speed does it matter?" To get
noticeable effects, the clock must be moving with an appreciable fraction (f)
of the speed of light. How big is "appreciable"? The moving clock rate (T'),
compared to a stationary clock (T), is given by T'=T/√(1-f2).
So, what speed would you go to lose one second per hour? 3600/3500=1/√(1-f2),
so f≈0.12, that is about 12% the speed of light. To put that number
in perspective, the shuttle, about the fastest thing around (18,000 mph) has
f≈0.00003 or about 0.003% the speed of light. For everyday life you
are not likely to notice time dilation. But wait a minute…if corrections
were not made for relativity, a GPS would not work at all. A GPS requires
extremely accurate times and without corrections for special relativity and
general relativity, would make very large errors (miles) in calculated
positions. (To better understand time dilation, you might like to read my
earlier answer on the twin paradox.)
QUESTION:
Does the gravity that affects high tide affect how much how much we weigh?
ANSWER:
Tides are caused by the gravity of the moon (and, to a lesser extent,
the sun). Your weight is the force which the gravity of the earth exerts on
you.
QUESTION:
When electric current flows in a wire, is the movement of electrons on the surface of the wire or is the entire wire (interior and exterior) involved?
ANSWER:
Under normal circumstances, current is distributed throughout the volume
of the wire. Only with extremely high frequencies (greater than a few MHz)
is the current pushed out to the surface.
QUESTION:

An old type car antenna, often called whip aerial , moves back and forth when the car is moving but when you speed up it seem to oscillate in figure 8 motion. Why is that?
ANSWER:
Vibrating systems have different modes of vibration. The prettiest
example I could find is some of the
modes of a drum, shown above. A real
drum will have all its infinite modes going on simultaneously but some will
play a more important role than others depending on how the drum is excited.
The leftmost one above is called the fundamental and would be the primary
one if the drum were struck right in the center; the center of the drum in
this case is called an antinode, a place which has maximum amplitude. The
right-most one above is another higher mode which, you will note, has the
center of the drum not moving; this is called a node and would probably not
contribute much if the drum were struck in the center. Your antenna, when
just going back and forth, is mainly in its fundamental mode. But when you go a
different speed you are doing the equivalent of striking the drumhead
somewhere other than its center and exciting a higher mode.
ANSWER ADDED LATER:
I found modes of a beam which should be analogous to your specific
problem. Is the second mode similar to your "figure eight"?

QUESTION:
Mine is but a simple question: what is the name of the theory or general principle relating to the rate of spin on a single axis?
Specifically, I am rewriting a wikipedia stub-article describing a circus act called the "Iron Jaw". It is a performance in which a person hangs from a trapeze only by her mouth.
The performer bites down on an attachment and spins, controlling her speed by alternately elongating and narrowing her body like a pencil to speed up, spreading out her arms and legs to slow down, or curling her body into a ball to both speed up and send her body off-axis as well.
I'm sure it is something simple, covered in my 10th grade physics class, but I can not for the life of me remember what it is nor find the right word combination to google the answer.
ANSWER:
Mine is but a simple answer: conservation of angular momentum.
The angular momentum is the product of angular velocity and moment of
inertia. The moment of inertia depends on the mass distribution of the
object, so when the person sticks out her arms, for example, her moment of
inertia increases and she therefore slows down. Similar examples are seen in
dancers, divers, and figure skaters.
QUESTION:
You know the theory that as light has no mass, it is forced to go "the cosmic speed limit" i.e. the speed of light, can you consider these questions and give an answer if you can or if there is one?
-
Light travels slower through water, glass, diamond etc. than through a vacuum? To move from the higher speed to the lower speed, does it decelerate and over what time span? Does it lose energy in the process and gain it again on emergence back into a vacuum? Or does it just appear to? Is there a time dilation effect perhaps?
- Light has no mass, so supposedly objects that have no mass cannot be attracted by other objects that have mass so how does light bend around a star as observed during a solar eclipse? Is it possible that gravity is providing a similar effect to a lens? i.e. does light travel slower through stronger gravity, this would explain the effect?
- Blue light has more energy photon for photon than say red light? So does blue light travel faster than red light and does this explain why light splits when it goes through a prism? "Gravity waves" may have a large magnitude of wavelength different to say gamma waves so could this explain why these waves are seen to travel so fast? i.e. two massive objects approaching one other, the force of attraction between them increases faster than light propagates (earth orbiting the sun is a good example?)?
ANSWER:
-
The energy of the light is proportional to its frequency which does not
change when it enters the optically dense medium. So no energy is lost
when it slows down. This happens by the wavelength changing such that it
satisfies v=f
λ
where v is speed, f is frequency, and λ is
wavelength. The light travels with a slower speed because of complicated
interactions with the medium, I would not think of there being a period
of acceleration.
The reason it bends is that mass deforms the space around it so the
space is no longer Euclidean. See
earlier answers.
Dispersion, different
wavelengths having different speeds in a medium, is not related to
energy per photon but rather to the electronic structure of the medium.
Gravity waves have never been directly observed let alone their speed of
propogation measured; there is certainly no evidence that gravity (or
anything) travels faster than the speed of light. Many things which work
their way into public popularity (gravitons, worm holes, alternate
universes, string theory, dark matter, etc.) are really nothing
more than figments of our imagination until they are observed
experimentally or are shown to describe nature in unique and correct
ways.
QUESTION:
I have tried to read a physics text book on this subject matter but was hoping to get a layman's term answer that i can understand.
Is the downward (vertical) pressure of water on an object the same as the sideways (horizontal) pressure on an object at the same depth?
ANSWER:
Think of your ear drum as a pressure measuring device. Dive to the
bottom of a 20 foot deep swimming pool. Your ear hurts no matter how you
orient it, up, down, or sideways. Pressure pushes in all directions equally
at a given depth.
QUESTION:
I am studying the laws of free fall and air resistance and I came across a demonstration about a penny and a feather free-falling. Obviously, the penny hits first because of the air resistance of the feather, but in a vacuum, they accelerate at the same rate. So my question is, terminal velocity is achieved when an objects air resistance = the force of gravity, so, is the speed of free fall exponential and therefore unlimited in a vacuum? Could an object accelerate to light speed with a strong enough force of gravity and a large enough vacuum?
ANSWER:
As I showed in an earlier answer,
speed does not increase exponentially; it increases linearly with time and
like the square root of the distance fallen. In principle, if the
acceleration were g for a long enough time, the speed could
approach the speed of light (but,
of course, not "to light speed"). It does get a little tricky, though,
because at relativistic speeds acceleration is not a useful variable and you
have to look at things differently; if you are interested in what happens at
very high speeds, look at this
earlier answer.
QUESTION:
In attempting to determine "G" with a torsion balance, as Cavendish and more recently Gundlach and Merkowitz have done, is there any way of ruling out or guarding against an influence of van der Waals force between masses? After all, isn't it a van der Waals force that would lead two dust particles that might meet in space to cling together and continue to attract other dust particles until the result is what we would consider a sizable mass? Isn't the Earth, after all, just a giant dust-bunny?
ANSWER: (thanks to
L. Magnani)
It depends on what size scales you are talking about, but certainly there is a stage
where vdW produce clumping. But it's at small scales (smaller than pebbles).
If you look at chondritic meteorites, they are a bunch of pebbles packed together
by heat and pressure and chemical reactions (like rocks in concrete). Do a google
search on chondritic meteorites and look at the images of what they look like.
There has definitely been heat and chemical processing going on and they are
the sizes of baseballs to ~ 1 km.
After that, the planetesimals (1 km) collide, and again, heat and chemistry produces
a loose aggregation of stuff.
Once the object is 1000 km or greater, self gravity via gravitational potential energy
is great enough to force the material to melt and reform into a sphere.
So, there's no way the Earth is a giant dust bunny.
I don't see how vdW forces have any measurable effect on big metal spheres.
QUESTION:
while i was reading about newtons first law, a doubt arose. according to newton's first law, we say that a body will be in state of constant velocity or of rest if no force is exerted on it. suppose if i apply a force of 1 newton to a body of 1 kg on a frictionless surface, we can say that the body is moving with constant acceleration of 1 m/second squared . and if i apply a force of 2 newton, we can say that the body is moving with a constant acceleration of 2m/s squared.if i dont apply any force to body, then it does not accelerate. but the statement states that a body will be in state of constant velocity if i dont apply any force. how does a state of constant velocity exist now. if a body is in state of constant velocity, some force has acted on it initially and it has to accelerate. if i dont apply any force it will be in state of rest. now i have a doubt that there is no state of constant velocity itself. if it exists please tell me with what force should it be moved initially so as to be in constant velocity?
ANSWER:
Just because something has constant velocity does not mean it always had
constant velocity. But if it does have constant velocity, the implication is
that there is zero net force on it now; that does not mean it always had
zero net force on it. Incidentally, being at rest is just a special case of
constant velocity (v=0).
QUESTION:
If you have runner who can run at any speed, under the speed of light, with no limitations from drag, friction, etc. is there a speed that the runner can go that he will break the bonds of gravity? Also if centripetal/centrifugal force can simulate gravity, can the runner traveling as fast as he was when he broke gravity's pull(?) or faster create any odd or interesting effects in his body, circle he is traveling in, or anywhere, -when, or -what you can think of.
ANSWER:
Anything which has a velocity greater than the local escape velocity can
"break the bonds of gravity". And it is nowhere near the speed of light
except for a black hole. Your second question has no meaning to me.
QUESTION:
Can something be observed that looks like synchronous rotation, but is not synchronous rotation?
ANSWER:
I don't know what you are asking. A helicopter hovering over my house is
rotating synchronously with me but is not in orbit. Is something like that
what you mean?
QUESTION:
The Shuttle orbits the Earth every 90 minutes or so, and from what I understand it's traveling at approx 18k/hr in order to maintain orbit and "fall" over the edge of Earth as gravity pulls on it.
Question is:
How can a Geostationary satellite exist since it has to be traveling much slower to match Earth's rotation. How does it maintain orbit?
ANSWER:
The period of an orbit depends on its radius. If the orbital radius is
about RE (radius of the earth), the period is about 1½
hr and the speed about 18,000 mph. But, if you go out to an orbital radius
of about 6.6 RE, the period is 24 hr and the speed about
6900 mph. And, if you go out to about 60 RE, the period is
about 28 days and the speed about 2200 mph; must be the moon!
QUESTION:
"In astronomy, of course, looking farther away means looking further back in time." This is related to the statement that everything gets older as you go farther away from us. But since there is not really any "center" of the universe, who is to say what farther away is. If i were on Pluto and I went towards earth that would be saying that earth is older since it is farther away than Saturn.
If i went from Earth and towards Pluto we would be saying that Pluto is older because it is farther away than Saturn.
I think that should make enough sense to get an answer but I was just kind of curious as to what astrophysicists define as "farther" away and where they measure it from.
ANSWER:
I think you are missing the point here. Since it takes time before we
see something because the light needs to travel to us, whatever we see is
what was when the light left it, so the farther away something is the more
in the past we see it. Technically, when you see someone across the room you
are not seeing them as they are but how they were when the light you are
seeing left them. When you see the sun, you are seeing it as it was about 8
minutes ago; so if the sun were to go out, you would not know for about 8
minutes.
QUESTION:
two monkeys of equal weight climb the rope from opposite ends,one of them climbing quickly than the other,relative to rope.rope is passing over pulley.which will reach the first?the answer given is both will reach at same time.but velocity=displacement/time.it means the monkey which has greater velocity should reach first.how both could reach at the same time.no doubt length of both segment is same.
ANSWER:
Each monkey has two forces on her: her own weight and the tension in the
rope. But the weights are given to be equal and the tension on the rope is
the same throughout the rope (assuming a massless rope and a massless,
frictionless pulley). The forces on each monkey are identical. If one monkey
jerks down on the rope so that the tension is greater than the weight, he
accelerates up but the other monkey will experience the same net upward
force and will accelerate up with precisely the same acceleration.
Therefore, regardless of what the monkeys do they must always move
identically because they have identical masses and forces on them at all
times.
QUESTION: 
I teach 8th grade physical science, and we discussed the moon's gravity. One student wanted to know the lightest weight that would fall to the moon's surface. How do I calculate that? And is the low gravity the real reason that there could be no atmosphere on the moon?
ANSWER:
Motion of objects near the moon's surface is much easier to deal with
than for the earth. The reason is the lack of atmosphere. On earth, very
light objects like dust can be held aloft for years by the air; on the moon,
dust will settle on the surface unimpeded. There is no limit to how light a
particle could fall to the ground there. You are right that the low gravity
is responsible for there being no atmosphere, but not simply because the
molecules in the air are too light to fall. If you took one molecule of
oxygen, it would drop to the ground on the moon. But when there is a gas,
molecules are running around with a distribution of velocities (called the
Maxwell-Boltzman distribution (MBD)). Some are very slow, some are very
fast. On the moon, those going fast are going faster than the escape
velocity (the speed necessary for anything to escape the gravity) and they
leave. But now, the rest have to readjust to the MBD and the new fast ones
escape; the process keeps repeating until all of the gas has "leaked" away
from the moon. Interestingly, this is the reason that you find almost no
hydrogen or helium in the earth's atmosphere; the lighter the molecule, the
higher its average speed in the MBD at a given temperature. The figure shows
the MBD for helium at two temperatures. The escape velocity on the moon is
about 2400 m/s, so you can see that there are a significant number of atoms
at 273 K (which is 00C); when those escape, slower atoms have to
move in to take their place, and so on until all have escaped. At higher
temperatures, you can see, the escape rate will be even faster.
QUESTION:
If rising sea levels continue and begin to become a threat to humanity, what is the possibility of piping excess water into space? surely if a long enough hosepipe was created, the vacuum of space would suck water up the tube without need for a pump?
ANSWER:
The maximum height to which a vacuum can "suck" a column of water is 33
feet. Besides, this is a pretty wacky idea for solving this problem! Water
is a precious commodity and, even if it seems like we have plenty right now,
to throw away vast amounts of it just to save coastal cities would be
short-sighted in my opinion.
QUESTION:
My question is, I need to ask about the force of gravity, outr teachers say or we have studied that the gravity is constant i,e. 9.8 m/sec2, But gravity is basically the force of attraction because of the centre of earth then those countries or those places that are near to equator should have more force of attraction than those who are at poles? if it is like that then why do we say that the value of gravity is constant.?
ANSWER:
The earth is approximately a sphere, and so every point on earth is
approximately equidistant from the center. In fact the earth is slightly
oblate, that is it is a little "squashed" at the poles, making those points
closer to the center and so having greater gravitational force. This, though,
is a very small effect and local variations in g are due also to
inhomogeneities in the earth's density and effects due to the rotation.
QUESTION:
My question is about stationary waves. How these waves are formed? How the energy is limited within the region of production? where pressure variation is maximum and where pressure is maximum?
ANSWER:
We call these standing waves. A standing wave is actually two identical
traveling waves traveling in opposite directions. An example is a guitar
string. The way you create a standing wave in a guitar string is to pluck
it. I do not understand your question about pressure.
FOLLOWUP QUESTION:
what are nodes and antinodes? how these are formed? how pressure variatuion occurs at nodes and antinodes?
ANSWER:
In a standing wave there are points where the medium is not moving at
all, called nodes, and points where the medium has maximum motion,
called antinodes. I guess you must be talking about standing sound waves
(like in an organ pipe or other wind instrument) since you keep asking
about pressure. At the nodes the pressure will simply be atmosperic
pressure. At the antinodes the pressure will fluxuate (with the
frequency of the waves) above and below atmospheric pressure.
QUESTION:
A scoter speed on the earth is 100km/hr,friction also acts on between the scoter tyre and the earth.if this scoter is taken in the moon then what will b the speed of the scoter,would it change or not?why?
ANSWER:
It is actually the friction between the tires and the ground which
drives the scooter forward. This force balances the friction in the bearings
of the wheel, the air drag, friction in the motor, etc. to keep the
scooter moving forward at a constant speed. As long as the tires did not
slip on the moon, the scooter would move forward with a bit larger velocity
because there is no air and so no air drag.
QUESTION:
Considering space as the object between things, I am always curious as to what occupies the space between earth, and all other universal objects ?
Is it actually empty space, or is it filled with atoms, protons, nutrons, and other particles that actually unify us with everything ?
ANSWER:
Space is certainly not empty. But, what there is and how much of it
depends on where you are. Generally speaking, there is dust and gas but in
amounts which are hugely below what you would find here on earth. There are
some regions called molecular clouds with relatively higher numbers of
atoms, but still what we would call very sparse compared to earth. And, of
course, the universe has photons zipping through everywhere, and neutrinos,
and who knows about more mysterious proposed dark matter? But, I wouldn't
think of any of that stuff as "unifying us with everything".
QUESTION:
I always hear that gravity is a weak force, typically demonstrated by using a magnet to overcome gravity to lift some object; yet gravity can bend light and a magnet doesn't, The earth is a huge magnet but it's gravity is felt by the moon. How is strength of the force defined for comparisons?
ANSWER:
I always think: "to be able to perceive the gravitational force I need
an astronomical amount of mass, but I can easily perceive an electrostatic
force with a very modest amount of charge." OK, this is a pretty qualitative
and therefore unscientific argument. How about "when two protons interact,
there is a region where the Coulomb repulsion dominates, a region where the
attractive strong interaction dominates, but never a region where gravity
makes the least amount of difference." Still not satisfied? The way
physicists evaluate the strength of interactions is by defining coupling
constants
which are dimensionless numbers whose size indicates the strength of the
force. Roughly they are 1 for the strong interaction; 1/137 for the
electromagnetic interaction; 10-6 for the weak interaction; and
10-39 for the gravitational interaction. You can read where these
come from at this
link.
QUESTION:
I have done a lot of readings about Kinetic Molecular Theory. I am quiet convinced that the theory says in an ideal gas(and I mean strictly ideal gas), the average kinetic energy of the gas particles is proportional to its absolute temperature. But the theory did not show this relation also applies to solid and liquid. Yet many authors seems to agree that that absolute temperature is proportional to the average kinetic energy for all three states. Were they wrong?
ANSWER:
Technically, it is the average energy per constituent rather than
average kinetic energy. When the particles interact, such as in a solid,
potential energy is part of the energy of an atom or molecule. Also be aware
that kinetic energy need not be restricted to translational (½mv2)
kinetic energy but may include other degrees of freedom like rotation and
vibration.
QUESTION:
When an electron absorbs a certain photon, and therefore jumps to a higher energy/shell level, how much time does the journey take?
(I am making the assumption that there is an actual distance between lower and higher energy shells)
ANSWER:
It is all pretty complicated quantum mechanics, but the answer depends
entirely upon what the initial and final state of the atom are.
Incidentally, it is precisely the same problem as the excited electron
dropping back down to the ground state. Such "decays" are always
characterized by a half-life and that is essentially what you are asking me
for; it varies with what the transition was.
QUESTION:
I dont completely understand newton's third law of motion.. It says every action, there is an equal and opposite reaction, but when we apply force to a book, why doesnt the book apply the same force to us? And why are we able to push the book wherever we want, if, according to third law of motion, book should also have an equal reaction force?
ANSWER:
The book does exert an equal and opposite force on you. So, why
does the book move and you do not? There are several reasons. First, you
have much more mass than the book does and so your force on the book has a
much bigger effect than its force on you (Newton's second law, a=F/m).
Second, there is friction between you and the floor which can be much
bigger than the force the book exerts on you, so you do not move; but the
friction between the book and the table is normally less than the force you
apply to it, so it does move. Imagine that the book is nailed to the table
and you are standing on a floor which is very slippery ice. Now, when you
push on the book, it will be you who moves. Or, if you and the book were in
empty space and you threw it (by exerting a force on it), you would recoil
(with a much slower speed) because of the book's force on you.
QUESTION:
How can a planet like jupiter have enough gravity to cause tidal friction on one of its moons to cause volcanic activity. yet doesnt pull the moon crashing into it?
ANSWER:
It makes no difference how strong the gravity is, there will be a
certain speed at a certain distance where a satellite can go into a stable
orbit. So your second question has no relation to your first. The way tidal
friction works is that the near side of the moon experiences a larger force
than the far side because gravity falls off like 1/r2 as
you go away from the source. This difference puts stress on the crust of the
moon.
QUESTION:
If you are in space between galaxy's, are you weightless inside your spacecraft or do you tend to stay near a bulkhead?
ANSWER:
You are, for all intents and purposes, weightless. If much of the mass
of your spacecraft is concentrated in one locale, you would feel a net force
toward it but the force would be so incredibly small that you would not
notice it (maybe it would take ten million years for you to accelerate one
cm toward it).
QUESTION:
given ke=1/2 mv squared
would it not be true that ke increases exponentially as an object falls in an accelerating gravitational pull like a rock falling to earth? in other words, the ke at any point in the fall increases exponentially with as it accelerates...
ANSWER:
You have asked an incomplete question because I need to know whether you
want to know how it increases with time elapsed or with distance traveled.
First, let us be clear what an exponential increase is: if kinetic energy
may be expressed as a function of the form Cat or Cax
where C and a are constants, and t and x are
time and distance fallen, respectively, then it increases exponentially. So,
let's see. I will assume I drop something from rest. Then the velocity is
given by v=gt or v=√(2gx).
So, KE=½mg2t2=mgx; KE increases
quadratically with time and linearly with distance, not exponentially.
QUESTION:
My girlfriend doesnt believe in the possibilty of traveling back in time because she doesnt believe theres anywhere to travel back too. In other words if you did travel back in time your not actually going back in time your going to an alternate universe so there would have to be an alternate universe for every second of the day because yesterday is gone. Is there some way or theory I could explain to her to help her understand in at least the possibility.
ANSWER:
She shouldn't say there is not "anywhere to travel back
to", but rather not "anywhen to travel back to". As far as contemporary
physics is concerned, she is right (not because the past does not exist
somehow, but there is no known mechanism to get there). It is possible to
time travel to the future, though. See my
earlier discussion of the twin
paradox. Alternate universes and worm holes are two speculative ideas
which might supersede currently accepted physics, but they are hypothetical.
QUESTION:
Considering that ether has been long debunked, how do we explain the wave part of the particle / wave duality, doesn't a wave mean a disturbance in some medium?
ANSWER:
Something has to be "waving" but it does not have to be a material
medium. See my earlier
discussion of electromagnetic waves.
QUESTION:
If the earth is rotating on its axis at a speed of 1000 miles per hour, how come we dont experience the movement and only the change of light and darkness. Why would'nt vertigo be the norm? the earth appears to stand still.
ANSWER:
First, we do not experience movement because our whole environment is
traveling with us, including the atmosphere. Note that if you are in an
airplane going with a constant speed of 600 miles per hour you do not
experience motion. The second thing to consider is the acceleration;
anything going in a circle experiences an acceleration. Acceleration is what
makes you queasy on an amusement park ride. But, since the radius of the
earth is so large, the acceleration we experience because of our rotational
motion is very small, in other words our path over a few minutes is just
about a straight line and we experience no significant acceleration.
QUESTION:
Why is it that spaceships need propulsion when there is nothing slowing them down. And if they reached a certain speed then continued untouched by gravity would they stay at that speed forever?
ANSWER:
If you are in truly empty space, no propulsion is needed to maintain
your speed. This is approximately true for all space probes we send to other
planets and beyond, approximately because they are usually far from massive
objects and the space is almost free of gas. Of course, you need fuel if you
ever want to change direction, slow down, correct for the gravitational
effects which are small but not absent, etc. Most of the time, once
the desired course has been set, no fuel is used.
QUESTION:
I've recently been reading a book about physics, and, in one section, they describe how to calculate the exact position of a thrown object (such as a ball) on the y-axis. The mathematical formula that they present, though clear in some ways, is not clear in others. It is: y = vt - ( (1/2)g(t^2) ). I understand the (vt) part and the (g(t^2)) part because the velocity*time would give the distance travelled while the g, the earth's gravitational pull (9.8 m/s^2)*(time^2) would give the distance travelled caused by the force of gravity, but I do not understand why the (1/2) is there. I think (from the way I have understood what they have written) that they seem to have derived this equation from the equations describing the velocity of the ball, but they do not explain how they derived it. The first equation/statement that they have made is that the initial velocity in the x direction will remain constant over the course of the ball's movement (which adheres to Newton's first law), or v2x = v1x. The second equation is that the second velocity is equal to the first velocity minus earth's gravity*time, or v2y = v1y - gt.
Can you help me understand what I am missing?
ANSWER:
What you are missing is just a little calculus to help you do the math
to derive the equations from the basic assumptions. Velocity is rate of
change of position, acceleration is rate of change of velocity; calculus
deals with rates of change of things. What you have written is the position
as a function of time if the acceleration is a constant, -g. What you
write as v should be written as v0 which is the
velocity at time t=0; by v we usually mean the velocity at
time t and in a constant acceleration problem, v is always
changing. I am going to tell you one piece of calculus. If you have a
function of the form tn, where n is any integer,
then the rate of change of that function is ntn-1.
For example, the rate at which t3 changes is 3t2.
OK, let's apply that to y=v0t-½gt2.
What is the velocity? [Rate of change of position y]=v=v0∙1∙t0-½∙2∙gt1=v0-gt.
This makes sense, because you can see that velocity is decreasing
(becoming more negative) at the rate g, which is the acceleration due
to gravity. The equation for velocity is easy to find the rate of change of
because it is a linear equation whose slope is the rate of change. But, just
to follow through on calculus I gave you, [rate of change of velocity v]=a=-g∙1∙t0=-g,
in accordance with our expectations.
QUESTION:
i am not a student. just interested in physics. this is a question just for the physicists. why do none of your theories have to be proved. take Schrodinger cat experiment for example. it does not make any sense and there is no logic to it. maybe Alastair Rae has it correct. is it real or just an illusion. Einstein spent most of his adult life trying to disprove theories that the person who came up with it could not prove and yet Albert could not disprove it either. some of these things make sense but others are nonsense and you have to sit back and wonder why. i know i will offend a lot of you but coming from a person who is not coledge educated and looks at things from a reality perspective you guys don't seem to have a clue. most of the basic theories make sense and do have validity. but when you get to the molecular level and start talking about things you cant both measure speed and position at the same time because just by observing it you alter it and thereby invalidate the measurement. well then you are getting a little ridiculous don't you think. your field of study is fascinating to me until you get to the useless stuff. well thats my rant , sorry if i pissed you off but sometimes common people have a better perspective on reality than those of you who are over educated and think too much.
ANSWER:
What makes you think that physicists do not need to "prove" theories.
Making theories is only maybe 20% of our work, testing them is the other
80%. The first thing you do
to betray your ignorance is to call Schrödinger's
cat a theory. It is what is called a gedanken, a thought experiment
put forward to make a point. And, here is what is ironic, the point Schrödinger
was making was that which you evidently espouse, that quantum mechanics, at
least the Copenhagen interpretation, is an incomplete theory. Even though
Schrödinger was one of the fathers of
quantum mechanics, he was on Einstein's side on this point. In his
original cat article Schrödinger
writes "One can even set up quite ridiculous cases." It makes no
difference to me whether you are college-educated (or if you can spell it);
lots of "common people" can think logically and analytically, keep an open
mind to new ideas. A major part of your rant addresses "reality". You find
the uncertainty principle (that you cannot measure position and speed to
arbitrary accuracy simultaneously) untenable from a "reality
perspective". Have you taken the trouble to find out how accurately you are
able to measure them and at what point the uncertainty principle kicks in?
Suppose that you could measure the position of a car to the diameter of one
atom, about 10-10 m (even though you and I could never hope to
make so accurate a measurement). How accurately could you measure the speed?
For a 1000 kg car, I could measure the car's velocity to an accuracy of
about 10-26 m/s=2.2x10-26 mi/hr. Have you ever thought
about trying to make measurements to such accuracy? Your "reality" is not
reality but intuition; your gut tells you that you can measure a car's speed
and position at the same time just fine (just take a photo of the car
driving past a meter stick with the speedometer visible in the photo,
right?), so it must therefore be possible to do the same for an electron.
But what you are doing is extrapolating your experience (with cars) into a
region where you have zero experience; intuition is based on your
experience, and it is not valid to apply your intuition where you have no
experience. The real bottom line goes back to your claim that we have no
need to prove our theories. The fact is that quantum mechanics has been
shown innumerable times to describe the way the subatomic world is observed
to behave; the "proof" is overwhelming. Questions still exist and are
vigorously debated concerning whether it is a complete theory, how to
interpret the theory, what does a measurement or observation really mean,
etc; this is how it should be—existing
theories should always be held up for testing and contemplation. Your claim
to be "interested in physics" but not "the useless stuff" really means you
are interested only in physics more than 100 years old; 100 years ago most
physicists assumed that, given how well Newtonian mechanics and Maxwell's
electromagnetism worked, there was nothing left to understand, just keep
making more accurate measurements of things that were already understood. In
the end, I agree that theories need to be proven, but mainstream modern
physics is at least shown to be in agreement with happens in nature and has
been able to predict phenomena not previously known. That is why I am not a
fan of string theory—it makes no predictions or descriptions of nature and
therefore is not testable.
QUESTION:
My question is in regard to special relativity. So according to this theory, we know that time changes based on how fast one is traveling or under different gravitational fields. I'm interested particularly with the time aspect of relativity--suppose one person is traveling fast enough or is under a strong gravitational field to result in some sort of time dilation effect and we compare this to an observer on earth. Using a simple mechanical clock, could we really observe a difference, and what is actually happening to the mechanical clock for this to happen?
ANSWER:
I know it is really hard to believe that clocks in moving systems really
run slower. But if I could get you to agree that one particular clock is a
perfectly good clock and all other clocks (mechanical, biological, etc.)
would run in synchronicity with it, and I could make it believable that this
clock runs slow when moving, then you would have to believe that time runs
slower in moving systems, right?! The one
thing you must believe is that all observers measure the speed of light
in a vacuum to be the same. Now, read my earlier answer about the
light clock.
QUESTION:
Is it possible for physicists to know the half life of a radioactive substance just by the arrangement of the protons and neutrons or is it completely random and the only way to find out is by measurement of each of the different isotopes?
ANSWER:
The structure of nuclei is a pretty well developed theory. What that
means is that we can often fairly accurately calculate the half lives of
nuclear decays. But, if you want a really accurate value, you should measure
it if possible.
QUESTION:
Why does light travel so fast?
ANSWER:
Light is an electromagnetic wave, that is, it is a phenomenon involving
electricity and magnetism. The physical laws which describe electric and
magnetic effects are called Maxwell's equations (there are only 4
equations). It turns out that if you mess around with these equations you
can actually calculate the speed of light. It is determined by only two
quantities, one tells you how strong the electric force is and one tells you
how strong the magnetic force is. So, the properties of electromagnetism fix
the speed of light to what it is, 3x108 m/s.
QUESTION:
If a car A, of mass 1,000 kg, and velocity 100 km/h, collides
with a car B, of mass 1,750 kg, and of velocity 90 km/h, will the cars come
to a stop when they collide, or will the overall forces push the cars in one
direction or another? As in, will the greater mass of car B cause the cars
to move in the direction that car B was travelling? I would assume this is
so, because of the addition and subtraction of vectors, but I become
confused when I try to account for the the law of action and reaction, and
the elastic/inelastic nature of the cars.
ANSWER:
In a collision, the important quantity is linear momentum, mass times
velocity; linear momentum in a collision does not change (this is called
conservation of momentum). I presume that you are talking about a head-on
collision. I will say that the 1750 kg is origninally going in the positive
direction, that is its velocity is +90 km/hr and its momentum is
1750x90=157,500 kg-km/hr. The other car's momentum is 1000x(-100)=-100,000
kg-km/hr. So the net momentum before they collide is 57,500 kg-km/hr.
Immediately after the collision let us assume that they stick together
(called a perfectly inelastic collision); then the momentum after the
collision of the 1000+1750 kg=2750 kg coupled cars is the same as just
before. So, the speed of the two coupled cars is v=57,500/2750=20.9
km/hr (in the direction the 1750 kg car was originally going since it is
positive). In the real world, the two will slide to a stop, but how far
depends on local conditions (like is the road slipery, are the wheels
locked, etc.) If they do not stick together, all sorts of
possibilities exist, but it is quite unlikely that one of the cars will be
at rest. Note that the 1750 kg car would not have "won" if it had been going
much slower. You could figure the speed that the 1750 kg car would have if
the two were to come to rest: 1750xv-100,000=0, so v=57 km/hr.
QUESTION:
Why couldn't a scientist accelerate a metal object to near light speed by building a electromagnet around a long vacuum tube with a metal object (ball) within it. The way I imagined it.... the tube would be surrounded (the length of the tube) with electromagnets that would "fire" along the length the tube creating magnetic fields that pull (or push would work too I think?) the ball along.....In other words the steel ball in the tube would be at position "a" and then position "b" magnet would "fire" pulling the ball to position "b" and then the electromagnet at position "c" would fire and position "b" magnetic would shutoff pulling the already moving ball to position "c" at slightly increased speed and so on and so forth. Since its my understanding that electricity is conducted at virtually the speed of light, it seemed to me that proper engineering could accelerate the ball to virtually the speed at which electricity is conducted.
ANSWER:
The idea of using magnetism to accelerate a projectile has certainly
been developed; it is called a
railgun. However, just
because the fields propagate at some speed does not mean the projectile will
be easily accelerated to those speeds. No matter what, you have to somehow
provide enough energy to your projectile and this has nothing to do with the
speed of field propagation.
QUESTION:
I understand that all forms of electromagnetic radiation travel at c in a vacuum. Do they travel at different speeds from one another in a medium such as water or glass?
ANSWER:
The speed with which an electromagnetic wave goes through a medium other
than vacuum is very complicated to understand and depends on the structure
of the material. However, it is certainly true that the speed of the wave
depends on the wavelength of the wave. This is called dispersion and it is
the reason that visible light passing through a prism (or raindrop) is
spread into a rainbow of different colors.
QUESTION:
If I have an observer A and B, and A is "at rest" while B is traveling .7c (or any big number smaller than c) in one direction, B would slow down in time, a la the effects of speed/mass and time dilation. This works in the reverse, since movement is relative. However, now A and B would perceive each other to be moving slower in time than the other, even though their "times" are slowed down equally. Why wouldn't they perceive one another to be traveling through time "normally"?
ANSWER:
I really do not know what you are asking. What does "normally" mean? And, time is not
perceived to run slower for a moving clock, it really does run slower.
The thing to grasp is that it is true that for both A and B, the other's
clock is running slower. In order to compare their clocks they must get into
the same frame (not moving relative to each other). You may be interested in
the twin paradox and a recently
asked related question.
QUESTION:
If atoms, hence molecules,hence objects are predominately 'empty space', why do things not simply fall through the other e.g. a book does not fall through the table, we do not fall through the floor, etc
ANSWER:
This question has been often asked before and the
answer is linked to from the FAQ
page.
QUESTION:
is it possible to conserve momemtum with a mousetrap? make the mousetrap continuously reload itself?
ANSWER:
I have no idea what you mean. Certainly a mousetrap cannot reload itself. It is really an energy thing, not a momentum thing. Before the trap
trips, energy is stored in the spring. When tripped, that energy is converted into the kinetic energy of the "killer bar" and when it strikes the board, the energy is converted into thermal energy (the trap heats up a little)
and sound energy. There is no way to use the thermal and sound energies to tension the spring back,
i.e. the energy the spring originally had is essentially lost.
QUESTION:
I am watching a tv show discussing the relationship between high velocity, gravity, and time. The show gave a hypothetical example: "Time travelers" or astronauts traveling at near the speed of light could experience 1 year of travel but find that 10 years had passed on earth while they were away.
My question is: In the above scenario, what does physics say about those astronauts being able to send and receive a signal, say with a rover, or even to just receive a video signal, if the signal traveled at the speed of light while they traveled at "near" the speed of light? If they could receive a video signal of earth would they witness time slowed?
ANSWER:
If you were a frequent reader of this web site, you would see that one
of my favorite points of view is that in special relativity, it is not how
things look, it is how things are. A moving clock may
appear (under some circumstances) to run faster, but it actually runs
slower. There is nothing to prevent two observers from communicating with
each other using light signals, but how those communications appear to each
observer depends on their relative motion and does not reflect how fast
their respective clocks are running. You should look at my
earlier discussion of the twin
paradox; if the moving twin is looking at a tv show (broadcast from earth)
while on his way out, it is in super-slo-mo (he gets two years worth of
signals every six years) but on the way home it is in fast-forward (he gets
18 years of signals in 6 years). As you will see, my whole explanation of
the twin paradox hinges on the twins' communicating.
QUESTION:
suppoose two blocks are placed such that one is belo and other is above ,,,,ionthe grond ....now below block have two rough surfaces....of ground and of other block......now if we apply ahorizontal force on bottom block such that it doesnot move ...... now it means both suface give static friction,,,,so by newtons third law...a staic fricion pair act on upper block $ hence it should move.,,,but it is never seen that ...below block is not moving but upper block is......where is my fault
ANSWER:
You are assuming that the upper block has a friction force on it, but
that is incorrect. Suppose we apply Newton's law to the upper block: it is
in equilibrium in the horizontal direction and therefore the sum of all
horizontal forces on it must be zero. Now, the only possible horizontal
force on it is static friction from the block below it. Therefore, that
friction force must be zero. If you push on the upper block and nothing
happens, there will be friction forces between it and the block below and
between the block below and the floor.
QUESTION:
I asked this question to many teachers of our country but couldnt get precise answer. It may sound a stupod question though.
If two bodies having same volume but different mass(say 1 be 20 kg and another 30 kg) is dropped from equal significant height, which will fall on earth faster? And why?
ANSWER:
And, you will not get a precise answer because you are not asking a
precise question. What does "significant height" mean? 5 m, 5000 m? What is
the "same volume"? A marble size, a bowling ball size, a football stadium
size? I am not being flip here, but the big question is how important is air
drag? If air drag is not important, the two hit the same time. So, if you
drop two bowling ball sized objects from a height of a few meters, they will
hit the same time as long as their masses are not too different (like your
20 & 30 kg objects). You can find an
explanation of why that happens on my FAQ. On the other hand, drop a
balloon and a bowling ball, both the same size, and you and I know who wins
that race. If there were no atmosphere, they would still tie, but you see
that in the real world mass makes a difference. The air drag also depends on
speed, in fact it is approximately proportional to the square of the speed
for most objects, so the faster you go the more important drag becomes (in a
hurry). That is why I stipulate from not too high. You can find
exhaustive discussions of air
resistance, free fall, and terminal velocity, also on my FAQ page.
QUESTION:
I am having a little trouble understanding why certain differences exist in the densities between elements. For this question I'll use Uranium, and Osmium.
Uranium has a density of 18.9 grams per cubic centimeter, Osmium has a density of 22.6, yes Uranium has an atomic mass of 238, whereas Uranium has 190.
Since Uranium has more protons, electrons, and neutrons per atom than Osmium, I am afraid I am at a loss to explain to myself why a cubic centimeter of uranium is less dense than a cubic centimeter of osmium.
Could it be that the volume of the uranium atoms is so much greater than the osmium atoms that fewer can occupy 1 cubic centimeter and thus account for the lower density?
ANSWER:
It all boils down to what is the size of an atom or, equivalently, how
far apart to atoms of a particular element space themselves in the material.
The size of an atom is determined not by what its atomic number or atomic
weight is, rather it is the atomic structure. For example, the radius of
potassium is much bigger than for lead. I have looked at a table of covalent
radii in Wikipedia
to get some numbers for this answer. In your case the radius of an osmium is
about 130 compared with uranium which is about 175 (these are in pm,
picometers, but that is not important because I will look at ratios). So if
a solid were just a pile of atoms, the density would be m/V and the volumes
are proportional to the radii cubed, so the ratios of the densities of
uranium to osmium would be
ρU/ρOs=(238/1753)/(190/1303)=0.51. In this simple
model, uranium has only half the density of osmium. Of course, this is a
really simple model and much depends on how the atoms bond in the bulk
material.
QUESTION:
I've been following the news about the LHC, and while it's very fascinating, I'm curious why it's any more imperative that we find a higgs boson than a graviton? I understand that we don't really have a very good understanding about how particles acquire mass (i.e. in the standard model), but there is also evidence that implies that our theory of gravitation might not be consistent under all circumstances (i.e. it isn't at singularities). Is it erroneous to think that finding the graviton is equally important to finding the higgs, or maybe even more so? It just really seems that finding the graviton would preclude finding the higgs, since it's responsible for one of the four forces in our physical universe.
ANSWER:
My perspective would be that the Higgs boson has been predicted by the
standard model of particle physics, a very successful model in describing
elementary particle physics; a graviton is predicted by no theory because
there is no successful theory of quantum gravity. The graviton would be the
quantum of the gravitational field if there were such a theory. For now,
though, there is no particular reason to believe that gravitons actually
exist. Also, we have no idea what to look for or how to look for it.
QUESTION:
Is their a maximum tempeture or can heat be infinite. If their is an abslute cold why can't there be an absolute heat. If heat causes aomic particles to accelerate is it possible for heat to cause matter to go beyond e=mc^2.
ANSWER:
There is a speed limit for particles (the speed of light), but there is
no energy limit. And, since the temperature is defined to be the average
energy per particle in the object, there is no upper limit to temperature.
Of course, as energy per particle increases, molecules and atoms disintegrate
into nuclei and electrons (a plasma) and then nuclei start interacting with
other and transmuting and so forth, so the identity of what it is you have
may change, but there is no upper limit on the total energy of a system.
QUESTION:
Doing a little target practice the other day I observed something that I am at a loss to explain. For this exercise I hung a large block of wood from a chain (I'd estimate the weight of the block at around 100 pounds) Then I shot it with a .30-06 springfield. The particular cartridge loads I was firing produce a muzzle energy of about 2600 foot-pounds. (I was about 50 feet away, more than close enough for the bullet to retain substantial energy)
The bullet made it about 8 inches into the block, since the bullet failed to penetrate this tells me that the block took the full energy of the bullet. However when it was struck the block more or less wobbled on the chain. Now as I understand the term foot-pounds, this is the energy required to move 1 pound, 1 foot.
So I am a bit of a loss to understand how all of the energy here was expressed. The energy of the bullet in foot pounds is exponentionally higher than the weight of the block yet it moved surprisingly litte. I am not sure I understand why.
My first thought was that it had something to do with the law of equal and opposite reactions, as the bullet impacted and pushed the block, the block pushed back. It also occured to me the block is hanging from a chain, and when its center of gravity was disturbed gravity pulling it back toward that center could also have had an effect.
So I was hoping you could explain for me why the block moved so little? Where did all of my bullet's energy go?
ANSWER:
First, what is a ft-lb? It is the energy needed to lift one pound
one foot, not the energy necessary to move it one foot. So, your 2600 ft-lb
could have, if transferred to a 100 lb block, lift it 26 feet. Wow, do you
believe that? So your question "Where did all of my bullet's
energy go?" really needs to be asked. The fact is that what you have is
called a perfectly inelastic collision; that is where the projectile and
target stick together after the collision. And, the energy is not
"conserved" in an inelastic collision, that is, energy disappears during the
collision. (It does not really disappear, we will get to that later.) Now,
scientists do not really like to work with feet and pounds and stuff like
that, we prefer meters and kilograms and Joules (for energy), so I am going
to recast your problem to those units. 100 lb is about 45 kg, 2600 ft-lb is
about 3500 J, the mass of the bullet (I get from Wikepedia) is about 0.01 kg
(10 grams), and so the speed of the bullet is about 840 m/s (which is about
1900 mph). What is conserved in any collision is linear momentum which is
the product of mass times velocity. The momentum of the bullet before it
hits the block is 0.01x840=8.4 kg-m/s; this must be the momentum after the
collision, so 45.01v=8.4, so v=0.19 m/s=0.6 ft/s. The energy
after the collision (using
½mv2 for kinetic energy) is only about 4.8 J=3.5
ft-lb. This is only enough to lift your block about half an inch! So, back
to your question—where did the energy go? Don't stick your finger in the
hole right afterwards, it will be hot. The energy goes into heat and you
will find the bullet and block both hot. What "disappears" is kinetic energy
(energy of motion), not total energy which is conserved.
QUESTION:
If an electrically charged rod is brought near normal flow of water from a tap, the flow gets slightly diverted towards the rod. How does this happen ?
ANSWER:
The water, being in the electric field of the rod, becomes polarized,
that is the water closer to the rod has a charge opposite the rod and the
water on the other side of the stream has a charge the same. The opposite
charge is pulled toward the rod and the like charge pushed away. But the
opposite charge is closer and so the force it experiences is bigger, so the
net force on the water is toward the rod.
QUESTION:
Are not black holes, not holes at all but intensly hardened spherical objects?
ANSWER:
They are singularities, that is they are points but have mass. So, they
have infinite density. But the reason they are called holes is that
everything that comes within their range is captured and disappears. The
reason they are called black is because light cannot escape them either. I
would call that a hole.
QUESTION:
if the earth is rotating and moving around the sun and the all while the milky way is rotating then why do we always see the same stars when we look up at night. i understand that the galaxy is full of stars and they move around the center and that we are on the outer reaches of an arm of the spiral but even so with the earth traveling around the sun and the solar system in motion and the earth rotation all at the same time it doesn't make sense why the sky is always filled with the same constilations. yes the are located in a different place over the night but they are always the same ones. help me to understand this phenominon please
ANSWER:
In fact, the sky is not the same all the time. It changes with both time
of day and time of year. There are some constellations only visible at
certain times of year. Regarding the galactic rotation, the period is 50-250
million years (depending on how you define it, it does not rotate like a
rigid body) so wer are not likely to notice any drastic changes there.
QUESTION:
I've been reading about dark matter and dark energy lately, and like most people, I'm very confused! I understand that dark energy is the energy of empty space, representing the cosmological constant. So is dark matter really just the matter that comprises empty space? This would make sense, given that 90% of the mass of a proton is empty space--we're living in a universe that is dominated by more dark matter than regular matter!
ANSWER:
The motion of many things in the universe cannot be understood if we
apply known laws (gravitation) with observable mass (stars, planets, etc.).
Therefore, it is postulated that there must be something, dubbed dark
matter, which we cannot see which is causing things to move differently
than we expect. I should note that all attempts to observe this stuff have
failed, although the search goes on. My own take on dark matter is that it
is just as likely that our "known laws" are not as good as we believe them
to be; that is, we do not understand gravity as well as we think we do.
Several years ago it was determined that the most distant objects were not
just moving very fast, they are actually accelerating. This was totally
unexpected because gravity is, as we know it, purely an attractive force and
the speeding up would imply the existence of a repulsive force. The origin
of this mysterious force is referred to as dark energy. Again, what
it is is not well understood and one way to integrate it into general
relativity (the theory of gravity) is, as you note, to reintroduce the
cosmological constant rejected by Einstein early in the development of the
theory. I have no idea what you mean by "90% of the mass of a
proton is empty space", but if dark matter is the answer and it is found,
the universe is dominated by it.
QUESTION:
If a 60 kilogram human were to fall off the top floor of the Eiffel Tower (276.13 meters), how much would they accelerate before they hit the ground?
ANSWER:
First, the easy answer—ignore air
friction. This is what an elementary physics book would tell you. In that
case, 0=276-5t2 and v=-10t. The first equation tells us that
he would fall for 7.4 seconds and then the second tells us that he would be
going 74.2 m/s=166 mi/hr; the mass is irrelevalant. But the assumption that
air resistance is negligible for this problem is surely wrong. Putting in
the effects of drag is very complicated and I have written many
answers related to this topic. If
you are really interested, you can look at those answers.
QUESTION:
I'm a high school student aspiring to study physics like a lot others students out there and I got a work related question:
Do you get free leisure time for yourself and did you get to have fun and do your own things when in college?
I'm not a party freak or something like that but I do like to paint, travel, reading, things like that, but a lot of people tell me that if I study physics I "won't have a life". I'm just curious as if this is a myth or is there some small truth behind it.
ANSWER:
Well, this isn't really a physics question, but I guess I can't resist
saying a bit about this. Are there some scientists who are narrow, just do
science, in short are nerds? Sure. But, there are just as many English
professors who are narrow, only care about books and arcane criticism; and
businessmen who spend 80 hours a week at work churning out money; and
attorneys whose only interest in life is to just get that partnership; or
physicians who have time for nothing but work and golf. In my experience,
there are many more scientists who have appreciation for art, music, and
literature than there are practitioners of the humanities who have any
appreciation for science. Your life is what you make of it and science,
although a demanding mistress, provides ample opportunities for those doing
it to taste many flavors in life. Many of my fellow physicists, like myself,
have collaborated with colleagues all over the world, traveled to spend time
at other laboratories, done research around the world, attended conferences
on many continents. I, myself, have done experiments in Paris, Tokyo,
Vancouver, Los Alamos, and you can be sure I did not just go to the lab when
at these places. Here is what matters—do
what you love and have broad interests on top of that. You will have a happy
life. Given the advice you have gotten, "a lot of people" are nuts. You can
maybe get an idea of how a perfectly ordinary physicist can "have a life"
from my personal web
page. You might enjoy the book "The Life it Brings" by Jeremy Bernstein.
QUESTION:
I can't get the actual concept of energy. In my text books it is given that energy is the capacity to do work. And work is the scalar product of force and displacement. But i can't understand anything from that definition. What is the need, or what is the physical significance of these two physical quantities?
ANSWER:
Here is my perspective. Sometimes the fundamental ideas of science can
be expressed rather easily, take Newton's laws for example. But, there is
often more than one way to skin a cat. Energy, at least at the level it
appears in introductory textbooks, really is nothing more than Newton's laws
expressed from a different point of view. Often in science we find that if
we find clever new ways to express some idea, we gain insight and we make
problem solving easier. No new fundamental physics is introduced but our
whole understanding becomes clarified. That is what energy is, just a new
way of looking at things. If we define something called work, it turns out
that when we do work on a system we change its energy, and this energy stuff
turns out to be very powerful (pun intended). One thing that comes from it
is that if we have some system where no work is being done on it, its energy
is conserved. And seemingly hard problems become easy. For example, if you
have a car sliding down a smooth hill whose shape is unknown but whose
height is known, it is trivially easy to find the car's speed at the bottom
using energy concepts yet very subtle and tricky to do just using F=ma.
The simplest example of work/energy is the isolated particle on which we do
work; the thing you change about the particle is
½mv2, the kinetic energy of the particle. If you look
in your textbook, you will find that the derivation of this simple fact
employs only Newton's second law and simple kinematics.
QUESTION:
if gravity in space acts like a magnet is there a , if weak, a gravity in between planets?
ANSWER:
Gravity does not act like a magnet. A magnetic force is sometimes an
attractive force, that is where the similarity ends. Gravity is throughout
the universe, although the farther you are away from large masses, the
weaker it is.
QUESTION:
When we say that a large mass causes spacetime to be warped, what exactly does that mean? My understanding is that the idea that space is made up of some type of "ether" was long ago refuted (Morely-Michaelson?).
Yet when photons travel near a massive body, their path is affected. This obviously can't be due to gravitational attraction since a photon has no mass.
ANSWER:
You will find these questions addressed in several earlier answers. Go
to my FAQ page.
QUESTION:
Is there a way to help nuclear decay happen more often than it happens naturally?
Is there a way to pound nuclear waste into iron in a particle accelerator?
ANSWER:
You cannot change the half life of aome particular process. But you can
force something to follow a different path and create something more benign.
The ideas for
transmutation of nuclear waste involve both accelerators and reactors.
Although there has been lots of thought about how this might be done, it has
not proven practical on a large scale as far as I know.
QUESTION:
I was wondering what could happen if you could get energy from harnessing the ocean. for example could you create energy by filling a huge basin in the ocean with water, draining it through a turbine(s) and then repeat? I would assume you would have to drain the water to start the process again, which might be a problem because that would use energy? Is this a good idea or not plausible?
ANSWER:
It would take more energy to fill it (lift the water up) than you would
get by letting it fall through turbines. However, the ocean is a vast source
of energy via
tides and waves.
QUESTION:
Someone I know reckons the rotation observed when a ball on a string is going round in a circle is only a visual effect and not real, another person says its real and its called synchronous rotation. Can you tell me which of them is right and why?
ANSWER:
See an earlier answer.
QUESTION:
If we spin a round object in a vaccum like in deep space will it rotate forever?
ANSWER:
In a classical sense, the answer is yes (although there is no such thing
as a perfect vacuum). A second layer of this question is that a rotating
mass will emit "gravity waves" the same way as a rotating charge
distribution will emit electromagnetic waves, so its energy will eventually
be radiated away. I should add the proviso, however, that gravity waves are
hypothetical in the sense that they have never been observed directly.
QUESTION:
Atoms are surrounded by electrons with a negative charge. What cohesive force keeps atoms together instead of being flung apart due to repulsion of negative charges?
ANSWER:
The easiest way to understand this is that the outermost electrons in an
atom get shared shared with a neighbor. If one kind of atom has one
"loosely bound" electron and another has a vacancy (hole) in its outermost
shell, the two atoms will bind together to form a a molecule. This is sort
of what chemistry is all about (valences). In a solid, the atoms are also
bound by sharing electrons but, if there is too high a temperature, the
atoms will separate (melting).
QUESTION:
So quick question, was just curious as I was making iced coffee, I boiled it in a French press, then I stick the coffee in a mayonnaise jar, and put it in the freezer to cool it. (I usually put ice in it too, but I was out this time).. And I wondered 2 things at once:
1. I've heard that if water is hot when it's put in a freezer, it freezes faster. I know that a stopwatch and a well conducted experiment would allow me to answer this for myself, but truth be told, I'm lazy, and was wondering if maybe you could just ya or nay that question a lot faster, plus, it still wouldn't answer WHY that was the case, if it IS true, so hoping you can help there too.
and 2. I was stopped for just a second by wondering if I should leave the lid on or off, or if it would make a difference at all.. If I left the lid off, seeing the steam come out of the jar as I put it in the freezer, I thought "well all that steam would get out and could thaw some of what I already have frozen in there.." (probably not true, but I thought it). Then on the heals of that I thought "well there would be a certain amount of heat energy inside that bottle that has to get out in some way, at some point, so the heat would transfer from the coffee, to the glass, then through the air in the freezer.. in other words, it's going to get out anyway, so what difference would it make whether the lid was on or off?"
ANSWER:
Read my earlier answer.
QUESTION:
If coffee is placed on a coffee warmer that has a 110 degree F coil
temperature, will the liquid gradually achieve a thermodynamic
equilibrium by reaching and remaining at 110 degrees F? The coffee could
begin either warmer or cooler?
ANSWER:
That depends on what else the cup is in thermal contact with. For example, if the room is real cold, the coffee will come into equilibrium at a temperature lower than 110.
QUESTION:
Are movement (acceleration) and gravity linked? To clarify, I read that an object accelerating at 1g will be moving close to the speed of light within one lifetime. Why is it that here on earth we are not experiencing the effect of near light speed travel every 80 years, relative to an object that exists far away from our gravity well? also, is it that time passes more quickly for objects father out from a gravitational influence and this is the acceleration they 'feel' when they move against it? (the slowing of relative time is the 'force' of gravity)
ANSWER:
Certainly acceleration and gravitation are not related in the sense you suggest. Maybe you are thinking of the
equivalence principle?
QUESTION:
An object gains mass as it moves faster. So the inverse must also be true: An objects loses mass as it moves slower.
If an object comes to a perfect (universal) stop, does it become massless?
Time moves slower for an object, relative to other objects, as an object moves faster, relative to other objects. So the inverse must be true: Time moves faster relative as an object moves slower relative.
If an object comes to a perfect stop, how fast is time, relatively speaking? Is there a similar function to "cannot reach or exceed lightspeed" as it relates to time, such that an object can never come to a perfect stop? (maybe because it becomes less massive than light, implying that light does, afterall, have some mass, which certainly is not our current understanding)
Do we need an analogous term to "Lightspeed", called "Lighttime"?
What's "Lighttime" and what are its limits?
Maybe the analogous term would better be "Masstime"?
ANSWER:
The problem with your question is that the whole thing is based on a
fallacious premise—that there exists
something called "a
perfect (universal) stop". That implies that there is some single preferred
frame of reference in the universe and any other frame should be viewed as
moving with respect to that one. In fact, there are an infinite number of
frames where the laws of physics are those which we know and they all move
with constant velocity with respect to all others. These are called inertial
frames of reference. An object at rest in any inertial frame has a mass
called its rest mass and, if it is moving with respect to some other
frame, it has a larger mass as measured by an observer in that frame.
Similarly, a clock at rest in any inertial frame runs at a rate called
proper time and, if it is moving with respect to some other frame, it
runs more slowly as measured by an observer in that frame. One thing you did
not mention was length: an object at rest in any inertial frame has a length
called its rest length and, if it is moving with respect to some
other frame, it has a shorter length as measured by an observer in that
frame. The only thing observers in all frames agree on is the speed of light—all
observers measure the speed of a beam of light to be the same. So, the rest
of your question does not really have any meaning. (Oh, by the way, light
does not "afterall,
have some mass".)
QUESTION:
Can Gravity effect a Magnetic Feild? If there was a Magnatar (NutronStar) Orbiting a Black Hole would the Magnatar's electromagnetic feild be drawn toward the black holes gravity?
ANSWER:
There is no accepted relationship between gravity and electromagnetism. Einstein spent most of his life after relativity trying to find a relationship, to no avail.
That is not to say there is no relationship, we just do not know it yet.
QUESTION:
as photons have a momentum when they collide with objects (e.g a solar sail) and get reflected the solar sail gains a velocity and the reflected photon would have less energy and hence lower wavelength (by a very very small amount). I cant find any proof of this change in wavelength, is there any mechanism by which the energy of the photon is conserved or does the wavelength chance by an incredibly small amount.
ANSWER:
You can learn about photon elastic scattering by reading about the
Compton effect,
where x-rays scatter from electrons. This was one of the crucial
observations and accompanying theory in paving the way for the new quantum
mechanics early in the 20th century. So, let's look at the
equation which, when energy and momentum are conserved, describes the change
in wavelength as a result of the scattering:
∆λ=(h/(mc))(1-cosθ) where h=6.6x10-34
(Planck's constant), c=3x108 (speed of light), θ is
the angle of scattering, and m is the mass (kg) of the electron or
whatever else is doing the scattering (all in SI units). Let θ=1800
for bounce back reflection, then ∆λ=(2h/(mc))=8.8x10-42/m.
Suppose that the wavelength is a visible photon, say λ=7x10-7 m
and the mass of your solar sail is 1 kg. Then ∆λ=8.8x10-42
m. I think you would agree that, for all intents and purposes, the reflected
photon has remained the same wavelength. On the other hand, if m=9x10-31
kg, electron mass, and λ=10-10 m (x-ray), ∆λ=10-11 m, a 10%
effect.
QUESTION:
is it true that matter cannot be produced just changed? what i mean is, does the matter that im made of come from the black hole and when i die, my matter simply changes but doesn't disapear?
ANSWER:
As I have said many times, there is no such thing as conservation of
mass. Mass may be created or destroyed. The physical law is conservation of
energy. The total energy of a system must remain constant. Mass is just a
form of energy, E=mc2. Incidentally, you did not come from
a black hole. The atoms from which you are made were manufactured in stars
long since exploded and dead.
QUESTION:
One man is inside a closed box in somewhere far in space with no force acting on this system and the container contains air. the man is holding onto a knob(which he can grab to stick to the wall) like thing in one side... and similar knob is on the other side of the box.
At the begining, the momentum of the system is 0. He pusses himself against the knob with a force F and let go off the knob. he moves with a velocity V in one direction and the container moves in opposite direction with same velocity. After some time the man and the other side of the container meet. They collide and the man quickly holds the other knob.
During his motion inside the box, he collided with millions of molecules moving in the random direction.for now, looking only in the direction of the motion, it may not be possible for equal no. of molecule to hit the man from both(towards and opposite)direction of motion( as the molecule are moving ranodmly) while moving through the air. So his final velocity(the velocity when he reaches the other end) may have increased or decreased as molecules randomly added their Vs to the man. But for the container the velocity has remained the same all the time. SO, there is difference in V during the final collision. AND as the man has held the knob again, he has in a way stuck to the wall making him part of the momentum of the box (which ultimately should have come to 0 when the man hit the opposite end of box.) BUT momentum of the both container and man donot cancel as the man has different V than it had when it separated from the box. THIS makes the system move in the one of the direction!!!!
A object inside a Closed system affected the outer system( the whole container and the universe). This cannot not happen, as we know. so my question arises-- DID the air molecules acted in such a way that it was not random?? or equally distributed like a wave????????? to provide same Vs from both direction?
ANSWER:
Wow, what a rambling question! Your question in essence boils down to:
is linear momentum really conserved in an isolated system, regardless of how
complicated the system is? First, you make a little error in saying that the
box recoils with the same speed as the man; this happens only if the mass of
the box happens to be the same as that of the man. In fact, when the man has
latched on to the other side of the box and when everything has come into
thermal equilibrium, the man and box will again be at rest. In order to
understand what is going on, let's consider a more extreme situation: the
box is filled with water. The mass of the box + water happens to be equal to
the mass of the man. When he pushes off, the box + water recoils with the
same velocity. Now, the man slows down, because of the water exerting a
force on him (which is sometimes called viscous force, sometimes friction).
As the man goes through the water he eventually stops. But, because of
Newton's third law, the man exerts and equal and opposite force on the water
+ box, so they stop too. It is the same with the air as with the water,
just less dramatic—any forces between the air and the man are equal and
opposite so that the net momentum of the man and air has to stay the same.
Momentum is always conserved in an isolated system. During the time of the
man's flight, air molecules were not moving in their usual random way; those
colliding with the leading wall slow down a little and those hitting the
trailing wall speed up a little so that there is a net flow of air in the
direction the box is moving. That is what you expect—the air has to move
with the box. Those which you strike your front side slow you down but that
speeds those molecules up in the opposite direction so that the net forward
velocity of the air is a little less than the velocity of the box. At all
times, the net momentum of everything is zero. A rambling question deserves
a rambling answer!
QUESTION:
does the volume of a liquid can be measure in litres or only in cubic meters? answer pleasse
ANSWER:
Volume can be measured in any units you like—l,
m3, gal, qt, cc (i.e. cm3)… Of course, there may be some
good reason to measure it in a particular way, like certain units are
required in the answer of a homework problem or local conventions require a
certain measure for people to understand.
QUESTION:
Scholars teach that airplanes fly because the velocity of air on the top of the wing is higher than the velocity of air on the bottom of the wing, because the curve of the wing requires the air on top to travel a longer distance, the Venturi effect. A theory is that the Venturi effect is valid with liquids but is not the deciding factor with air planes, and that air plane lift is created predominantly by wing surface angles and opposing air forces, like a kite. Which is it and where is the proof? I envision an airfoil with the long curved surface above and the short curved surface below, both symetrical to the left and right, presenting it on the level to an airstream, and see if it flies. My bet is it won't fly and moreover it will dive. I'm trying to learn and any info will be greatly appreciated. Also I have a great deal of trouble understanding why the venturi effect works, with liquids or air. I can kind of see it with liquids, as the molecular attraction of passing liquid might pull inward the surface of the conduit, but find it difficult to imagine the same effect with gases of the magnitude required to lift an airplane. I guess my question is, how is the venturi effect described by physical equations?
ANSWER:
You are getting at a fact normally ignored in an introductory physics
course—fluid dynamics is really a
complex subject, not amenable to nice neat solutions on a blackboard.
Nevertheless, we like to get real life applications of things like
Bernoulli's equation which, although inexact and incomplete, provides much
insight into fluid dynamics. I am not sure why you think that gases are less
appropriate to apply fluid dynamics to than liquids. True, the notion that
they are incompressible is much less applicable than for liquids, but the
general ideas still hold. Your overall conclusion, that the "Venturi effect"
is not the only important effect for airplane flight, is correct. You seem
to want to assert that it has no effect, and that is certainly not true; the
pressure being lower on the upper side of the wing plays an important role
in providing lift. Your idea that the wing acts "like a kite" is not, I
think, right either, since I think of a kite as being pushed up by a wind on
the bottom which is not really what happens with a wing. I have had some
flight instruction and one of the most important features in the theory of
how planes fly is "angle of attack", the angle the surface of the wing makes
with the oncoming airflow direction. Here is a brief explanation of how
changing the angle of attack provides lift. When the wing is inclined, the
air which comes off the trailing edge has a component downward. How did the
air, originally moving horizontally, end up also moving down? It must have
been that the wing exerted a downward force on the air. Finally, what does
Newton's third law say about this situation? If the wing exerts a downward
force on the air, the air exerts an equal upward force on the wing. Voilà!
That, I believe, is the main reason airplanes fly (and also why curve balls
curve and other phenomena which are normally attributed only to pressure
difference in elementary physics classes). Keep this in mind, though: reread
the first sentence of my answer—this is not simple stuff!
QUESTION:
why do we need the wavelength of the light to be smaller than the object being viewed ?
ANSWER:
Because diffraction
effects occur when the size of the object becomes comparable to the
wavelength of the light. To form a good sharp image of something requires
the wavelength to be much smaller than the size of the object.
QUESTION:
Do light have mass? Why and how can light travel at the speed of 3 * 100000000 m/s? What is the accelerator of the light or due to which energy light so fast? Is the following statement proved or accepted without proof: Highest speed of any particle is 3 * 100000000 m/s. If it is proved then explain me how it is proved.
ANSWER:
Your statement about the highest speed of a particle being the speed of
light is wrong; a particle with mass must have a velocity less than
the speed of light. The answers to the rest of your questions may be found
on the FAQ page.
QUESTION:
In the Twin Paradox, someting I
recently heard of, I have two questions.
-
Why is it that the closer you get to the speed of light, the less time affects you, in other words, what is it about extreme speed that makes your clock run slow?
- The whole situation is just a though
experiment, and if we assume the theory of speed affecting time (d=rt)
then everything works out perfectly. Why is it a paradox?
ANSWER:
The reason that moving clocks run slow is that the speed of light is the
same as seen by any observer. I know that this does not seem to follow, but
that is the case. I believe the easiest way to see the connection is the "light
clock" which I have described in an earlier answer. It is wrong to say
that the faster you go,
"the less time affects you". In your own frame of reference, time ticks
on perfectly normally. Your second question makes no sense, but I assure you
that the notion of moving clocks running slowly is not "just a thought
experiment"; it is a well-verified fact. You might also be interested in
reading my explanation of the twin
paradox.
QUESTION:
Do friction takes place in vacuum? If yes, then how and why? If no, then is fuel (force) required to continue the motion of spacecraft in vacuum (assume that it is moving with constant velocity)? I am confused because Galileo states that no force is required to continue the motion with constant velocity.
ANSWER:
In the context you are asking, no, there is no drag type friction in a
vacuum. Hence, a spacecraft experiences no force and therefore moves with
constant velocity without having to burn an engine. I should note that there
is never a pure vacuum and so you are never really fully free of friction;
this force is sufficiently tiny that you would probably go many millenia
before there was any noticable loss of speed.
QUESTION:
Is the graviton a particle like light is a particle, and if so, if you are moving away/toward it at high speed could it get 'red'/'blue' shifted, and you'd experience higher or lower gravitation?
ANSWER:
As I have said many times in my answers, there is no such thing as a
graviton because there is no successful theory of quantum gravity. A
graviton is the hypothetical quantum of the gravitational field in a
quantized theory of the gravitational field (of which there is not one yet).
Questions about gravitons are also linked to on the
FAQ page. Regarding your red/blue shift
question: when photons are red/blue shifted, the electromagnetic force does
not change strength.
QUESTION:
Is the energy in our bodies (nervous system not nutrients) and the energy we power our devices with the same thing? i.e. are we electrical in the same way a television or stereo are? If so, can our electricity be measured in volts and amps and do we always transfer electricity when we touch?
ANSWER:
Electrophysiology is very complex and, in any reasonable detail, beyond
the scope of this site. Nerve impulses are, indeed, electrical in nature.
However, they are really very different from the electrical currents in your
tv. Most appliances have currents carried by electrons in conductors whereas
neural cells transmit currents using ions of certain salts. Currents are
still measured in amperes and potential differences in volts.
QUESTION:
why are the particles made to collide at a speed very near to the speed of light in the experiment carried out in the LHC at CERN?
ANSWER:
Because the things which they want to study take very large energies to
create.
QUESTION:
I recently was introduced to Hawking Radiation but somthing about it confused me how can particals with have Negitive Mass? I understand that photons dont have mass but how does Negitive Mass work all i can imagine when I think about it, is some sort of warped area of space that would curve inward relitive to the space around it???
ANSWER:
Hawking radiation is often pictured as a virtual particle/antiparticle
pair being created near the the event horizon (called vacuum fluctuations)
and one of the two (both with positive mass) escapes and the other is
captured by the black hole. However, this creation is called "virtual"
because it violates energy conservation (something from nothing) but that is
ok, by the uncertainty principle, provided it only occurs for a very short
time. However, because this particular pair does not get back together,
energy must be conserved somehow and this is done by the particle which gets
captured back having negative energy. Thus, the escaping particle carries
away energy and the captured particle plus the black hole has net loss of
energy. The final effect is for the black hole to lose energy which would be
equivalent to saying we added negative mass to it.
QUESTION:
Why torque is defined as cross product of r & F ?
ANSWER:
Torque represents the effectiveness of a given force to cause something
to rotate about a given axis. Logically, it will depend on three things,
- how far from the axis you apply the force,
- the magnitude of the force, and
- how much of the force is perpendicular to the moment arm (distance
to the axis).
Taking the three together, torque should be proportional to rFsinθ
where θ is the angle between the vectors r and
F. Now, that just happens to be the magnitude of the vector
product rxF! Finally, we want torque to be a
vector because we want to distinguish between torques which make things want
to go clockwise from those which make things want to go counterclockwise, so
we very naturally define τ=rxF.
QUESTION:
Is there any natural antimatter in the universe? I mean by "natural" antimatter that was not created by humans. Does it exist naturally in our universe, or somewhere else. Also, how exactly do we, humans, obtain antimatter? Do we get it from another universe? I know that matter cannot be created by the Law of Conservation of Matter, so how do we do it?
ANSWER:
Nuclei which have too many protons (or too few neutrons, depending on
how you look at it) undergo
β+ decay which turns a proton into a neutron, a neutrino, and
a positron (an antielectron). This is a naturally occuring process.
Antimatter can be created in an accelerator by colliding particles together;
for example, smashing a proton into a nucleus can cause a proton-antiproton
pair to be created. In fact, antiprotons are also naturally occuring in
cosmic rays in the same way—an energetic proton from outer space enters the
atmosphere and creates a proton-antiproton pair. There is no such thing as
the "Law of
Conservation of Matter"; matter can be created or destroyed.
QUESTION:
How can a train moving without jerks between 2 stations be considered as a particle?
ANSWER:
To apply the ideas of physics to real-world problems, it is almost
always necessary to make approximations. Just how to make the approximation
depends on the particular problem you are addressing.
- If you have a train which moves in a straight line with known
acceleration and known initial velocity, you can do the kinematics
telling you the position and velocity of, say, the front of the train at
any time. This treats the train as a particle, makes no approximation,
and is perfectly accurate.
- If the train is moving at 50 m/s and has a mass of 108
kg, what is its kinetic energy? Treating it as a particle, we would say
K=
½mv2. Is
that right? No, because not all of the energy is translational—the
wheels are rotating and have energy in addition to their translational
energy. But, is it a good approximation? Probably so because the
rotational energy of the wheels is probably tiny compared to the total
energy of the train.
How much work was done to accelerate
the train to the speed given in the previous example? W=K, right?
That would assume that there was no friction and so that would probably
be a bad approximation.
The bottom line is that you have to make
approximations to make the problem tractable, but not such severe
approximations as to make the answer not approximately correct.
QUESTION:
Is it possible for a universe to exist that is made up exclusively of subatomic particles that never combine to become atoms?
ANSWER:
I would not think so. Two of nature's most important forces, gravity and
electromagnetic forces, are long range forces. Since protons and electrons
each have charge, it seems inevitable that they will find each other and
make hydrogen atoms. Now that we have large amounts of hydrogen atoms, it
seems inevitable that they will attract each other and form stars. Now that
we have stars, the atoms get really close to each other and the other forces
of nature come into play and cause heavier atoms to form. Only if you change
the laws of physics or create a universe with very extreme conditions like
huge velocities per particle or all uncharged particles might there be no
change in the microscopic structure.
QUESTION:
If I had an electric jackhammer and used it to spin a turbine generator once I got the cyle running could I not just loop the generated electrical energy back into the jackhammer to make the device run forever by its self or atleast till the pound of the jackhammer broke what ever plate it was hitting to spin the turbine???
ANSWER:
One of the cold, hard facts of nature is that no engine, even if there
were no friction (which there always is), can be 100% efficient. What this
means is that the work you get out of a machine is always less than the
energy you put into it. I think you can see the implication of this for your
idea.
QUESTION:
Is there any posibility that the speed of visible light could be slowed down? Basically what I am trying to ask is if the speed of light is a limit or a manditory constant?
ANSWER:
I assume we are talking about the speed of light in a vacuum. (Light
goes more slowly through a material like glass, for example.) There is no
possibility to slow it down—it is a
mandatory constant. It is also a speed limit for everything else.
QUESTION:
If an object is travelling at a velocity v, but has a constant acceleration a, why is it that I feel a force, mass x acceleration, rather than the momentum, mass x velocity? I suppose what I am asking is why, if the object hits me at its end point with an ending maximum velocity of vmax, do I measure the force I feel by the acceleration, the amount by which the velocity increased as a function of time, rather than by the end velocity of vmax?
Even having read your answer to another question, that it is the force that causes the acceleration, I am still confused.
ANSWER:
Let's agree that what we feel is a force. We do not feel a mass x
acceleration or a mass x velocity—we
feel a force. We just need to understand why we feel a force when something
hits us. And, you need to stop worring about what the velocity or
acceleration of the mass is before it hits you—it is only what is
going on when it is hitting you that matters. So, when a mass m hits
you it stops and to stop it has to slow down, that is, it experiences an
acceleration a. Newton's second law states that what causes a mass to
accelerate is a force F=ma, so the object experiences a force
F=ma. What is the source of that force? Why, you, of course! Finally,
Newton's third law says that if you exert a force on an object, that object
exerts an equal and opposite force on you; so you feel a force of magnitude
F=ma. It is important to note that this is the a the object
has while it is hitting you, not some acceleration it might have had before
it hit you. An alternative way to view this, if you really want to express
it in terms of the momentum, is the following. The acceleration is the time
rate of change of velocity, a=dv/dt. But, since the mass
remains constant, the force can be written as F=m(dv/dt)=d(mv)/dt=dp/dt;
the force is the time rate of change of momentum (during the
collision).
QUESTION:
Does a ball on a string being whirled around in a circle also exhibit synchronous rotation like the moon?
ANSWER:
See an earlier answer.
QUESTION:
Can water be change directly from a gas to a solid, without going through liquid form?
ANSWER:
Yes, it is called deposition and is the reverse of sublimation. This is
how frost usually forms. See the
phase diagram of water.
QUESTION:
If a bullet is fired from a proper angle, can it skip across the water
surface like a stone? Also what would be that angle?
ANSWER:
Yes, it is possible although, given its velocity, a single skip would
probably be the result except at exceptionally small angles. My dad tells
the story of a kid in his home town shooting a rifle into a lake and the
bullet ricocheting into a home and killing someone. There is no way of
telling what the angle is without knowing the geometry of the bullet, its
velocity, its mass, etc. Even so, it would probably be just as well
to do an experiment varying the angle and recording the effects (skip or
not).
QUESTION:
If the magnetic force of the Large Hadron Collider is 100,000 times that of the earth's magnetic fields, is there a chance that it could interfere with the earth's fields? If so, could it be causing a shift of the earth, which is then causing the weird occurences, earthquakes, tsunamis, etc. that are occuring?
ANSWER:
The field of the collider is very large compared to the field of the
earth inside the collider. But, that field is essentially zero at the source of the earth's
field in the core of the earth which is the only place you might have any
effect on the field of the earth. The field inside the collider is huge
compared to the field of a compass I have here in my pocket, but it has no
effect on the compass because it is so far away. I suspect that, even if you
could put the collider inside the core of the earth, there would be no
important effect on the earth's fields because the electric currents in the
core must be gigantic to cause the earth's field. Finally, even if the
earth's field were to change dramatically (it is well known that it has
changed direction many times in the past), it certainly would not cause the
kind of castrophies you mention; the main effect would be that the field
serves as a shield against cosmic radiation and if the field disappeared we
would suffer health consequences of radiation.
QUESTION:
My question is regarding the effects of mass on Universe. On Earth animals give birth. Fast forward a few hundred billion years and assuming all is well, there could be an enormous number of beings in Universe. Suppose they will inhabit and Terraform other planets, they will also multiply etc. My question is: Will this enormous number of beings (mass) in Universe alter the expansion rate at which Universe is expanding? In other words just by giving birth and multiplying are we adding mass to the system? (I know it takes a lot of imagination and if's but for the sake of discussion)
ANSWER:
But, birth is not the process of creating new mass. A new baby's mass
came from the mother who got it from the food she ate and the air she
breathed and the water she drank. And many processes in the universe result
in a net loss of mass—stars, for
example, are continually decreasing in mass as mass is converted into energy
(you know, E=mc2).
QUESTION:
My age is 20. I am wearing a wristwatch (which shows date and year also) and I am also carrying a mobile. Now assume that I travel at 99.99% speed of light (almost 3.8 * 108 m/s) for 100 years (100 years for the earth) and then I stop. My friends tell me that 100 years have passed. Now if I go through biological tests on the earth, will it show my age (a) 120 years or (b) 20 years and some days?
If my age would be 20 years and some days then I would be of this age in 2110, yet I was born in 1990. In this case if I die at the age of 80, it will mean that I die in 2170.
From given conditions is it right to say that a man born in 1990 died at the age of 80 in 2170.
Now from the stated condition my second question is that in my journey if my friend call me on my mobile then what will happen? Will I be able to talk to him? What about the signal of the satellite due to phone? Please answer me briefly.
ANSWER:
Why should I be brief? You haven't been. First, the speed of light is
3x108 m/s (not 3.8). At your high speed, your clock, compared to
an earth clock, runs slow. The elapsed time on your clock when the earth
clock is 100 years is 100√(1-.99992)=0.014
year=5.2 days. Indeed, you will die in 2170 earth time but your clock is
what matters to you—your clock will say
2070 when you die. (How can you undergo "biological tests on the earth"
when you are 100 light years away from the earth?) You cannot talk to your
friend on your mobile phone because he is dead; but the most important
reason is the mobile phone signal travels at the speed of light so there is
a long delay. For example, suppose he calls you after 50 years his time, a
few years before he dies. You will receive it about 50 years after you arrive at
your destination (which is 2060 your time but 2160 earth time) and, if you
answer, your reply will not arrive on earth until after you and he have both
been dead for many years (2160 your time, 2260 earth time). You make two
serious mistakes: you seem to think earth time is special and that mobile
phone messages are instantly transmitted.
QUESTION:
Imagine a metal link chain of .5m in length with each link weighing 10 grams.
Now rotate that chain about its centre point at 100 rpm.
So, the very last link at either end of the chain is rotating at 2.60 m/s
NOW,
That very last link rotating at 2.60 m/s breaks off.
Does it A) shoot off at a speed of 2.60 m/s and decelerate uniformly until it hits the floor.
or B) experience a small degree of acceleration additional to its 2.60 m/s due to the centrifugal force that was acting upon its mass prior to it breaking off.
I know the link was experienceing a centrifugal force (Fc=mv2/r), but I just cant work out if or how that affects the velocity of the link as it breaks free. Instinctively I think it would increase the initial velocity but I cant work out how. Any help would be greatly appreciated.
ANSWER:
First of all, the rotating link does not experience a centrifugal force,
it experiences a centripetal force. The instant that the link leaves the
chain, the chain is out of the picture entirely—the
link leaves the chain moving 2.6 m/s in exactly the direction it was moving
when it left. Thereafter it experiences two forces, gravity and air
resistance. The gravity causes a uniform acceleration vertically down; the
air resistance causes an acceleration which is opposite the direction of the
velocity vector (that is it slows the link down). Whether the net effect as
it falls to the floor is to speed up or slow down depends on the details of
air resistance (can be very complicated), but in most cases like this air
resistance may be neglected.
QUESTION: .jpg)
We have two clocks starting out in an the same inertial framework, and then accelerate one of them (Clock A) to some constant speed V, but the two clocks are also tethered by a rope. At some point, the accelerated Clock A will tug on the rope and begin accelerating the clock that is still at rest in the original framework (Clock B). Clock A will begin to decelerate and clock B will begin to accelerate until they are both traveling at the same speed V2. The question is, will they both show the same time (from the point of view of someone still at the initial framework)?
ANSWER:
I have been puzzzling over how to best explain this one! I believe that
the problem, as stated, is equivalent to clock A moving away at constant
speed for a while and then stopping. In both cases, clock A starts in the
same inertial frame as B, then jumps out of that frame and stays there for a
while, and then jumps back into B's frame. I recommend first reading my
earlier explanation of the twin
paradox to see what my paradigm is for the explanation illustrated by
the graph at the right. The graph represents clock A traveling at 80% the
speed of light to a point 8 light years from the earth; then clock A stops
moving. The graph shows clock A's ticks (once a year) with black crosses,
and clock B's ticks (once a year) with red crosses. Clock B measures 10
years for the trip [(8 light years)/(0.8 light years/year)]. But clock A
measures only 6 years because of length contraction (the distance is only
4.8 light years for clock A). Thereafter, the clocks run at the same rate
but clock A is 4 years behind clock B.
QUESTION:
In my physics textbook, it says that electricity the movement of electric charge. This movement is MOSTLY carried by electrons.
What other particles could possibly be used in electricity?
Are electrons the fundamental part of electricity?
ANSWER:
In nearly all household electrical circuits (light bulbs, toasters,
driers, motors, etc.) electrons flow through conductors to do the
work. However, in some materials, as you note, the charge carriers are
positive rather than negative. Here is how it works: the material has
"holes" in atoms, places where electrons are missing and so the hole has an
effective positive charge. When the voltage is applied across such a
material, it is the holes which move (hop from atom to atom) rather than the
electrons in a normal material. Such a material is called a p-type
semiconductor.
QUESTION:
In a previous answer, you said, "according to quantum mechanics, a change in one part of an entangled system immediately affects all other parts of the system." Is it possible for someone to force a change in one part of the system? And, if so, couldn't this be a form of communication (i.e., if I change the spin from up to down, it means I've done something), which would then violate light speed?
ANSWER:
If you make a measurement, that is equivalent to "forcing" a change; a
measurement "puts" the particle into the state you observe (let's call it
"up"). This instantly puts the other particle into the complementary
state (let's call it "down"). But, if somebody observes the other particle
and and finds it to be "down", he doesn't know whether this observation is
the result of your having "put" it in that state or his having put it there,
does he? Therefore, finding the second particle "down" conveys no
information to him regarding what you did.
QUESTION:
If a clock were moving at half the speed of light, how fast would it be going in m/s? Also, would the clock moving be showing half the time passed as the outside observer?
ANSWER:
The speed would be c/2=1.5x108 m/s where c is
the speed of light. The change in clock speed is not proportional to the
speed ratio
β=v/c
but rather to
√(1-β2). So, the
clock would show √(1-½2)=0.866 the time passed on a stationary
observer's clock.
QUESTION:
My doubt is if protons repel protons how is it possible for them to be in the nucleus?
if it is possible to separate a proton from a nucleus can we form new elements if done in large scale can we achieve creation of new elements?
ANSWER:
This is how we know that there is another force present besides the
electrostatic repulsion. It is called the nuclear force or strong
interaction. This force is very short ranged. That is, if the protons are
not very close to each other, this force will will be very small and the
repulsion will win out; but if they are very close, the nuclear force wins
out and a nucleus may be held together. Neutrons also feel this force which
is why neutrons are in nuclei.
QUESTION:
I have a problem in understanding Terminal Velocity.
When we are handling the questions about drag force in college (1st Sem.), we consider the density completely constant.
We have drag force in free falling.
When we leave the object from a certain height, there is only W=mg applying on the objects.
But, just as the object moves to the ground, it hits the molecules in its way, which causes in increasing of the drag force.
After Drag force's magnitude becomes equal to the weight, the total acceleration will be Zero and we will reach the constant velocity which is the Terminal velocity.
But after it reached the terminal velocity, it stills hit the molecules in the air, so the Drag force must become larger than the weight.
Why it doesn't happen?
ANSWER:
The drag force is proportional to the velocity (or some power of the
velocity). The reason the object speeds up at the beginning is that the
downward force (its weight) is larger than the upward force (drag). But as
it speeds up the drag gets bigger and so the acceleration (down) gets
smaller. Eventually the drag force increases to the point where it is equal
to the weight; now the forces are balanced and the object moves with
constant speed. The air molecules are are still colliding with the object
but their effect is no longer changing.
QUESTION:
Does a light source from a torch or carlight (a light source that isn't spherical) obey the inverse square law or if you were to calculate the intensity differently?
ANSWER:
No. The inverse square law is for a point source (or spherically
symmetric source). A beam of light is more like a plane wave which does not
lose intensity as it travels. Of course, real world cases like a car
headlight do eventually lose intensity due to imperfect optics and
absorption of the light by the air.
QUESTION:
If we are moving around in space at x speed and light is constant, then how do we know how fast light travels? If we shine light in the opposite direction we are traveling, won't it seem to travel faster (relative to us) than it truly is? What I mean to ask is, have physicists considered this variable for the speed of light
ANSWER:
Here is the basic rule of special relativity: the speed of light in
vacuum is the same to all observers. Therefore, if there is a beam of light,
you will measure its speed to be 3x108 m/s no matter what your
own speed is. You should read my earlier
discussion of this.
QUESTION:
does an 40 lb object that is 12 inch X 12 inch X 2 inch have a greater downward force or pressure when starting from a resting position balanced atop a soda can if it is standing on its end or lying flat?
does it have greater ability to crush the can in the two different positions?
what if it were resting 12 inches above the ground and were in a free fall.
ANSWER:
First, model the can as a cylinder; the diameter of the can is about 3".
However you place the object on the can, the force on the can will be 40 lb.
However, standing on its end, this 40 lb will distributed over a smaller
area (since the object will not cover the whole top when on end) so the
pressure (force divided by the area over which it is applied) is larger and therefore
more likely to crush the can. In reality, the top of the can is not flat but
has a raised lip and so the pressure in both cases will be greatly increased
(because of the greatly decreased area) but the on-end situation will still
have the larger pressure. When dropped on the can, the block is more likely
to crush the can. The reason is that, to stop the block, the can must exert
an upward force on the object which is larger than the weight; by Newton's
third law, the force the can exerts up on the object must be equal to the
force the object exerts down on the can, so it is bigger than the weight.
QUESTION:
A ray of light is moving towards a certain space station from 1
light year away. A rocket departs from the space station at exactly the same
time, accelerating at a certain rate, directly towards the ray of light.
(the exact rate of acceleration isn't necessary for the question).
Would I be right to assume that two observers, one on the rocket, and one on
the space station, would each experience exactly one year passing before
being reached by the ray of light, Even though the rocket may be a great
distance away from the station now?
As I understand it, light can never travel faster than c. So if the rocket
is the body of reference, the light starts out 1 light year away, and
travels towards it at c for the duration of 1 year. While if the space
station is the body of reference, the same is true.
ANSWER:
No, less than one year will have elapsed for the rocket. Not only does
it meet the light somewhere between the two points, the distance that it
sees that it has to travel is contracted by length contraction (that is, the
rocket sees the distance from the light source to the space station to be
less than one light year.) If you just assume that the acceleration happens
in a very short time so that he travels with constant speed, then you could
calculate the time he travels before encountering the light. Here is an
example: if the rocket has a speed of v=0.8c where c is
the speed of light, the distance between the source and the station
(measured by the rocket) is
√(1-0.82) ly=0.6 ly. It is then a straightforward kinetmatics problem to
show that the light and rocket will coincide at time 0.625 y (using the
rocket's clock), so the place they coincide is 0.6x0.625=0.375 ly from the
light source. The time for the light and rocket to coincide as measured by
the station's clock would be 0.556 y, so the distance from the source would
be 0.566 ly.
QUESTION:
If nothing travels faster than the speed of light then how come 2 electrons can become entangled in such a way as to effect each other regardless of distance. ie light years apart. It seems to me that this would mean that they are breaking the speed limit to achieve this.
ANSWER:
No material object may travel at or faster than the speed of light.
Information may not be transmitted faster than the speed of light. Since
neither of these is violated, entanglement does not violate the speed of
light limits. It may seem like information is being sent from one electron
to the other, but you cannot use these two electrons to send information to
somebody. I always find it easiest to think about the two electrons as a
single system rather than as a pair of electrons talking to each other;
according to quantum mechanics, a change in one part of an entangled system
immediately affects all other parts of the system.
QUESTION:
This might take a little time to explain. I know that the speed of light is such that when we look at stars, distant galaxies and other stellar phenomena, we are looking at them as they were (since it took light time to reach us). Here lies my problem. If physicists and cosmologists state that the universe is expanding due to the red-shifted light from galaxies, and the further away a glaxay is, the faster it is traveling, then that red-shifted light being observed took a long time to reach us. So, we are seeing a red-shift from, say, 1000 years ago. Could it be that now galaxies are moving towards us, just that the blue-shifted light has not reached us yet? What am I missing? Every text I read, every show I watch, everyone is certain the universe is expanding.
ANSWER:
First, your time scale is way off—we're
talking billions of years, not thousands. You are right, it is certainly
possible that distant objects could now be moving toward us and we won't
find out for billions of years. But, we are able to see a huge range of
distances into the cosmos and all systematics, near and far, indicate that
everything is moving away. In recent years evidence has been found that the
distant objects are actually speeding up (the source of which is called
"dark energy"), providing even more evidence that we do not expect anything
to be turning around.
QUESTION:
Is a low or high current solar charger/battery system (same voltage) more efficient to charge small electrical devices (iphone etc) please?
ANSWER:
Well, since power is current times voltage, higher current is higher
power—charges faster.
QUESTION:
if electricity is made up of millions / billions of electrons and has a
tiny amount of mass. Is it affected by G force when it goes from zero to
the speed of light and back to zero, eg when its switch a light on and
off?
ANSWER:
Indeed, electrons do not go at the speed of light in a wire. They go
very slowly, maybe on the order of 1 mm/hour! In any case, the force of
gravity on an electron is negligible under almost all possible conditions.
QUESTION:
I am not wishing to make a weapon its purely scientific curiosity. If you had a laser beam and placed it behind a magnifying lens of some sort such as a telescope, you could magnify the lasers strength. Now my question is if you were to put another magnifying lens in place to magnify the current beam would it magnify it even stronger?
What I am asking is if your laser is 1kW and by placing the magnifying lens or telescope makes your laser go to 2kW. Adding another lens or telescope would make it 4kW?
ANSWER:
You are confusing power with intensity. You can use a lens to increase
the intensity (energy/second/square meter) but not the power
(energy/second). Hence, you cannot take 1 kW and increase it, you can only
decrease the area over which it hits.
QUESTION:
If matter and anti-matter annihilate each other when they come into contact, how is Positron Emission Tomography possible ?
ANSWER:
Because PET detects the products of the annihilation (two 512 keV gamma
rays).
QUESTION:
How do you have Kinetic Energy at the top of a projectile? I thought the
velocity in the y direction was 0, and even if we consider the x
direction, wouldn't the kinetic energy at the top of the projectile
equal the kinetic energy when the projectile initially set into motion?
ANSWER:
Anything which is moving has kinetic energy. Part of the the kinetic
energy has been converted to potential energy, but not all of it. The energy
conservation is expressed as
½mvx2+½mvy2=mgh+½mvx2 at the top (y=h).
QUESTION:
What l want to know is can you see something before the sound without it
being faster than the speed of sound? For example, all my life l've
noticed that l will hear the jet plane over here and see the jet plane
there. l do hear and see it at the same moment in time but the sound and
the sight are not in the same place. l hope what l just wrote makes
sense, haha. The current argument raised is that this is not possible
unless the thing is traveling faster than the speed of sound. However,
the speed of sound is like 1000 miles an hour or something, right??? l'm
not sure on that but l'm pretty sure it's faster than most commercial
jets fly. So l have a sneaking suspicion that what's going on here is
some kind of matter of semantics and/or we are both right and both
wrong. Or we are talking about different things, l don't know.
ANSWER:
The answer is very simple: the speed of sound (about 330 m/s) is
enormously smaller than the speed of light (300,000,000 m/s).
QUESTION:
As the stars die, will the sun die too?
ANSWER:
All stars will eventually die because they will run out of energy. The
sun may last a few billion more years but life on earth will be
unsustainable in about one billion years because the sun will become too
hot.
QUESTION: 
My question is: why does light bend when it slows down? I'm currently a physics student at UC Santa Barbara (2nd year) and so I know that light has a finite speed, and it slows down when it enters another medium, and if it enters another medium at an angle other than perpendicular it bends (refracts). I know about angle of incidence and all that, I just don't understand why light has to bend because it slows down? As I understand it light can be thought as a quanta of energy, an infinitesimal wave packet (maybe that's where I'm wrong?) So why does it need to bend just because it is slowing down in an angled medium? I've often heard the analogy of a car: if it hits glass angled downward from left to right then the upper left tire hits the glass first and slows down while the right wheel remains faster and therefore bends it "upwards". But light packets don't have a discernible "thickness" where one part hits before another (I don't think!) so that analogy breaks down for me! Sorry for rambling, I'm just confused.
ANSWER:
Refraction is geometric optics and thinking of photons is definitely not
the way to best understand it. You should think in terms of waves—wave
fronts and rays. I found a nice description (based on Huygen's principle)
on the web.
Refer to the picture on the right.
- Wavefront 1 reaches A.
- Wavefront from A starts to spread out.
- When incident wavefront reaches B, secondary wavelet from A has travelled a shorter distance to reach D.
- It gives a new wavefront 2.
- As a result the wave path bends towards the normal.
QUESTION:
What is the word for the amount of upward velocity necessary for an object to continue moving upward against gravity after it leaves your hand. I believe there is a word that distinguishes between simply applying the force necessary to move an object against gravity vs. accelerating that object so that it will continue moving against gravity on its own.
ANSWER:
I am not sure what you are asking because you have many misconceptions.
You may be asking the term which describes the minimum velocity something
must have to completely escape from the earth. This is called the escape
velocity. Escape velocity from the surface of the earth is about 25,000
mi/hr. For comparison, the required speed to put a satellite in a low orbit
(like the shuttle) is about 18,000 mi/hr.
QUESTION:
What is the proper term for the opposite of antimatter? "Regular matter"? "Normal matter"? Just "matter"? Is anitmatter a form of matter, or are "regular matter" and antimatter both forms of a larger concept? And, if they are, what is that concept called? Is it also called "matter"?
ANSWER:
This is just semantics. As far as I know, there is no formal definition of the word matter but it very well could include antimatter.
Here is what Wikipedia has to say: "…in practice there is no single correct scientific meaning; each field uses the term in different and often incompatible ways. A common way of defining matter is as anything that has mass and occupies volume."
QUESTION:
What part of a U-235 or Pu-239 atom is converted into energy during nuclear fission? Proton? Neutron? or something else?
ANSWER:
The energy comes from mass, you know, E=mc2. When a
heavy nucleus breaks into two pieces, the masses of the pieces are smaller
than the mass of the original nucleus; that is mainly where the energy comes
from. After the fission occurs, numerous neutrons are ejected from the
smaller nuclei and these have kinetic energy which comes, again, from mass.
The nuclei turn out to be unstable (they have too many neutrons) and so they
beta decay, converting neutrons into electrons and protons in the nuclei;
again, the energy released comes from the mass decreases which occur. In the
end, if you measure the mass of everything that is left, it is less than
everything you started with and that missing mass is where all the energy
came from. You might like to learn a bit more at an
earlier answer.
QUESTION:
Do spirits have any mass ?
ANSWER:
The density of alcohol is 0.79 gm/mL.
QUESTION:
I have another question for you sir. This is a simpler one, perhaps laughably simple to you, but I haven't taken physics in school yet. (It's next on the list). Anyway, why is the distance traveled by an object dropped from rest equal to half of the 9.8 m/s/s it's traveling at in the first second? Also, why does it's distance then increase four fold to match the velocity in the second second, and then why is the distance traveled by the object much larger than its velocity after the second second?
ANSWER:
This is very basic kinematics. 9.8 m/s/s is not the rate at which it is
traveling, it is the rate at which it is changing its speed, its
acceleration. At the end of one second after being dropped the speed is 9.8
m/s but, if you think about it, it started from rest and so its average
speed over that first second must have been less than 9.8 m/s. It turns out
(I will leave it to you to learn kinematics when your time for physics
arrives or sooner if you want to dig it out for yourself) that the average
speed is 4.9 m/s over that first second. In general, x=½gt2
where x is distance fallen from rest, g=9.8 m/s2, and t
is the time fallen from rest. So you can see why the distance increases
quadratically with time.
QUESTION:
Are colors associated with sound? Specifically, do visible colors correlate with the musical scale... red=DO; orange=RA; yellow=MI; green=FA; blue=SO; indigo=LA; violet=TI
ANSWER:
Sound and light are two completely different kinds of physical phenomena
and there is no intrinsic relation between any colors and pitches. You may
define a corespondence but it has no meaning in physics. Your correlated
pairs are at least both in the order of increasing frequencies, red and do
are low frequencies and violet and ti are high frequencies.
QUESTION:
I'm wondering about buoyant force. It seems to me that a particular liquid would exert a particular buoyant force, making the buoyant force a constant much the same way gravity is a constant force. An object's density would then determine the effect the buoyant force would have on the object. If an object is less dense than the liquid it will float - the buoyant force is having a great effect on the object. On the other hand, if the object is more dense than the liquid the buoyant force will have less of an effect. Am I thinking about this correctly? I would really appreciate an answer as soon as possible because I'm teaching a teacher workshop and I don't want to give teachers misconceptions.
ANSWER:
You are talking about a classic physics problem, perhaps the oldest
known physics. The basic principle was discovered by Archimedes more than
2000 years ago. Simply stated, Archimedes' principle is that the buoyant
force is equal to the weight of the fluid which the object displaces. So the
buoyant force certainly depends on the density of the fluid. So your
conclusions follow: an object whose weight is greater than the weight of the
fluid it displaces will sink and the converse situation implies it will rise
to the surface where it will settle to where it displaces a volume of fluid
equal to its weight.
QUESTION:
I am interested in building a device that might collect electrical energy from using a solenoid generator that would be push the magnet by being connected to the inside of the tire. The solenoid generator would be in-line on the rim where when the tire comes in contact with the road surface it would come toward the rim, then when the tire leaves thr road surface it would be returned with force to the original position. DOES THIS SOUND LIKE IT MIGHT COLLECT SOME USEFUL ENERGY IN=ORDER TO HELP RECHARGE A BATTERY IN A ELECTRIC VEHICLE ??
ANSWER:
It sounds to me like you want to replace the shock absorbers with
electromagnetic dampers. What a shock absorber does is damp out the vertical
motion of the wheels by converting the energy to heat. What you want to do
is convert that energy instead into electrical energy. Although the idea is
sound, I believe that the amount of energy you would harvest would be
smaller than the energy you would lose by having to carry those heavy
permanent magnets along. Already hybrid cars harvest the kinetic energy of
the car by electromagnetic braking. Think about it: conventional brakes get
very hot in use indicating that there is significant energy there to harvest
whereas I suspect shock absorbers really do not heat up that much.
QUESTION:
If I pointed an infrared-based remote control at a some mirror that are aligned so the beam can hit it several times before being recieved by a television or similar device, would the device be able to recognize the command sent to it, or would it think that nothing useful happened? Under what situations might these results be obtained?
ANSWER:
I have certainly bounced the signal from a remote to the TV. How many
times you might bounce it around would depend on the nature of the
reflecting surfaces and the power of the remote.
QUESTION:
We know that the gratest persentage of an atom is vacuum. We also know that soundwaves do not travel through the vacuum. However sound travels through matter which, though, is mainly vacuum. How can this happen?
ANSWER:
Sound waves have wavelengths of a few centimeters to a few meters. Atoms
are of a size roughly 10-10 meters and their structure is totally
invisible to sound. Anyhow, the atom is not mostly a vacuum, but is filled
up with electrons. The atom should not be thought of as tiny electrons
orbiting the nucleus but as a "cloud" of electric charge surrounding the
nucleus. You might think about the space between atoms in a gas as being
"vacuum" but since the distance betweens atoms in a gas is on the order of
10-7 m, this too is invisible to sound waves.
QUESTION:
I am reading a book "Power Hungry" by Robert Bryce. He takes a position that wind and solar energy are basically scams because they are unreliable. Society demands that power is availbale immediately, the moment it is needed. The nature of wind and solar is that it is unreliable - we cannot predict with 100 per cent certainty how hard the wind will blow or whether the sun will shine. More power may be generated from these sources when it is not needed and less energy may be generated when it is needed. Therefore, natural gas and coal-fired generators are still needed for backup and these generators must be constantly running because it takes time to bring them on line. Wind and solar are a waste because the gas and goal generators must run anyway. He gives other reasons but this is the main reason.
My question is whether it is possible to store the energy generated from wind and solar. If we could build up reserves of this energy, it seems we could use it the same way as coal and gas is used - just switch it on when it is needed. Does this concept violate the laws of thermodynamics?
ANSWER:
The storage device is called a battery. This is already how home installations work, using wind or solar to charge a battery. And when the batteries are fully charged, send the excess onto the grid. Another storage possibility (less efficient, I suppose) is that energy may be used to pump water up to a reservoir and then let it fall back to drive turbines when power is needed. Yet another storage device is to use the heat from solar to melt salt; the molten salt is stored in insulated containers and used to later heat water to run steam turbines. To say that solar and wind are "scams" is idiotic. It is true that for a long time we will still need conventional power plants, not because of storage issues but because the amount of demand cannot be met overnight by alternative sources.
QUESTION:
I was wondering, what are estimated or known deviations of the masses and radii for the 3 basic particles (protons, neutrons and electrons ) making up the atoms ? Can we expect atoms from one edge of the universe to match atoms plucked from the opposite reaches ? Is it possible that some atoms would be scaled up or down by multiple factors with respect to the lot we are familiar with ?
ANSWER:
Masses are extremely accurately known. Regarding the sizes, they are not
simply well-defined particles like a marble or bowling ball, they have fuzzy
edges. But you can define a size (for example, where charge density drops to
½
the maximum value). The size of an electron is unknown and maybe
unmeasurable. The sizes of protons and neutrons are on the order of 10-15 m.
There is no evidence whatever that atoms at the extreme edges of the known
universe are different. Some physicists speculate that the fundamental
constants of physics may change over time (hence distant regions would have
different physics) but there is no good evidence for this being the case.
QUESTION:
Can I move the Earth myself by jumping? Can a single atom move the Earth?
ANSWER:
When you jump, the earth exerts a force on you and you exert an equal
and opposite force on the earth; that is Newton's third law. Hence the earth
accelerates away from you and you accelerate away from the earth. But, your
mass is small and the earths is huge, so your acceleration is modest and
observable and the earth's is tiny and so small as to be unobservable. But,
after you leave the ground you and the earth exert attractive forces on each
other (gravity) and you fall back together so the net effect has been not to
"move" the earth. Of course, a single atom would really have a negligible
effect.
QUESTION:
Electromagnetic physics asserts that when a charge is accelerated, in the medium of a copper wire (antenna), a disturbance in the electric field results (a "kink" in the E field lines develops), this "disturbance" is associated with propagating E and B fields. Does the summation of all photon energy comprise the energy of the E and B fields, and, if not, to what degree does photon energy comprise the energy found in either the E or B fields?
ANSWER:
There are electric and magnetic fields which are associated with the
charge but are not radiation fields. Therefore, there is less energy in
photons than in all the electric and magnetic fields.
QUESTION:
I have read your ground rules, particularly the rule that bars asking about traveling faster than light. If the question I'm about to ask is in violation of this rule, please tell me.
My question is this: If you could travel "at" the speed of light, and you shined a flashlight in front of you, what would happen to the beam? Would you be unable to see it, or would it behave normally?
ANSWER:
You have not violated the groundrules because I neglected to specify
at the speed of light; I have fixed that now! As you can see from a
previous answer, it is not possible for
anything with mass to go as fast as the speed of light. However, if you
happened to have a speed of 99.9999999999% the speed of light, you would
observe the flashlight beam to be moving away from you at the speed of
light. Again, see an earlier answer.
QUESTION:
I was told in my electromagnetics class by my professor that a RF wave is a "photon." A photon appears to be defined as a quantity of measureable energy.
I then read, that a microwave oven permits "photons" of light to pass through a metal mesh but not microwaves." Can you please distinguish between a light photon and a microwave (define)? How can a mesh be designed to block microwaves?
ANSWER:
Electromagnetic waves, it turns out, are both waves and streams of
particles called photons. The photon is the smallest amount of energy
possible for a wave of a given frequency. For most practical applications
there is no need to talk about photons at all, just considering the wave
properties is sufficient. There is no need to think about microwave photons
when trying to understand why the waves do not penetrate the mesh enclosing
the oven. Light waves have wavelengths typically hundreds of nanometers
(very short). The wavelength of the microwaves is several inches. The holes
are much bigger than the light wavelengths and much smaller than the
microwaves.
QUESTION:
I am perplexed at something a subsititute teacher in physics class told me. He said, rockets rely on Newton's Third Law (action/reaction) to leave Earth's gravitional force (they have to reach a speed called 'cosmic speed' I think). But I remember him saying rocket engines don't work in space. Is this true? Does that mean we rely on Inertia for space travel? Then, how would we avoid the gravity of other objects to stay on path? I remember you answering a question with 'influential gravity' to 'steer' through space; please explain this concept a little more.
Back on rocket engines, how do we return from the moon then?
ANSWER:
It is scary how ignorant teachers can sometimes be. It is absolute
nonsense to say rockets do not work in space.
QUESTION:
Why do neutrons decay with a half-life of 10 minutes when free, but do not decay when they are attached to other protons in nuclei or when they occur in bulk in neutron stars? Does the presence of other particles have a stabilizing effect on the neutrons?
ANSWER:
Yes, the presence of other particles in nuclear matter does have a
"stabilizing effect" on neutrons. But it is most easily understood in terms
of energetics. A free neutron has a certain mass and has the "option" to
decay into a proton, a neutrino, and an electron; the mass of a neutron is
larger than the summed masses of its decay produc
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